oracle pl-sql find the 3rd wednesday of a given date

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Currently I have a process which takes a date variable EG: '01-MAR-2026', it then iterates over this date checking if the day is wednesday. If so then increment a counter else add 1 day and check again. This exits when the wednesday count is = 3.

IF (to_char(v_Date,'dy') = 'wed') THEN
        v_NumWed := v_NumWed + 1;
END IF;

WHILE (v_NumWed != 3) LOOP
    v_Date := v_Date + interval '1' day;
    IF (to_char(v_Date, 'dy') = 'wed') THEN
        v_NumWed := v_NumWed + 1;
    END IF;
END LOOP;

However I have a feeling there is a simpler way to achieve this maybe via a query or something not using a loop EG: use an input date and query to find the first wednesday then + 14 days?

Any suggestions would be great, thanks in advance :)

EDIT: I have something like this which appears to work, also considers if the first day is a wednesday itself.

select next_day(trunc(v_date, 'MM') - 1, 'WED'), next_day(trunc(v_date, 'MM') - 1, 'WED') + 14 into v_first, v_third from dual;

SOLVED: thanks for the help folks, got a few possible solutions now in the comments!


TO get the third Wednesday from a date, including that date if ti is itself a Wednesday, you can do:

select next_day(date '2026-03-01' + 13, 'Wednesday') from dual;

NEXT_DAY(D
----------
2026-03-18

The next_day function is a bit awkward because it is NLS-sensitive, and doesn't have an override (like to_char() does) - so the NLS session language and the day name/abbreviation have to be in the same language. If you can't control then then you can work around it by getting the current-language day-name from a known fixed date:

alter session set nls_date_language = 'French';

select to_char(date '2026-03-01', 'Day'),
  next_day(date '2026-03-01' + 13, to_char(date '1999-12-29', 'Day'))
from dual;

TO_CHAR( NEXT_DAY(D
-------- ----------
Dimanche 2026-03-18

Demo with some sample dates:

with t (sample_date) as (
  select date '2026-02-15' + level
  from dual
  connect by level <= 31
)
select sample_date, next_day(sample_date + 13, 'Wednesday') as third_wed
from t
order by sample_date;

SAMPLE_DAT THIRD_WED 
---------- ----------
2026-02-16 2026-03-04
2026-02-17 2026-03-04
2026-02-18 2026-03-04
2026-02-19 2026-03-11
2026-02-20 2026-03-11
2026-02-21 2026-03-11
2026-02-22 2026-03-11
2026-02-23 2026-03-11
2026-02-24 2026-03-11
2026-02-25 2026-03-11
2026-02-26 2026-03-18
2026-02-27 2026-03-18
2026-02-28 2026-03-18
2026-03-01 2026-03-18
2026-03-02 2026-03-18
2026-03-03 2026-03-18
2026-03-04 2026-03-18
2026-03-05 2026-03-25
2026-03-06 2026-03-25
2026-03-07 2026-03-25
2026-03-08 2026-03-25
2026-03-09 2026-03-25
2026-03-10 2026-03-25
2026-03-11 2026-03-25
2026-03-12 2026-04-01
2026-03-13 2026-04-01
2026-03-14 2026-04-01
2026-03-15 2026-04-01
2026-03-16 2026-04-01
2026-03-17 2026-04-01
2026-03-18 2026-04-01

Ask TOM "How to find out if the date is a weekend or , I'm having trouble figuring out how to find out if the date is a weekday or a weekend from a column. Day, then generate the results to date_desc of table B using PL/SQL block? SQL> CREATE TABLE t 2 (id int, 3 d date); Table created. 18 10-MAY-17 19 11-MAY-17 20 12-MAY-17 20 rows selected. Oracle SQL Day Of Week. Occasionally we need to find out the day of week from a given date. This is also achieved throug TO_CHAR function with appropriate date flag ā€˜Dā€™. Specifically the expression below can be used to get the day of week from date value. to_char(date_value,ā€™Dā€™)


How about this? Find the first Wednesday (using NEXT_DAY) that follows some date, and add 14 days (i.e. 2 weeks) to find the 3rd Wednesday.

