regex multiline with diffrent length

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I have a multi line text.

Leui Centum 07 Base 9GALLON  
2020-02-10  
1,00 kg  461,90 461,90710201449  
3899104400  
EAN13 7344236003355

Leui Centum 07 Base 9GALLON  
2020-02-10  
1,00 kg  159,62 159,62050223  
3248900000  
EAN13 7358962113386

Well I´ve tried for a while now to get the last characters behind the second decimal at line 3

If the whole line goes:

1,00 kg  159,62 159,62050223

^\d,?[,$].+,.. with regex: the value I get is

1,00 kg  159,62 159,62

but my goal is to get the value marked in bold.

1,00 kg 159,62 159,62 050223 1,00 kg 461,90 461,90 710201449

as you can see the length dont match as the lines in the whole text is digits. when I try to use $ I get all the lines besides the first. and I cant figure how to escape to only get the 3:rd line, I cant use . becuse the lenght is diffrent. any suggestions?

Your regex is very loose see this example https://regex101.com/r/7qVM6W/1 You need to look at the actual requirements for line 3, will it always be in the format you suggest? if so maybe try the following regex with a capture group to grab the final characters.

questions to ask

  1. is the value always in the same shape?
  2. is it always kg
  3. is the value at the end always a number?

https://regex101.com/r/7qVM6W/2

^(\d+,?)+\d+ (kg|lb|ton) (\d+,?)+\d+ \d{3},\d{2}(?<VALUE>\d+)

the VALUE you're after will be in the final capture group

Multiline mode of anchors ^ $, flag "m", In the multiline mode they match not only at the beginning and the end of the string, but also The regular expression \d$ finds the last digit in every line Another difference: now every match includes a newline character \n . multiline.flush_pattern Specifies a regular expression, in which the current multiline will be flushed from memory, ending the multiline-message. multiline.max_lines The maximum number of lines that can be combined into one event. If the multiline message contains more than max_lines, any additional lines are discarded. The default is 500.

I've been able to achieve this with this simple regex:

.*kg.*(\b\d+$)

Explanation: Search for a line that has "kg" in it and take a number that's at the end of the line into a capturing group. Be sure to have multiline flag on.

A demo on regex101.com: https://regex101.com/r/U9PQ8I/1/

Regex Tutorial, A regex that consists solely of an anchor can only find zero-length matches. This can be Like in all other flavors, Boost's \Z is independent of multi-line mode. I would like to know the regex to match words such that the words have a maximum length. for eg, if a word is of maximum 10 characters in length, I would like the regex to match, but if the length exceeds 10, then the regex should not match. I tried ^(\w{10})$ but that brings me matches only if the minimum length of the word is 10 characters.

RegExp.prototype.multiline, The multiline property indicates whether or not the "m" flag is used with the regular expression. multiline is a read-only property of an individual� Let’s see what happens when we try to match ^ 4 $ to 749 486 4 (where represents a newline character) in multi-line mode. As usual, the regex engine starts at the first character: 7. The first token in the regular expression is ^. Since this token is a zero-length token, the engine does not try to match it with the character, but rather

7.2. re — Regular expression operations — Python 2.7.18 , Matches the start of the string, and in MULTILINE mode also matches match the pattern; note that this is different from a zero-length match. It is a bit difficult to explain what I would like to see, but I will give it a try though: If it is possible I want the regular expression(s) to match the underscored (cause a bankaccount is available after :86:) the bankaccount is P 12345678 and is allways 9 or 10 characters and it is allways in this position.

Pattern (Java Platform SE 7 ), A regular expression, specified as a string, must first be compiled into an Note that a different set of metacharacters are in effect inside a character class than If MULTILINE mode is activated then ^ matches at the beginning of input and after the pattern is applied and therefore affects the length of the resulting array. The following regular expression ensures that text is between 1 and 10 characters long, and additionally limits the text to the uppercase letters A–Z. You can modify the regular expression to allow any minimum or maximum text length, or allow characters other than A–Z.

A simple cheatsheet by examples. UPDATE! Check out my new REGEX COOKBOOK about the most commonly used (and most wanted) regex 🎉. Regular expressions (regex or regexp) are extremely useful in

Comments
  • Value reference gave me the correct value! Thank you! Not only did you solve the problem you actually give me good insight!
  • is it possible to use regex in automation, actually to clean PDFs, I´m a bit new to regex, let´s say we got diffrent suppliers and they send bills in PDFs but diffrent layouts. is it possible for regex to clean the data for all PDFs to get the desierd output?
  • That is a much bigger question than the regex one you are originally asking about here.Ii have no experience with doing that, it may be possible, i would recommend asking another question on stackoverflow
  • This is an extreamly loose regex . will match any character so you will match the string "foobar-kg!!!!!?? 12121212121212121212" probably not what you want! see regex101.com/r/U9PQ8I/2
  • Well I guess the topic starter can decide if that's what he wants or not. Given his data structure, it works just fine and is simple to read. Of course if data structure changes a lot, then he needs a more complicated solution.
  • Hi pavel, this one gave me the whole number, reach to the comma, what I want is to exclude it from the second decimal, like from : 1,00 kg 159,62 159,62050223 I want 050223 and: 1,00 kg 461,90 461,90710201449 I want 710201449 the structure is more complicated, but we can leave the whole data structure for now becuse first things first :)
  • hey @friend, so you need a number on from two digits after a coma like 1,234567 turns into 4567? Is that correct?
  • correct, the regex seemed little bit complex for my knowlage.
  • This would match the following ",,,,,,,,,,,, kg ,,, ,,,12345 " i suppose it depends on the specification of the data file as to is this would ever happen and what should occur if it does
  • @Damo Yes, exactly! Well, the best person to know how to write the regex is the one that knows what the data contains!
  • true, we are but guessing at the true business requirements