Understanding bool operator==(paramater 1, parameter 2)

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logical operators in java

bool operator==(str_array a, str_array b)

Where str_array is a struct for my assignment. What does this notation mean, how will this need to be considered for when I implement the function, and how do I call it when I'm done (same as normal function calls?)

This is the first time seeing this notation. The implementation is a simple comparison between two str_array variables (I know how to implement this without the weird notation)

How do I call it when I'm done?

As you have defined an operator, then it is not called like a 'normal' function! Rather, it can be used like a 'normal' operator:

str_array sa1;
str_array sa2;
//.. some code
if (sa1 == sa2) { // Here, you are calling the == OPERATOR that you've defined
    //.. do something

The implementation will, however, look like a normal function:

bool operator==(str_array a, str_array b) {
    bool answer;
    // some code that sets "answer" according to the (in)equality of a and b
    return answer;

Ambiguous function overloading in C++ — Matt Godbolt's blog, Take the example code snippet: candidate 1: operator==(int, int) <built-in> note : candidate 2: bool The second parameter gets converted: Parameter Class Reference. #include <parameter.h> Public Types: enum ParamType { UNDEFINED, REAL, STRING, BOOL, INT, STEREOSAMPLE, VECTOR_REAL, VECTOR_STRING,

When you do something like (where a and b are str_array)

if (a == b) { // ...

This function will be called.

operator== is the name of the function that using the == calls. You are supposed to return true if the arguments are equal.

Logical operators, If any of its arguments are true , it returns true , otherwise it returns false alert( 1 && 2 && 3 ); // 3, the last one The boolean NOT operator is represented with an exclamation sign ! What is the code below going to output? If operator== is a non static data member, is should take only one parameter, as the comparison will be to the implicit this parameter: class Foo { bool operator==(const Foo& rhs) const { return true;} }; If you want to use a free operator (i.e. not a member of a class), then you can specify two arguments:

This is operator overloading. You are creating an overload of the == operator that accepts an str_array object on either side of the operator:

str_array a1;
str_array a2;
if (a1 == a2)

Overload resolution, 2) rvalues can be bound to non-const implicit object parameter (unless this The function-call operators of T are obtained by ordinary lookup of the 1) Conversion that involves pointer to bool or pointer-to-member to bool is� 11 1 1 bronze badge Shoving " using namespace std; " into a header file is just asking for a world of hurt . You will really do yourself a big favor if you completely forget that "using namespace std;" is a part of C++, and learn how to use namespaces correctly.

This function

bool operator==(str_array a, str_array b);

introduces an overloaded equality operator (operator ==) for objects of the type str_array.

So you can compare twp objects of the type as you do with fundamental types as for example

if ( a == b ) { /* do something */ } 

The compiler will substitute the expression a == b for a call of the overloaded operator == (function).

Here is a demonstrative program with two overloaded operators: operator == and operator <<.

#include <iostream>
#include <iomanip>

class A
    explicit A( int x = 0 ) : x( x ) {}

    friend bool operator ==( const A &a1, const A &a2 )
        return a1.x == a2.x;

    friend std::ostream & operator <<( std::ostream &os, const A &a )
        return os << a.x;

    int x;

int main() 
    A a1( 10 ), a2( 10 ), a3( 20 );

    std::cout << "a1 = " << a1 << '\n';
    std::cout << "a2 = " << a2 << '\n';
    std::cout << "a3 = " << a3 << '\n';

    std::cout << "a1 == a2 is " << std::boolalpha << ( a1 == a2 ) << '\n';
    std::cout << "a2 == a3 is " << std::boolalpha << ( a2 == a3 ) << '\n';
    std::cout << "a1 == a2 is " << std::boolalpha << operator ==( a1, a2 ) << '\n';

    return 0;

Its output is

a1 = 10
a2 = 10
a3 = 20
a1 == a2 is true
a2 == a3 is false
a1 == a2 is true

Conditionals and logic | Think Java, The result of a relational operator is one of two special values, true or false . 7) is the same as x < 1 && y == 7 boolean evenFlag = (n % 2 == 0); // true if n is even boolean positiveFlag = (x > 0); // true if x is This method takes an integer, n , as a parameter and displays n newlines. What is the complete output? We all know that 1 method should do only 1 thing (Single Responsibility Principle for methods and classes) If your method has a boolean parameter it is highly possible that your method is doing 2 things See the following code examples private string GetAuctionStatus(long auctionID, bool includeClientDetails)

Language tour, void printElement(int element) { print(element); } var list = [1, 2, 3]; // Pass printElement as a parameter. list.forEach(printElement);. You can also assign a function to� The first copy is used by the Select operator (with index parameter = 1) to select the first element of collection i.e. the preprocessed 'Golf' data set. The second copy is used by the second Select operator (with index parameter = 2) to select the second element of the collection i.e. the preprocessed 'Golf-Testset' data set.

[PDF] Operator Overloading, In the first case, the function takes in two parameters, and in the second, the receiver object is one piece of data and the parameter is the other. If we now want to� Value equality means that two objects contain the same value or values. For primitive value types such as int or bool, tests for value equality are straightforward. You can use the == operator, as shown in the following example.

7.7 Expressions, Construction or operator, Associativity The order in which the expressions expr, argument1, …, argumentn are evaluated is not specified. certain class of recursive definitions of non-functional values, as explained in section 8.1. of expr2 if expr1 evaluates to the boolean true, and to the value of expr3 if expr1 evaluates� A boolean (or Bool, or whatever syntax your language uses) is simple construct but can often make code more complex and less straightforward. But why?