## Counter in double loop with counting in both internal and external for

I would like to know if there is a well-known formula for the following way of counting:

count = 0 for i in range(n): for j in range(m): count = count + 1 count = count + 10

Many thanks in advance,

Cayo

EDIT 1:

Thanks Ernest, you are right, but that is not really the problem. Sorry, I was not clear enough, let me explain better my problem. I don't just want to count, I need use this counter inside the inner loop. I have a 2D flatten array and I want to access just a sub-2D-region of this array. So, actually, what I am doing is:

count = 0 for i in range(n): for j in range(m): big_flatten_array(count) = value count = count + 1 count = count + 10

EDIT 2: It doesn't work just using

count = i * 10 + j

Try checking the values:

count = 0 for i in range(3): for j in range(): k = i * 2 + j vec[k] = count vec2[k] = i * 10 + j count = count + 1 count = count + 10

And you will see the vec and vec2 are not the same...

Let's consider that the line `count = count + 10`

didn't exist, then it would simply be:

count = i*m + j

Consider n = 3, and m = 3
So the count values are like 0, 1, 2, 3, 4 ..
once you add the line `count += 10`

, you're simply adding multiples of 10 to the count value each time the outer loop finishes.

0, 1, 12, 13, 24, 25... or 0, 1, 10 + 2, 10 + 3, 20 + 4, 20 + 5...

so the expression becomes

count = (10*i) + (i*m+j)

And you can get all the count values like so:

count = [(10 * i) + (i * m + j) for i in range(n) for j in range(m)]

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There is really simple solution

count = n*(10+m)

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Let me try. If I understand correctly you just need current (not final) value of `count`

inside the loop. So this should do:

# In the inner loop count = i * 10 + j

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foreach is a loop which iterates through a collection or array one by one, starting from 0 index till the last item of the collection. So, if I have n items in an array. foreach (var item in arr) { }