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I have two sets of codes that work. Needed help combining them into one.

This code gets me the difference between two dates. works perfectly:

function test(){
var date1 = new Date(txtbox_1.value);    
var date2 = new Date(txtbox_2.value);

var diff = (date2 - date1)/1000;
var diff = Math.abs(Math.floor(diff));

var days = Math.floor(diff/(24*60*60));
var leftSec = diff - days * 24*60*60;

var hrs = Math.floor(leftSec/(60*60));
var leftSec = leftSec - hrs * 60*60;

var min = Math.floor(leftSec/(60));
var leftSec = leftSec - min * 60;

txtbox_3.value = days + "." + hrs; }

source for the above code

The code below by @cyberfly appears to have the answer of excluding sat and sun which is what i needed. source. However, its in jquery and the above code is in JS. Therefore, needed help combining as i lacked that knowledge :(

<script type="text/javascript">

$("#startdate, #enddate").change(function() {       

var d1 = $("#startdate").val();
var d2 = $("#enddate").val();

        var minutes = 1000*60;
        var hours = minutes*60;
        var day = hours*24;

        var startdate1 = getDateFromFormat(d1, "d-m-y");
        var enddate1 = getDateFromFormat(d2, "d-m-y");

        var days = calcBusinessDays(new Date(startdate1),new Date(enddate1));             

if(days>0)
{ $("#noofdays").val(days);}
else
{ $("#noofdays").val(0);}


});

</script>

EDIT Made an attempt at combining the codes. here is my sample. getting object expected error.

function test(){
var date1 = new Date(startdate.value);    
var date2 = new Date(enddate.value);
var diff = (date2 - date1)/1000;
var diff = Math.abs(Math.floor(diff)); 
var days = Math.floor(diff/(24*60*60));
var leftSec = diff - days * 24*60*60;
var hrs = Math.floor(leftSec/(60*60));
var leftSec = leftSec - hrs * 60*60;
var min = Math.floor(leftSec/(60));
var leftSec = leftSec - min * 60;

var startdate1 = getDateFromFormat(startdate, "dd/mm/yyyy hh:mm");
var enddate1 = getDateFromFormat(enddate, "dd/mm/yyyy hh:mm");
days = calcBusinessDays(new Date(startdate1),new Date(enddate1));           
noofdays.value = days + "." + hrs; }

start: <input type="text" id="startdate" name="startdate" value="02/03/2015 00:00">
end: <input type="text" id="enddate" name="enddate" value="02/03/2015 00:01">
<input type="text" id="noofdays" name="noofdays" value="">

JavaScript support for excluding weekends., JavaScript support for excluding weekends. You'll just need to change add a class called "sdate" to you start date field, a class It does not generate the calculation of the total requested vacation days without weekend. If you’d like to calculate the difference between two dates while excluding weekends and holidays, use the NETWORKDAYS function instead. This also looks for 3 arguments: the start date, the end date, and optional holidays. =NETWORKDAYS(start_date, end_date, [holidays])

Here's a simple function to calculate the number of business days between two date objects. As designed, it does not count the start day, but does count the end day so if you give it a date on a Tuesday of one week and a Tuesday of the next week, it will return 5 business days. This does not account for holidays, but does work properly across daylight savings changes.

function calcBusinessDays(start, end) {
    // This makes no effort to account for holidays
    // Counts end day, does not count start day

    // make copies we can normalize without changing passed in objects    
    var start = new Date(start);
    var end = new Date(end);

    // initial total
    var totalBusinessDays = 0;

    // normalize both start and end to beginning of the day
    start.setHours(0,0,0,0);
    end.setHours(0,0,0,0);

    var current = new Date(start);
    current.setDate(current.getDate() + 1);
    var day;
    // loop through each day, checking
    while (current <= end) {
        day = current.getDay();
        if (day >= 1 && day <= 5) {
            ++totalBusinessDays;
        }
        current.setDate(current.getDate() + 1);
    }
    return totalBusinessDays;
}

And, the jQuery + jQueryUI code for a demo:

// make both input fields into date pickers
$("#startDate, #endDate").datepicker();

// process click to calculate the difference between the two days
$("#calc").click(function(e) {
    var diff = calcBusinessDays(
        $("#startDate").datepicker("getDate"), 
        $("#endDate").datepicker("getDate")
    );
    $("#diff").html(diff);
});

And, here's a simple demo built with the date picker in jQueryUI: http://jsfiddle.net/jfriend00/z1txs10d/

Calculate Days,Exclude Weekends and Holidays Using Javascript , <title>Date</title>. </head>. <script>. var startDate = "01/25/2017", endDate = "01/​27/2017";. var currentYear = (new Date).getFullYear();. var disabledDays  Rama this will just exclude the weekends. But i want something else. suppose there is start date i.e 31st march which is a friday and today is 5th of april so i want result to be 3 as there is 3 working days from friday to wednesday.

@RobG has given an excellent algorithm to separate business days from weekends. I think the only problem is if the starting days is a weekend, Saturday or Sunday, then the no of working days/weekends will one less.

