## Python 3 turn range to a list

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I'm trying to make a list with numbers `1-1000` in it. Obviously this would be annoying to write/read, so I'm attempting to make a list with a range in it. In Python 2 it seems that:

```some_list = range(1,1000)
```

would have worked, but in Python 3 the range is similar to the `xrange` of Python 2?

Can anyone provide some insight into this?

You can just construct a list from the range object:

```my_list = list(range(1, 1001))
```

This is how you do it with generators in python2.x as well. Typically speaking, you probably don't need a list though since you can come by the value of `my_list[i]` more efficiently (`i + 1`), and if you just need to iterate over it, you can just fall back on `range`.

Also note that on python2.x, `xrange` is still indexable1. This means that `range` on python3.x also has the same property2

1`print xrange(30)` works for python2.x

2The analogous statement to 1 in python3.x is `print(range(30))` and that works also.

Python range to list, I am trying to convert a range to list. nums = [] for x in range (� A Computer Science portal for geeks. It contains well written, well thought and well explained computer science and programming articles, quizzes and practice/competitive programming/company interview Questions.

In Pythons <= 3.4 you can, as others suggested, use `list(range(10))` in order to make a list out of a range (In general, any iterable).

Another alternative, introduced in Python `3.5` with its unpacking generalizations, is by using `*` in a list literal `[]`:

```>>> r = range(10)
>>> l = [*r]
>>> print(l)
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
```

Though this is equivalent to `list(r)`, it's literal syntax and the fact that no function call is involved does let it execute faster. It's also less characters, if you need to code golf :-)

range() to a list in Python, Python | Convert mixed data types tuple list to string list � Shubham__Ranjan. Check out this Author's contributed articles. If you like� range(1, 500) will generate a Python list of 499 integers in memory. So It will use high memory and increased execution speed; xrange(1, 500) function doesn’t generate all numbers at once. It produces number one by one as for loop moves to the next number. Use of range() in Python 3. Python 3’s range() function returns the range object, i.e., It doesn’t generate all numbers at once.

in Python 3.x, the `range()` function got its own type. so in this case you must use iterator

`list(range(1000))`

Python, Python3 Program to Create list Approach #3 : using Python range() We use range() with r1 and r2 and then convert the sequence into list. s = set( {1, 2, 3}) print(convert (s)) chevron_right. filter_none. Output: [1, 2, 3] Approach #2 : using sorted () method. Using sorted () function will convert the set into list in a defined order. The only drawback of this method is that the elements of the set need to be sortable.

Python range() Function Explained with Examples, How to convert a range to a list in Python. Converting a range object to a list results in a list containing the numbers from the range . Output. [0, 1, 2, 3, 4]� The easiest way for your understanding, without using list comprehension, is: mylist = [] for y,x in zip(range(0,4,1),range(0,8,2)): mylist.append(str(x+y)) print mylist.

You really shouldn't need to use the numbers 1-1000 in a list. But if for some reason you really do need these numbers, then you could do:

```[i for i in range(1, 1001)]
```

List Comprehension in a nutshell:

The above list comprehension translates to:

```nums = []
for i in range(1, 1001):
nums.append(i)
```

This is just the list comprehension syntax, though from 2.x. I know that this will work in python 3, but am not sure if there is an upgraded syntax as well

Range starts inclusive of the first parameter; but ends Up To, Not Including the second Parameter (when supplied 2 parameters; if the first parameter is left off, it'll start at '0')

```range(start, end+1)
[start, start+1, .., end]
```

How to convert a range to a list in Python, Turtle() for i in [0, 1, 2, 3]: # repeat four times alex.forward(50) alex.left(90) wn. exitonclick(). It turns out that generating lists with a specific number of integers is a very In fact, these lists are so popular that Python gives us special built-in range� Moving on to the next topic of this article let us see how to input a list in python that holds strings, Accept a List of Strings from the User. Similar to the above program, we have the ability to create a program in Python to accept a list of strings from the user. Take a look at the example below to understand this better.

4.7. The range Function — How to Think like a Computer Scientist , When we convert a range to a list (using the list constructor) the range is evaluated by the constructor and a list object is returned. The nice thing about Python 3� In this tutorial, you can quickly discover the most efficient methods to convert Python List to String. Several examples are provided to help for clear understanding. Python provides a magical join() method that takes a sequence and converts it to a string. The list can contain any of the following object types: Strings, Characters, Numbers.

Does range() return a list or a range object?, In Python 3, range stopped generating lists and became essentially what xrange One way is to turn the ranges into lists before concatenation: To add another alternative to tuple(l), as of Python >= 3.5 you can do: t = *l, # or t = (*l,) short, a bit faster but probably suffers from readability. This essentially unpacks the list l inside a tuple literal which is created due to the presence of the single comma ,.

Discontinuous ranges in Python - All this, Example 3: How range() works with negative step? start = 2 stop = -14 step = -2 print(list(range(start, stop, step))) # value constraint not met print(list(range(start,� [i for i in range(1, 1001)] List Comprehension in a nutshell: The above list comprehension translates to: nums = [] for i in range(1, 1001): nums.append(i) This is just the list comprehension syntax, though from 2.x. I know that this will work in python 3, but am not sure if there is an upgraded syntax as well

• also, `some_list[i] == i+1`, so you probably don't really need a list anyway.
• My +1 for "construct" as it is consistent with other OO languages. The `list(arg)` is understood in other languages as calling a constructor of the `list` class. Actually, it is also the Python case. The debates whether the object is filled during the construction (as in the C++ case) or only during the first automatically called method (as in the Python `__init__()` method) cannot change the basic abstract idea. My view is that the list constructor takes the iterator and fills the list with the returned values.
• Why does it give an error in jupyter notebook and working fine in shell? Error: `'range' object is not callable`
• To be clear, you can still one-line it: `[*range(10)]` works just fine for when you don't need the `range` for any purpose but initializing the `list`. Side-note: My favorite(okay, not really) part of the unpacking generalizations is that empty `set`s now have a literal syntax, `{*()}`, or as I call it, the one-eyed monkey operator. ;-)
• @Earthshaker You must have a typo, like `list(range(1000))()`