Binary addition of 2 values represented as strings

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I have two strings:

string a = "00001"; /* which is decimal 1 I've converted with next string:
string a = Convert.ToString(2, 2).PadLeft(5, '0'); */
string b = "00010";

I want to perform binary addition between the two so the answer will be 00011 ( 3).

System.Convert should be able to do the work for you

int number_one = Convert.ToInt32(a, 2);
int number_two = Convert.ToInt32(b, 2);

return Convert.ToString(number_one + number_two, 2);

(you may have to tune the strings a bit)

Add two bit strings, In every iteration, we need to sum 3 bits: 2 bits of 2 given strings and carry. The sum bit will be 1 if Using StringBuilder as Java only uses call by value. static int​  Count number of binary strings of length N having only 0's and 1's; Count number of binary strings without consecutive 1’s : Set 2; Number of sub-strings in a given binary string divisible by 2; Count binary strings with twice zeros in first half; Number of binary strings such that there is no substring of length ≥ 3

You do it just as you would do it on paper. Start from right and move left. if A[i] + B[i] + carry >= 2, carry remains 1 and you move on. Otherwise, write A[i] + B[i] + carry and set carry to 0.

a = "00001"; b = "00010";

carry = 0; a[4] + b[4] + carry = 1, write 1, set carry = 0: 00001

a[3] + b[3] + carry = 1, write 1, set carry = 0: 00011

And so on.

Binary addition of 2 values represented as strings, System.Convert should be able to do the work for you int number_one = Convert.​ToInt32(a, 2); int number_two = Convert.ToInt32(b, 2); return  Between lines 8-11 some variables are declared: a scanner to read the binary numbers entered, an array list to store the binary numbers entered, a string to hold a number once is entered, and a int to keep track of how many numbers have been entered, since I extended this solution to add 0,1,2,3,,n numbers).

private static bool[] BinaryAdd(bool[] originalbits, long valuetoadd)
    {
        bool[] returnbits = new bool[originalbits.Length];

        for (long i = 0; i <= valuetoadd - 1; i++)
        {
            bool r = false; //r=0
            for (long j=originalbits.Length-1;j<=originalbits.Length;j--)
            {
                bool breakcond = false;
                bool o1 = originalbits[j];
                if (r == false)
                {
                    if (o1 == false) { o1 = true; breakcond = true; }//break
                    else if (o1 == true) { o1 = false; r = true; }
                }
                else
                {
                    if (o1 == false) { o1 = true; breakcond = true; }//break
                    else if (o1 == true) { o1 = false; r = true; }
                }

                originalbits[j] = o1;
                if (breakcond == true)
                {
                    break;
                }
            }

        }
        returnbits = originalbits;

        return returnbits;
    }

Add Binary, Given two binary strings, return their sum (also a binary string). The input strings Similar Questions. Add Two Numbers Add to Array-Form of Integer. Easy  Generate all binary strings from given pattern; Count of sub-strings with equal consecutive 0's and 1's; XOR two binary strings of unequal lengths; Maximize the number of palindromic Strings; Number of sub-strings in a given binary string divisible by 2; Number of binary strings such that there is no substring of length ≥ 3; Count number of binary strings without consecutive 1’s : Set 2

I would recommend parsing the data to ints and then adding them, then outputing the result as binary.

Add two binary strings, Difficulty: Easy (https://www.geeksforgeeks.org/easy/) Find Complete Code at GeeksforGeeks Duration: 1:54 Posted: Mar 22, 2018 Multiplying by a power of two, e.g. 2 2 = 100 2, simply results in the binary number being shifted n digits to the left and n zeros being added as the LSBs. Consequently long multiplication is simply performed by shifting (i.e. multiplying by powers of two) and adding.

Very easy -- write a lookup table for 'addition' of binary characters, don't forget to carry if necessary, and send me 50% of the credit you get for the work.

Binary Addition, Binary addition is much like decimal addition, but easier, as shown in Figure 1.8. Likewise, in binary, if the sum of two numbers is greater than 1, we carry the 2's In this framework, the digits of the bit strings are thought of as the coefficients  For adding two binary numbers, a and b. You can use the following equations to do so. sum = a xor b. carry = ab. This is the equation for a Half Adder. Now to implement this, you may need to understand how a Full Adder works. sum = a xor b xor c. carry = ab+bc+ca. Since you store your binary numbers in int array, you might want to understand bitwise operation. You can use ^ for XOR,| operator for OR, & operator for AND.

2 Ways to Add Binary Numbers in Java, In the last article, I have shown you how to subtract binary numbers in Java and parseInt(number, 2), where the number is a String denoting a binary number. Given two numbers as strings. The numbers may be very large (may not fit in long long int), the task is to find product of these two numbers. The idea is based on school mathematics. We start from last digit of second number multiply it with first number. Then we multiply second digit of second number with first number, and so on.

Part B, If we were adding two binary numbers by hand, say 1001 (that's 9 in decimal, 2 such ``binary strings" as input and then outputs a string representing their total. In binary, 8 is represented as 1000. Reading from right to left, the first 0 represents 2 0, the second 2 1, the third 2 2, and the fourth 2 3; just like the decimal system, except with a base of 2 rather than 10. Since 2 3 = 8, a 1 is entered in its position yielding 1000.

Python Program to Add two binary numbers, Program for adding two binary numbers. In the following program, we are using two built-in functions int() and bin(). The int() function converts the given string  Divide large number represented as string Given a large number (represented as string) which has to divided by another number (represented as int data type). The large number can be very large which does not even fit in long long in C++.

Comments
  • Homework it might be, but still quite an interesting one - it piqued my curiosity enough that I've got a Console app open and fiddling around with it right now! ;)
  • not really homework >.< project :D
  • Actually, looking at your comments on the accepted answer I think you might be looking in the wrong direction. You're not really looking at addition I think, but at a bitwise AND.
  • @Erik i was looking in the wrong direction true but thanks to this answer i now made a new function that takes 2 integers and returns a string equivalent with the proceeding zero's , which is exactly what i needed.
  • string a = "00001"; string b = "00011"; int num1 = Convert.ToInt32(a, 2); int num2 = Convert.ToInt32(b, 2); string ans = Convert.ToString(num1 + num2, 2); MessageBox.Show(ans); "thanks alot :) u have saved my project !!!!!!!!!!!!!!!!"
  • i needed to caluclate attendance using this logic :) , as 00001 wld represent absent for 1st hour ( we haf hourly wise attendance) so if a student is absent for the next hr in the same day 00001 - absent first hr 00010 - absent second hr ------ 00011 - absent for 1st and second hr :D it works !! thank u
  • I have to say, I didn't know that particular override of Convert.ToInt32 exists!
  • You should add some explanation to your example so novices can understand what it does.