Function doesn't return right array's values

I've started learning functions in C.

I have a task to convert numbers from imperial to metric, which are contained in the 2d Array.

Array:

{1300, 0}  [0][0] [0][1]

{2198, 0}  [1][0] [1][1]

{4199, 1}  [2][0] [2][1]

{2103, 0}  [3][0] [3][1]

{3104, 1}  [4][0] [4][1]

{1093, 1}  [5][0] [5][1]

{3204, 0}  [6][0] [6][1] 

So I am calling function with double return SortedArray[DATA_ROWS] = find_function(MixedData);

find_function logic:

0 is an indicator of the metric system value and 1 is an indicator of imperial system value, i is a row indexer and j is a column indexer.

So when for cycles find out that column value is 0 or 1 they save [j-1](an actual value that we need) into SortedArray.

It also converts value if finds out that column value is 1 SortedArray[i] = MixedData[i][j-1]*CONSTANT;

Just for a check, I did printf to see if values are correct and correctly converted if needed. I got this output:

1300.00
2198.00
1301.69
2103.00
962.24
338.83
3204.00

So, seems like correct, but in Task I have another task - use 2 functions to solve this task. I've decided to make another function, which will sum all values in SortedArray[DATA_ROWS] and then calculate avg - average. Then print them out. And here comes the problem.

Calling function with no return total_AVG(SortedArray); with copied array SortedArray[DATA_ROWS]

Just to check made a printf and got this:

-1.#R
0.00
0.00
0.00
0.00
0.00
0.00

It seems like my SortedArray[DATA_ROWS] did not copy into the second function total_AVG

Pointers are coming in the next task, so according to task's timeline I can't use them * (and even if I could, I have no idea how to use them still)*

Can you please tell me, what I am doing wrong.

NB: Some comments and variables, which are not used just old ones, when I tried to correct my code. And also I only need to understand why SortedArray[DATA_ROWS] did not copy into second function total_AVG. All further logic will be corrected after solving this problem.

Thank you! And sorry for broken English!

CODE:

#include <stdio.h>
#define DATA_ROWS 7
#define DATA_COLS 2
#define CONSTANT 0.31
#define MAX 3


double find_function(int MixedData[DATA_ROWS][DATA_COLS]);
void total_AVG(double SortedArray[DATA_ROWS]);


int main(void)
{
    int i;
    double SortedArray[DATA_ROWS];


    int MixedData[DATA_ROWS][DATA_COLS] = {
        {1300, 0},//[0][0] [0][1]
        {2198, 0},//[1][0] [1][1]
        {4199, 1},//[2][0] [2][1]
        {2103, 0},//[3][0] [3][1]
        {3104, 1},//[4][0] [4][1]
        {1093, 1},//[5][0] [5][1]
        {3204, 0}};//[6][0] [6][1]

    SortedArray[DATA_ROWS] = find_function(MixedData);
    total_AVG(SortedArray);


    return 0;
}

double find_function(int MixedData[DATA_ROWS][DATA_COLS])
{
    // imperial numbers from source array "mixedData" are 4199,3104,1093;

    int i,j; // indexers
    double SortedArray[DATA_ROWS]; 




    // 7 rows, each row suppose to contain only metric values
    // That means, if second for cycle with j indexer finds 0, it will contain j-1 value for example 1300 in SortedArray
    // If it finds in second for cycle with j indexer 1, it will converte the value from imperial to metric for example 4199*0.31
        /*  {1300, 0}  [0][0] [0][1]
            {2198, 0}  [1][0] [1][1]
            {4199, 1}  [2][0] [2][1]
            {2103, 0}  [3][0] [3][1]
            {3104, 1}  [4][0] [4][1]
            {1093, 1}  [5][0] [5][1]
            {3204, 0}  [6][0] [6][1] */


    // Probably problem in "double SortedArray and int MixedData"
    for(i=0;i<DATA_ROWS;i++)
    {
        for(j=0;j<DATA_COLS;j++)
        {
            if(MixedData[i][j]==0)                                               
            {
                SortedArray[i] = MixedData[i][j-1];
            }
            else if(MixedData[i][j]==1)
            {
                SortedArray[i] = MixedData[i][j-1]*CONSTANT;

            }
        }
    }
    for(i=0;i<DATA_ROWS;i++)
    {
        //total += SortedArray[i];
        printf("%.2lf\n", SortedArray[i]);
    }

    return SortedArray[DATA_ROWS];
}

void total_AVG(double SortedArray[DATA_ROWS])
{
    double avg,total;
    int i;

    for(i=0;i<DATA_ROWS;i++)
    {
        printf("%.2lf\n", SortedArray[i]);
    }
    //avg = total/DATA_ROWS;
    //printf("Total by every worker: %.2lf\n",total);
    //printf("In average by every worker: %.2lf", avg);

    return;
}


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You cant use arrays like this

return SortedArray[DATA_ROWS];
SortedArray[DATA_ROWS] = find_function(MixedData);

You can pass it as parameter to function. like below.

find_function(MixedData, SortedArray);

void find_function(int MixedData[DATA_ROWS][DATA_COLS], double SortedArray[DATA_ROWS])
{
// Dont define, use itt from parameter
// double SortedArray[DATA_ROWS];

// ...

// Dont need to return.
// return SortedArray[DATA_ROWS];
}

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The function you've defined is:

double find_function(int MixedData[DATA_ROWS][DATA_COLS]) { }

It's return type is double whereas you're trying to return an array, assays can't be returned liked nor can be assigned.

return SortedArray[DATA_ROWS]; 

Here you're trying to access the element which is equal to length, it's wrong. What you can do is, pass array as function parameter (or as a pointer) and return void. i.e:

void find_function(int MixedData[DATA_ROWS][DATA_COLS], double* SortedArray) { /*...*/ }

or you may use dynamic memory allocations.. in case you want to return the base address from the function.

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