How do i check if an Array is filled with a certain value?

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I have array, lets say

arr = [1,0,3,5,1,0]

How do i check if the entire array contains only 0 values ? I know could use for-loop and check each index repeatedly until i reach the end of an array. Like

var onlyZeros = false
if arr.count > 0
{
  for i in(0..<arr.count)
  { 
   if arr[i] == 0
    {
      onlyZeros = true
     }
      else
    {
      onlyZeros = false
     }

   }
}
// do something with status of onlyZeros variable.

But i want to know if there are any faster / easier ways? Since the array sometimes will be very large. And i want this to happen every time a new value is added to the array.Nothing should happen if the array is filled with any other numbers (1s 2s or any other number).

Clarification The function or code should return false if the array is filled with any other number , mixed or repeated.

Eg : [0,0,0,0...] should return TRUE

but [1,1,1,1...] or [2,2,2,2...] or anything else should return FALSE

and [1,2,3,0,0,0...] or anything else should also return FALSE

I searched and found out that

extension Array where Element : Equatable {
    func allEqual() -> Bool {
        if let firstElem = first {
            return !dropFirst().contains { $0 != firstElem }
        }
        return true
    }
}

could return true or false if the entire array is filled with same value.

Edit : I am looking for the fastest method. Thanks.

The simplest way to check that all elements in your array are all zero is to use the Sequence.allSatisfy method and check that each element is equal to zero:

let onlyZeros = arr.allSatisfy { $0 == 0 }

How to Check if an Array Contains a Value in Java Efficiently?, How to check if an array (unsorted) contains a certain value? This is a very useful and frequently used operation in Java. It is also a top voted question on. anyMatch () method takes a predicate, an expression or a function which returns a boolean value. In our case, the predicate compares each element n in the stream to toFind and returns true or false. If any of the element n returns true, found is set to true as well.

To check if array contains all same values , you can create a Set from the array and check if the Set contains a single element.

extension Array where Element: Hashable {
    func allEqual(to value: Element) -> Bool {
        let set = Set(self)
        return (set.count == 1 && set.first == value)
    }
}

In the above code, I've created a computed property allEqual in extension Array.

Example:

let arr1 = [1,0,3,5,1,0]
arr1.allEqual(to: 0) //false

let arr2 = [0, 0, 0, 0]
arr2.allEqual(to: 0) //true

Check if a value is present in an Array in Java, Given an array, the task is to check whether a certain element is present in Repeatedly check until the value is found or the interval is empty. To check if a value exists in an array, we can loop through its elements. However there is another solution! You can use the INDEX () function, native to Excel and in the case of two-dimensional arrays use a combination of the INDEX/MATCH function. However, if the value is not found, Application.Match returns an error.

Do you mean its an empty array without a value?

if its that the case, you can use other pre-defined functions like empty(), isset() to check the array by using if/else statement.

Java Program to Check if An Array Contains a Given Value, Example 1: Check if Int Array contains a given value. public class Contains { public static void main(String[] args) { int[] num = {1, 2, 3, 4, 5}; int toFind = 3;� This method assigns the specified data type value to each element of the specified range of the specified array. Syntax: // Makes all elements of a[] equal to "val" public static void fill (int[] a, int val) // Makes elements from from_Index (inclusive) to to_Index // (exclusive) equal to "val" public static void fill (int[] a, int from_Index, int to_Index, int val) This method doesn't return any value.

JavaScript Array some(): Check If at Least one Element Passes a Test, Caution: Empty arrays. If you call the some() method on an empty array, the result is always false regardless of any condition. For example� 2) Do a linear scan of the sorted array. If the difference between current element and next element is anything other than 1, then return false. If all differences are 1, then return true. Time Complexity: O(nLogn) Method 2 (Use visited array) The idea is to check for following two conditions. If following two conditions are true, then return true.

How to check if array is empty or not, Is it possible to store more than one variable inside a specific array position? What happens if an array's initializer has fewer values than the size of the array? But when they do, it can happen that you’re interested in seeing only one value in the array. You can use Excel’s INDEX function to help with that. For example, LINEST is one of the worksheet functions that will work properly only if you array-enter the formula that contains the function.

8.5 Partially Filled Arrays, In addition, before adding a new item, we must check that there is room in the array's length to be as large as we would ever need, it is almost certain that, if a If an array is full when we try to add an element, we can solve that problem by� The array must be sorted, if Arrays.binarySearch () method is used. In this case, the array is not sorted, therefore, it should not be used. Actually, if you need to check if a value is contained in some array/collection efficiently, a sorted list or tree can do it in O (log (n)) or hashset can do it in O (1). Category >> Array >> Java

Comments
  • let arrayContainZeros = arr.filter { (number) -> Bool in return number == 0 }
  • does this make sense for you?
  • @jagdeepsingh Lemme try it.
  • "I am looking for the fastest method" – any method must traverse through the array until a non-zero element is found, or the end of the array is reached. There is no magic how you can make this faster for large arrays.
  • @MartinR True. There could be several different ways to check for this, and i suppose one of them is faster than the other?
  • This seems to do the job. Thanks , much better than my for-loops !
  • No prob! Yeah and as for how fast it is - since it's built into the Swift standard library, I imagine it's been optimized like crazy, so I don't think you're going to get much faster than this.
  • you both are correct .. different approach ... so dont worry guys
  • @PGDev Wouldn't this return true even arr2 is filled with [1,1,1,1]?
  • @Zyfe3r You said you want to only check if all are same or not right?