How to include jar files with java file and compile in command prompt

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I have 3 jar files and a .java file that depends on these jar files. How do I compile the .java file with these jar files using a command prompt?

You can include your jar files in the "javac" command using the "-cp" option.

javac -cp ".:/home/path/mail.jar:/home/path/servlet.jar;"

Instead of "-cp" you could also use "-classpath"

javac -classpath ".:/home/path/mail.jar:/home/path/servlet.jar:"

You could including the jars every time you compile by setting the environment variable "CLASSPATH" correctly. The environment variable will store the path where the jars and classes that needs to be used for compiling/executing any java file. You will not have to include the jars individually every time you compile you file.

Different machines have different methods to set the classpath as an environment variable. The commands for Windows, Linux, etc are different.

You can find more details in this blog.

Compile and Run Java in Command Line with External Jars, The jar file is downloaded to "jars" directory which is located the same with import org.apache.commons.lang3.*; public class  You can include your jar files in the "javac" command using the "-cp" option. Instead of "-cp" you could also use "-classpath" You could including the jars every time you compile by setting the environment variable "CLASSPATH" correctly.

Please try on Linux

javac -cp jarfile source file 


javac  -cp .:/jars/* com/template/*.java

5 ways to add multiple JAR in to Classpath in Java, One thing Java developer must know is how to add JAR files to Classpath of a 2. Include name of JAR file in -classpath command line option. 2. Compile & Run Java Program With External Jar. Now let's download a third-party library and use some method from the library. In this case, I downloaded apache.commons.lang from here, and use the StringUtils.capitalize() method. The jar file is downloaded to "jars" directory which is located the same with

Syntax will work on windows dos command:

javac -cp ".;first.jar;second.jar;third.jar"

How to compile, package and run a Java program using command , How to use javac, java and jar commands to compile, package and How to compile, package and run a Java program using command-line tools (javac, jar and java) sql = "INSERT INTO Student (name, email, university) VALUES (?, ?, ?) Before wrapping the compiled files into an executable JAR file,  What is a Jar File? A jar file is a Java Archive File and is built off of the zip format that is familiar to many Windows users. Jar files allow you to compress data to take up less space and they allow you to combine many individual files into one entity. For instance, if you have two compiled classes. A.class; B.class

Try to add all dependency jar files to your class path through environment variable settings or use the below steps:

  1. Open command prompt.
  2. Change directory to the location of you java file that you would like compile.
  3. Set the classpath for your dependency jar files as shown below:

    set classpath=C:\Users\sarath_sivan\Desktop\jars\servlet-api.jar; C:\Users\sarath_sivan\Desktop\jars\spring-jdbc-3.0.2.RELEASE; C:\Users\sarath_sivan\Desktop\jars\spring-aop-3.0.2.RELEASE;

  4. Now, you may compile your java file. (command: javac

Hope this will resolve your dependency issue.

Java classpath - how to set classpath in java, When you have set of jar files which are always required during your Use -​classpath argument to set classpath from command prompt/console. Below syntax examples will add single jar file in classpath. e.g. let's say there are five .​class files are present in location folder which you want to include in classpath. Open command prompt and move the current directory to the StudentProgram. javac -d classes src et\codejava\ This command compiles the source file and places the.class files under the classes directory. The -d option is used to specify the output directory containing compiled files.

The followings are steps,

  1. Copy all jars and your .java file in a same folder (It will be easy to mention file names instead of mentioning long path. Though you can keep jar and .java in separate folders).

  2. To compile,

    javac -cp .:<file_1_name>.jar:<file_2_name>.jar <prog_name>.java
  3. To execute,

    java -cp .:<file_1_name>.jar:<file_2_name>.jar <prog_name>

I hope this helps!

Creating an Executable jar File, jar files are created using the jar.exe utility program from the JDK. If you use it as a library, you can edit and compile any of the classes included in the jar, and add it to your project. JDK's bin folder, the same place where javac.exe and java.exe are. jar.exe takes command-line arguments; Set path to include JDK's bin. To ensure that your file is saved as a .java file, be sure to write .java after the file name, and select All Files from the dropdown extension menu. Make note of where you saved the file on your system.

How do I update my classpath to include a jar file?, At the command prompt in the C:\stuff directory, I can type the following to compile the file. If I didn't include commons-lang in the classpath, I'd get a  A class file is a compiled Java program that can be executed by the java command. The Java compiler reads source files and creates class files. To use one or more of these options, type the option before or after the source filename. Either of the following commands, for example,

Running Java Programs with Command-Line Arguments, Eclipse can also export your program as a “runnable JAR file” that contains generated JAR file includes the code from the other jar files you depend on return Parser.compile(grammarStream, IntegerGrammar. The input-file(s) argument is a space-separated list of one or more files that you want to include in your JAR file. The input-file(s) argument can contain the wildcard * symbol. If any of the "input-files" are directories, the contents of those directories are added to the JAR archive recursively.

Setting the class path, sdkTool: A command-line tool, such as java , javac , javadoc , or apt . For a .jar or .zip file that contains .class files, the class path ends with the name of the .zip modify your CLASSPATH environment variable to include the libaries they use. This will ensure that your generated JAR file includes the code from the other jar files you depend on, like parserlib.jar and physics.jar in this project. After you finish the dialog, open your command prompt and cd to the folder containing the jar file you just generated. Assuming its name is myproject.jar,

  • type "javac -help"
  • hope this helps you..
  • Note to self: you must use -cp/-classpath flag before the name of the java file you want to run, otherwise it will ignore the flag. java -cp ".;magic.jar" Foo is ok java Foo -cp ".;magic.jar"is not.
  • javac -classpath ".:/home/path/mail.jar;/home/path/servlet.jar" worked for me. I was using mac. I read somewhere that ':' is used for unix.
  • I have used this command but when tried to access the class present in jar file, I am getting ClassNotFoundException.
  • what does .: do? sorry if it is a dumb question, but it is not obvious to me.
  • @kensen. Typo mistake. replace : (colon) with semicolon (;)
  • Above didn't worked for me on ubuntu. I tried without quotation mark and it worked. Ex. javac -cp .:/home/path/mail.jar:/home/path/servlet.jar;
  • When I try the EXAMPLE :-, with .:/jars replaced with the directory in which my JAR files are located, I get the error message javac: invalid flag: /location/of/first/jar/file.jar.
  •… please refere this ,it may solve your problem
  • After successful execution of above command how to run the java class file?
  • java -cp first.jar:second.jar:third.jar MyFile