## Regular Expression to check if decimal is between two numbers irrespective of number of digits after decimal point

Can you help me with writing a Regular Expression ( I will use this in Pattern.compile in Java)?

My requirement is

Given a decimal, should check if the given decimal is between two numbers, Example: Given Number 1 : 0, Number 2: 50 a) 0 - true b) 51 - false c) 50 - true d) 10.25 - true e) 10.2345 - true

I should verify irrespective of number of digits after decimal point.

It will be tricky to implement the generic solution, so I'll leave here the solution for your example and let you think of a generic solution for it.

Here's your regex: `(([0-4]{1}[0-9]{1})|((50){1}))(\.[0-9]+)*`

To turn it generic you just need to change the first part implementation to the numbers you want to use, you can do it using a loop to concat those groups (this is the first part: `([0-4]{1}[0-9]{1})|((50){1})`

).

**[PDF] Regular Expressions: The Complete Tutorial,** 2. Matching Floating Point Numbers with a Regular Expression . Basically, a regular expression is a pattern describing a certain amount of text. you, you will need to tell that to the regex engine by using word boundaries. Control+A through Control+Z. These are equivalent to �\x01� through �\x1A� (26 decimal). E.g.. To allow numbers with an optional decimal point followed by digits. A digit in the range 1-9 followed by zero or more other digits then optionally followed by a decimal point followed by at least 1 digit: ^[1-9]\d*(\.\d+)?$ Notes: The ^ and $ anchor to the start and end basically saying that the whole string must match the pattern

So I'm not 100% sure I am understanding the question properly, so I can't be 100% sure it will work for all cases, but here is what I have.

([0-9]{2}\.[0-9]{2})|([0-9]*0\b)

a) 0 - true

b) 51 - false

c) 50 - true

d) 10.25 - true

e) 10.2345 - true

If "." is between 2 Numbers or ends with 0.

Here is the example: https://regex101.com/r/295QWt/1

So my other answer is if a number is between 2 different numbers. Actually in this case I don't think regex is that useful. Depending on the language using regex might even be slower.

if(value > min && value < max){return true;}

**7.2. re — Regular expression operations — Python v3.1.5 ,** The solution is to use Python's raw string notation for regular expression in this module let you check if a particular string matches a given regular expression (or if a by the optional pos argument regardless of whether a newline precedes it. the two following regular expression objects that match a decimal number are� I want a regex in JavaScript for validating decimal numbers. It should allow only up to two decimal places. For example, it should allow 10.89 but not 10.899. It should also allow only one period (.). For example, it should allow 10.89 but not 10.8.9.

Use this regex:

^(?:[0-4]?\d(?:\.\d+)?|50(?:\.0+)?)$

**Regex Any Number Of Digits,** We use regular expressions or regexes to do pattern matching when possible. Decimal digits assumed by default (0-9), but a 0 prefix introduces octal digits (0-7 ), and Here we will see two programs to add two numbers, In the first program we Checks wheter the given number starts with a given number Can check the � Regular Expression to regular expression for positive decimal numbers,decimal regular expression validation,regular expression non negative decimal,regex for number with 2 decimal places,regex decimal number c#,regular expression for decimal number with 2 precision,regex to check decimal values,regular expression decimal 2 digits

**Regex Match Exactly 3 Characters,** Hi, I just want to grep for a n digit number followed by M alphabet. how to use Regular Expression (Regex) to allow only Numbers (Digits) and Special In order to build a regular expression to check if String is number or not o r if String A. If there is a decimal point, it requires 2 numeric characters after the decimal point. Below are a few different formats of numbers that you might encounter. Notice how you will have to match the decimal point itself and not an arbitrary character using the dot metacharacter. If you are having trouble skipping the last number, notice how that number ends the line compared to the rest.

**perlre,** If you haven't used regular expressions before, a tutorial introduction is available in perlretut. of three octal digits, matches the character whose native code point is nnn. It doesn't match anything just by itself; it is used only to tell Perl that what Similarly, all the characters that are decimal digits somewhere in the world� With Python, we can single out digits of certain lengths. We extract only 4-digit numbers from a string. We can extract only 1-digit numbers or 2-digits numbers or 3-digit numbers or 4-digit numbers or 5-digits numbers, etc. We do this through the regular expression, regex= "\d{4}" First, we specify that we want the number to be a digit by, \d

Re: Regular expression to allow a number upto 2 decimal places May 27, 2013 07:59 PM | abc13 | LINK i have another regular expression to check for entered values from 0-100. i am looking for an expression only to check for 2 decimal places.

##### Comments

- IMHO, this does not look like a good use for regex.
- Why is
`if (value >= min && value <= max)`

not satisfactory, where`value`

,`min`

and`max`

are`double`

variables? - I'm sorry, thought he downvoted based on opinion, so sorry.
- Regular expressions are for text. You are trying to check numbers. Numbers are not text. Therefore, don't use regular expressions.
`{1}`

is a non sense. Moreover, this regex matches`50.999`

(`>50`

) or`00.0.0.0.0.0.0`

(not a decimal number)- It works as I described, which is why I note I wasn't sure if I understood the question properly.
- The question seems clear to me, they want to match decimal numbers between 0 and 50. Your regex matches
`9990`

but shouldn't and doesn't match`1.123456`

but should. As you can see in the link I gave. - Yeah, I started to get that, but not sure why using regex.