Python 3 turn range to a list

python range
python list
python range to list
python range float
how to find the range of a list in python
if in range python
python range tool
for i in range python increment

I'm trying to make a list with numbers 1-1000 in it. Obviously this would be annoying to write/read, so I'm attempting to make a list with a range in it. In Python 2 it seems that:

some_list = range(1,1000)

would have worked, but in Python 3 the range is similar to the xrange of Python 2?

Can anyone provide some insight into this?

You can just construct a list from the range object:

my_list = list(range(1, 1001))

This is how you do it with generators in python2.x as well. Typically speaking, you probably don't need a list though since you can come by the value of my_list[i] more efficiently (i + 1), and if you just need to iterate over it, you can just fall back on range.

Also note that on python2.x, xrange is still indexable1. This means that range on python3.x also has the same property2

1print xrange(30)[12] works for python2.x

2The analogous statement to 1 in python3.x is print(range(30)[12]) and that works also.

Python range to list, I am trying to convert a range to list. nums = [] for x in range (� A Computer Science portal for geeks. It contains well written, well thought and well explained computer science and programming articles, quizzes and practice/competitive programming/company interview Questions.

In Pythons <= 3.4 you can, as others suggested, use list(range(10)) in order to make a list out of a range (In general, any iterable).

Another alternative, introduced in Python 3.5 with its unpacking generalizations, is by using * in a list literal []:

>>> r = range(10)
>>> l = [*r]
>>> print(l)
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

Though this is equivalent to list(r), it's literal syntax and the fact that no function call is involved does let it execute faster. It's also less characters, if you need to code golf :-)

range() to a list in Python, Python | Convert mixed data types tuple list to string list � Shubham__Ranjan. Check out this Author's contributed articles. If you like� range(1, 500) will generate a Python list of 499 integers in memory. So It will use high memory and increased execution speed; xrange(1, 500) function doesn’t generate all numbers at once. It produces number one by one as for loop moves to the next number. Use of range() in Python 3. Python 3’s range() function returns the range object, i.e., It doesn’t generate all numbers at once.

in Python 3.x, the range() function got its own type. so in this case you must use iterator


Python, Python3 Program to Create list Approach #3 : using Python range() We use range() with r1 and r2 and then convert the sequence into list. s = set( {1, 2, 3}) print(convert (s)) chevron_right. filter_none. Output: [1, 2, 3] Approach #2 : using sorted () method. Using sorted () function will convert the set into list in a defined order. The only drawback of this method is that the elements of the set need to be sortable.

Python range() Function Explained with Examples, How to convert a range to a list in Python. Converting a range object to a list results in a list containing the numbers from the range . Output. [0, 1, 2, 3, 4]� The easiest way for your understanding, without using list comprehension, is: mylist = [] for y,x in zip(range(0,4,1),range(0,8,2)): mylist.append(str(x+y)) print mylist.

You really shouldn't need to use the numbers 1-1000 in a list. But if for some reason you really do need these numbers, then you could do:

[i for i in range(1, 1001)]

List Comprehension in a nutshell:

The above list comprehension translates to:

nums = []
for i in range(1, 1001):

This is just the list comprehension syntax, though from 2.x. I know that this will work in python 3, but am not sure if there is an upgraded syntax as well

Range starts inclusive of the first parameter; but ends Up To, Not Including the second Parameter (when supplied 2 parameters; if the first parameter is left off, it'll start at '0')

range(start, end+1)
[start, start+1, .., end]

How to convert a range to a list in Python, Turtle() for i in [0, 1, 2, 3]: # repeat four times alex.forward(50) alex.left(90) wn. exitonclick(). It turns out that generating lists with a specific number of integers is a very In fact, these lists are so popular that Python gives us special built-in range� Moving on to the next topic of this article let us see how to input a list in python that holds strings, Accept a List of Strings from the User. Similar to the above program, we have the ability to create a program in Python to accept a list of strings from the user. Take a look at the example below to understand this better.

4.7. The range Function — How to Think like a Computer Scientist , When we convert a range to a list (using the list constructor) the range is evaluated by the constructor and a list object is returned. The nice thing about Python 3� In this tutorial, you can quickly discover the most efficient methods to convert Python List to String. Several examples are provided to help for clear understanding. Python provides a magical join() method that takes a sequence and converts it to a string. The list can contain any of the following object types: Strings, Characters, Numbers.

Does range() return a list or a range object?, In Python 3, range stopped generating lists and became essentially what xrange One way is to turn the ranges into lists before concatenation: To add another alternative to tuple(l), as of Python >= 3.5 you can do: t = *l, # or t = (*l,) short, a bit faster but probably suffers from readability. This essentially unpacks the list l inside a tuple literal which is created due to the presence of the single comma ,.

Discontinuous ranges in Python - All this, Example 3: How range() works with negative step? start = 2 stop = -14 step = -2 print(list(range(start, stop, step))) # value constraint not met print(list(range(start,� [i for i in range(1, 1001)] List Comprehension in a nutshell: The above list comprehension translates to: nums = [] for i in range(1, 1001): nums.append(i) This is just the list comprehension syntax, though from 2.x. I know that this will work in python 3, but am not sure if there is an upgraded syntax as well

  • also, some_list[i] == i+1, so you probably don't really need a list anyway.
  • @RikPoggi. for example, one might need to supply a list for a plotting function. Sometimes a range will suffice, but a range cannot be concatenated (is immutable), so if you need to add a default starting value to all lists being plotted, that on needs to be turned into a list also.
  • This is definitely the way to go, but a nitpick: this isn't really a "cast"
  • @jterrace changed "cast" to "convert". You're right about it not being a cast... I don't really know what to call it exactly.
  • I would say "construct" or "build" (or possibly "materialise")- as you're not "converting" (as such) a generator to a list, you're creating a new list object from a data source which happens to be a generator... (but s'pose just splitting hairs and not 100% sure what I favour anyway)
  • My +1 for "construct" as it is consistent with other OO languages. The list(arg) is understood in other languages as calling a constructor of the list class. Actually, it is also the Python case. The debates whether the object is filled during the construction (as in the C++ case) or only during the first automatically called method (as in the Python __init__() method) cannot change the basic abstract idea. My view is that the list constructor takes the iterator and fills the list with the returned values.
  • Why does it give an error in jupyter notebook and working fine in shell? Error: 'range' object is not callable
  • To be clear, you can still one-line it: [*range(10)] works just fine for when you don't need the range for any purpose but initializing the list. Side-note: My favorite(okay, not really) part of the unpacking generalizations is that empty sets now have a literal syntax, {*()}, or as I call it, the one-eyed monkey operator. ;-)
  • @ShadowRanger that's how I originally thought about writing it. I decided to be a bit more verbose in order to not confuse new Python users :-)
  • "in this case you must use iterator"? What the heck is that supposed to mean?
  • I am using python 3.7 & tried x=list(range(1000)) but got the error TypeError: 'list' object is not callable
  • @Earthshaker You must have a typo, like list(range(1000))()