SQL> alter session set nls_date_format = 'dd.mm.yyyy';

Session altered.

SQL> alter session set nls_date_language = 'english';

Session altered.

SQL> WITH test (col)
  2       AS (SELECT DATE '2020-01-27' FROM DUAL
  3           UNION ALL
  4           SELECT DATE '2020-02-06' FROM DUAL
  5           UNION ALL
  6           SELECT DATE '2020-02-12' FROM DUAL)
  7  SELECT col, NEXT_DAY (col, 'wed') + 14 next_3
  8    FROM test;

COL        NEXT_3
---------- ----------
27.01.2020 12.02.2020
06.02.2020 26.02.2020
12.02.2020 04.03.2020

SQL>

[EDIT]

If comment you posted means that - for any date - you want to find 3rd Wednesday in that month, then truncate date to month (which returns 1st day in that month) and find the 3rd Wednesday, taking care about whether the 1st day of the month is (or is not) Wednesday.

SQL> WITH test (col)
  2       AS (SELECT DATE '2020-01-27' FROM DUAL
  3           UNION ALL
  4           SELECT DATE '2020-02-06' FROM DUAL
  5           UNION ALL
  6           SELECT DATE '2020-03-18' FROM DUAL)
  7  SELECT col,
  8           NEXT_DAY (TRUNC (col, 'mm'), 'wed')
  9         + CASE
 10              WHEN TO_CHAR (TRUNC (col, 'mm'), 'dy') = 'wed' THEN 7
 11              ELSE 14
 12           END
 13            next_3
 14    FROM test;

COL        NEXT_3
---------- ----------
27.01.2020 15.01.2020
06.02.2020 19.02.2020
18.03.2020 18.03.2020

SQL>

WeekDay, Use this function to determine the day of the week in a given date and return the Sunday. 2. Monday. 3. Tuesday. 4. Wednesday. 5. Thursday. 6. Friday. 7. Date. Enter a valid date string. The system assumes your entry is in the format specified by the Format parameter. The default is the current date. Format. Enter a valid date format that describes the format used by your entry in the Date parameter. The default is date format 1 (MM/DD/YY). Locale (Optional) Enter the locale code.


I know you already solved the issue, just wanted to show you another example:

DECLARE
        dStartDate DATE := SYSDATE;
        dNextWednesDay DATE;
BEGIN
        FOR n IN 1..3 LOOP
                dNextWednesDay := NEXT_DAY(dStartDate, 'WEDNESDAY');
                DBMS_OUTPUT.PUT_LINE(dNextWednesDay);

                dStartDate := dNextWednesDay +1;
        END LOOP; 
END;
/

Output:

2020-02-19 15:33:58
2020-02-26 15:33:58
2020-03-04 15:33:58

Ask TOM "Displaying week days for current week", I would like to output all weekdays (monday-friday) of the current week. SQL> exec :x := '26-SEP-2016' PL/SQL procedure successfully completed. SQL> SQL> select 2 next_day(to_date(:x,'DD-MON-YYYY'),'MON') + 3 case days) starting with a given date and having week count always start with 1? I want the sql to get the start of the week date and end of the week date for a given date and my week starts from saturday and ends with friday. Example, if the given date is 03/mar/2018 then start date is - 03/mar/2018 and end date is 09/mar/2018 if the given date is 04/mar/2018 then start date is - 03/mar/2018 and end date is 09/mar/2018


Oracle NEXT_DAY Function By Practical Examples, function to get the date of the next weekday which is later than a specified date. that evaluates to a DATE value which is used to find the next weekday. Thanks for the question, Cindy. Asked: January 22, 2003 - 4:48 pm UTC. Answered by: Tom Kyte - Last updated: August 31, 2005 - 2:02 pm UTC


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