How do I remove spaces, brackets and everything in between using REGEX in Javascript

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Cant seem to find the same question on here, so here goes,

my string that i want to edit is: +44 (0)1234 123321 I want to remove:

  1. All spaces
  2. Both brackets
  3. Anything inside the brackets

So it should output as +441234123321


Ive already tried:

const phoneRaw = phone.replace(/\([^\)\(]*\)/, ""); const phoneRaw = phone.replace(/[( )]/g); <-- This gets rid of brackets and spaces

let string = '+44 (0)1234 123321';
let regex = /\s+|\(.*?\)/g;
let result = string.replace(regex,'');

\s+ matches any whitespace. \(.*\) matches anything inside of parenthesis.

JavaScript/regex: Remove text between parentheses, var prevStr; do { prevStr = str; str = str. replace(/\([^\)\(]*\)/, ""); } while (prevStr != str); InDesign: how to remove everything between square brackets , test{{this should not be selected and the curly brackets too}} but this one { or } should be selected. In regex-builder I can get matches with the following: But when I try to do any kind of regex-replace across the file, with a replace pattern like {\1} I get 0 matches. Flummoxed.

What about this?

phoneRaw = '+44 (0)1234 123321';

function clearPhoneNumber (phone) {
  return phoneRaw.replace(/(\(\d+\))|[^\d]/g, '');


It will replace anything in between (...) and anything that isn't a number.

If you want to keep the + sign, you can use this instead, inside that function:

return phoneRaw.replace(/(\(\d+\))|[^\d|\+]/g, '');

Remove everything from text except what is in brackets with Regex , RegEx for Remove everything from text except what is in brackets with Regex. Test String. [D-1.1.1-A] - bla bla text here[D-1.1.1-B] - some more bla bla text� you are right the sed -e 's/([[^]]*)( )/\1/' replace the last space between the brackets. the sed you provided me is the right one. THANK YOU – ekassis Feb 1 '13 at 17:20 I found this query when I was interested in remove spaces between double quotes.

try this.

let str = '+44 (0)1234 123321';
console.log(str.replace(/\(.*?\)|[^0-9+]/g, '')); 

JavaScript RegExp Object, The search pattern can be used for text search and text replace operations. In JavaScript, regular expressions are often used with the two string methods: search() and replace() . The search() method uses [abc], Find any of the characters between the brackets, Try it �. [0-9], Find \s, Find a whitespace character, Try it �. A simple cheatsheet by examples. UPDATE! Check out my new REGEX COOKBOOK about the most commonly used (and most wanted) regex 🎉. Regular expressions (regex or regexp) are extremely useful in

Regular Expression Examples, But you will earn back that time quickly when using regular expressions to Anything between the tags is captured into the first backreference. Search for ^[ \t]+ and replace with nothing to delete leading whitespace (spaces and tabs). Search Illustrates simple yet clever use of capturing parentheses or backreferences. Url Validation Regex | Regular Expression - Taha Match or Validate phone number match whole word nginx test Extract String Between Two STRINGS Match html tag Blocking site with unblocked games Find Substring within a string that begins and ends with paranthesis Empty String Checks the length of number and not starts with 0 Match anything after

Strings between the curly braces, Match anything enclosed by square brackets. Blocking site with unblocked games � Find Substring within a string that begins and ends with paranthesis I am using zone ocr to capture a value example G123456 A I need to remove the blank space between the 6 and the A. I have tried a number of variations such as \w[0-9]+ this returns G123456 any help would be appreciated.

Links to help debug RegEx: Debuggex: Online visual regex tester. JavaScript, Python, and PCRE., here, you see your RegEx as a diagram , it is helpful to understand where is a problem.NET Regex Tester - Regex Storm

  • Why has this got negative rating for a simple question?
  • Because you're asking us to do your job. You should, at least, try it yourself, post your tries, and then let us help if you don't understand something
  • Do you not think I've already tried? Hence the reason I'm here in the first place, I dont understand REGEX in general if I'm honest.
  • \s* also matches the emptiness between all characters. Is there any reason to prefer that over \s+?
  • Good catch, I'll fix that.
  • Thank you very much! Appreciate it
  • Needs a global flag (g), otherwise it will just replace the first space and nothing else.
  • Also, making it non-greedy would cover multiple sets of parenthesis /\s+|\(.*?\)/g