Corrected code is below.

function dateDifference(start, end) {

  // Copy date objects so don't modify originals

  var s = new Date(start);
  var e = new Date(end);

    var addOneMoreDay = 0;
    if( s.getDay() == 0 || s.getDay() == 6 ) {
    addOneMoreDay = 1;
  }

  // Set time to midday to avoid dalight saving and browser quirks
  s.setHours(12,0,0,0);
  e.setHours(12,0,0,0);

  // Get the difference in whole days
  var totalDays = Math.round((e - s) / 8.64e7);

  // Get the difference in whole weeks
  var wholeWeeks = totalDays / 7 | 0;

  // Estimate business days as number of whole weeks * 5
  var days = wholeWeeks * 5;

  // If not even number of weeks, calc remaining weekend days
  if (totalDays % 7) {
    s.setDate(s.getDate() + wholeWeeks * 7);

    while (s < e) {
      s.setDate(s.getDate() + 1);

      // If day isn't a Sunday or Saturday, add to business days
      if (s.getDay() != 0 && s.getDay() != 6) {
        ++days;
      }
      //s.setDate(s.getDate() + 1);
    }
  }
  var weekEndDays = totalDays - days + addOneMoreDay;
  return weekEndDays;
}

JSFiddle link is https://jsfiddle.net/ykxj4k09/2/

Calculate number of working days - JavaScript, please help me to write code in JS which will calculate no. of working days when start and end date are provided, excluding the weekends. Count Workdays excluding Holidays and Weekends (Saturday & Sunday) The function NETWORKDAYS is used while counting the total number of workdays in Excel. While counting the workdays using this function Saturdays and Sundays are considered as weekends by default. The syntax of this function is, =NETWORKDAYS (start_date, end_date, [holidays]).

First Get the Number of Days in a month

     totalDays(month, year) {
        return new Date(year, month, 0).getDate();
     }

Then Get No Of Working Days In A Month By removing Saturday and Sunday

  totalWorkdays() {
     var d = new Date(); // to know present date
     var m = d.getMonth() + 1; // to know present month
     var y = d.getFullYear(); // to knoow present year
     var td = this.totalDays(m, y);// to get no of days in a month
     for (var i = 1; i <= td; i++) {  
        var s = new Date(y, m - 1, i);
        if (s.getDay() != 0 && s.getDay() != 6) {
           this.workDays.push(s.getDate());// working days
        }else {
           this.totalWeekDays.push(s.getDate());//week days
         }
      }
      this.totalWorkingDays = this.workDays.length;
 }

excluding weekends from a date script, format('D jS, M'));. However i need the code to exclude weekends, as it is not possible to deliver on a weekend, how would i go about changing  Tip: In the formula, A2 is the start date, B2 is the days you want to add. Now the end date which add 45 business days excluding weekends has been shown. Note: If the calculated result is a 5-digit number, you can format it to date with clicking Home > Number Format > Short Date. See screenshot:

Working with dates (and weekends!) in Javascript - JavaScript, Is it possible to allow for weekends in my calculations!? <script type="text/​javascript"> var d1=new Date(2009,0,20); var d2=new Date(2009,1,5); for(var i=0​; d1<d2; ) { if( d1. return business days return weeks*5+tem; }. Include end date in calculation (1 day is added) Days in Results: Exclude Include only Weekends and public holidays Weekends Public holidays (not in weekends) All days No days Custom Holidays for United States – Washington.

Add days to date while ignoring weekends and holidays, number of business days to a given date and it works beautifully. deliveryWeeks = Math.floor(days / 5); //two days per weekend per week  The problem is I dont know how to calculate a due date that exclude weekends. Basically I need a formula or javascript that can calculate due date with business days only. I have current date, I have number of days for each task, but I dont have a way to exclude weekends for a correct due date.

Calculate the diffrence between two dates, excluding weekends and , I'm using Adobe Pro XI. I did some digging and found a script for calculating the difference between two dates to get the a total count of days. Wha. The Date Calculator adds or subtracts days, weeks, months and years from a given date.

Comments
  • You're missing the calcBusinessDays() function in your post which is the relevant portion of the code.
  • FYI, jQuery is JavaScript. It's just a library of already written functions that makes it easier for you to do common things in JavaScript. To use jQuery, just include it as an import.
  • In the second function, you are missing the important bits: getDateFromFormat and calcBusinessDays, which are the bits actually doing the calculations. jQuery is just being used to get and set some values in the page and can be replaced with about the same amount of plain JS. The "…works perfectly…" part is questionable since you are parsing strings without validating the input and using the built–in Date.parse (which is used when passing strings to the Date constructor). I suspect decent testing will reveal errors.
  • Please do not use the jquery-validate tag when the question has nothing to do with the jQuery Validate plugin.
  • @jfriend00 Hi everyone. thank you for taking time and looking at my post. I tried to combine the two codes but get an object expected error. I think its something trivial but i was unable to debug it. Posted my code sample above. Kindly help.
  • Thank you SO MUCH for the detailed explanation Rob. I cant tell you how much i appreciate your time and effort. your solution works well!! :)
  • @RobG this returns the number of days, what if we want to display all the resulted dates too? Could you please amend a bit. Thank you
  • @Mogambo—what are "resulted dates"? If you mean the weekend dates that are excluded, that is a different question so no, I won't amend the answer.
  • @RobG see this please :) stackoverflow.com/questions/47449790/…
  • Re: "…but does work properly across daylight savings changes". There's a bug in Safari where it applies daylight saving 4 hours early on the changeover date, so midnight on the last day becomes 23:00 (and vice versa at the start). May not affect your algorithm though. I set the time to noon and round so as to avoid it for whole days at least.
  • @jfriend00 Thank you so much mate, i tried your solution as well and it works awesome!! Again, appreciate your time and help on this one.
  • @jfriend00 Can you look at this please? stackoverflow.com/questions/47435105/…