Newtonsoft json is not deserializing when the name of the class is the root element

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Newtonsoft json DeserializeObject is not parsing the json message when the name of the class is the root element.

var json = "  {\r\n \"amount\": {\r\n    \"currency\": \"EUR\",\r\n    \"value\": 99792\r\n  }\r\n}";
var amount = JsonConvert.DeserializeObject<Amount>(json)

and the class

class Amount 
{
    [JsonProperty("value")]
    public decimal? Value { get; set; }

    [JsonProperty("currency")]
    public string Currency { get; set; }
}

In that case the Amount properties are null. The problem is that the amount is nested in a more complex json and I found out that it is always returned empty because it starts with the "amount". Of course I tried some annotations in the Amount class like [DataContract] and [JsonObject] but still it is empty In case of:

 var json = "{\r\n    \"currency\": \"EUR\",\r\n    \"value\": 99792\r\n }";

Then is parsed properly. The question is how can I deseriale the json in the first case?

how can I deseriale the json in the first case

Reason why your json is not getting deserialized correctly is because Newtonsoft does not know how to translate amount to your class that has two variables, named: currency and value. To deserialize the json in the first case, you need a class for the first object: amount. This object contains another object that matches up with the class you were working with, Amount.

When you add the missing class, RootObject, and deserialize to that RootObject, you will see the json deserialize correctly.

Classes you need

public class Amount
{
    [JsonProperty("currency")]
    public string Currency { get; set; }
    [JsonProperty("value")]
    public int Value { get; set; }
}

public class RootObject
{
    [JsonProperty("amount")]
    public Amount Amount { get; set; }
}

Use this for Deserialization

var amount = JsonConvert.DeserializeObject<RootObject>(json)

Easy way to find the classes

I have found www.json2csharp.com to be a pretty good resource. Whenever in doubt, copy / paste your json there to get all the classes you need. Copy them in your project and deserialize to RootObject. If your JSON is invalid, you'll find out whats wrong there as well.

JsonConvert Class, C#. Copy. public static class JsonConvert. The JsonConvert type exposes the following members. Properties. Name, Description. Public property Static Deserializes the XmlNode from a JSON string nested in a root element specified by� Gets or sets the name of the root element to insert when deserializing to XML if the JSON structure has produced multiple root elements.

You could create a wrapping class Root, which has a single element called Amount. For example,

public class Root
{
    [JsonProperty("amount")]
    public Amount Amount { get; set; }
}

You would now need to deserialize to an instance of Root. For example,

var amount = JsonConvert.DeserializeObject<Root>(json);

Alternatively, if you do not want to declare another class, you could also use

var innerJson = JObject.Parse(json)["amount"].ToString();
var amount = JsonConvert.DeserializeObject<Amount>(innerJson);

Serialization Attributes, OptIn)] public class Person { // "John Smith" [JsonProperty] public string Name { get; [JsonProperty] public DateTime LastModified { get; set; } // not serialized� I don't want to use dynamic typing, I have my class Diagnostics.Common.DiskSpaceInfo that I want to use when deserializing. I am using Json.NET (Netwonsoft JSON). The question is how to tell it to ignore the root element (that 'd' element) and parse what is inside. The best solution I have so far is to use an anonymous type:

You should model your classes like this:

public class Amount
{
    [JsonProperty("value")]
    public decimal? Value { get; set; }

    [JsonProperty("currency")]
    public string Currency { get; set; }
}

public class RootObject
{
    [JsonProperty("amount")]
    public Amount Amount { get; set; }
}

Then deserialize RootObject:

var amount = JsonConvert.DeserializeObject<RootObject>(json);

Note: You can paste your JSON into json2csharp.com, which models your JSON into C# classes for you.

JsonPropertyAttribute name, This sample uses JsonPropertyAttribute to change the names of properties when they are serialized to JSON. Sample. Types. Copy. public class Videogame� This article shows how to use the System.Text.Json namespace to serialize and deserialize to and from JavaScript Object Notation (JSON). If you're porting existing code from Newtonsoft.Json, see How to migrate to System.Text.Json. The directions and sample code use the library directly, not through a framework such as ASP.NET Core.

How to serialize and deserialize JSON using C#, Json namespace to serialize to and deserialize from JSON in .NET. It includes sample code. The code examples refer to the following class and variants of it: C# Copy attributes. This is why the JSON property name Wind in the example is not camel case. JsonDocument exposes a RootElement property. The following� public class Address { [DataMember(Name = "address_1")] public string AddressLine1 { get; set; } } This will work fine. Upon investigation it seems that for enum json.net uses internally enum.tryparse which doesnt use the enummember attribute. If json.net could be fixed in that manner so that enummember value could be used that would be great

DataContractJsonSerializer Class (System.Runtime.Serialization , Serializes objects to the JavaScript Object Notation (JSON) and deserializes JSON C# Copy. public sealed class DataContractJsonSerializer : System. Runtime. with properties that contain essential data, such as a name and address. or deserialize an object of a specified type using the XML root element specified by� This sample uses T:Newtonsoft.Json.JsonPropertyAttribute to change the names of properties when they are serialized to JSON.

Newtonsoft.Json Represents a reader that provides fast, non-cached , Initializes a new instance of the class with the specified . Json.NET will use a non-public default constructor before falling back to a paramatized constructor. Gets or sets the name of the root element to insert when deserializing to XML if� Deserializes the from a JSON string nested in a root element specified by . Newtonsoft.Json The name of the root element to append when deserializing.