How do I check if input is an integer/string?

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My problem here is I don't know how to insert a rule wherein if a user inputted a number on the string, it will cout a warning saying it's not valid, same with if a user inputted a string/char on the grades. How? I've been trying it but the formula won't work.

int x, cstotal = 100, extotal = 150;

double scorecs, exscore, labtotala, labtotalb, total;

string mystr = "";

cout << "Compute for: " << "\n" << "1. Laboratory Grade " << "\n" << "2. Lecture Grade" << "\n" << "3. Exit" << "\n";
cout << "Please enter a number: ";
cin >> x;
switch (x) {
case 1:

    cout << "Compute for laboratory grade." << "\n";
    cout << "Enter Student Name: ";
    cin >> mystr;


    cout << "Good day, " << mystr << " . Please provide the following grades: " << "\n";
    cout << "CS Score: ";
    cin >> scorecs;

    cout << "Exam Score: ";
    cin >> exscore;


    labtotala = scorecs / cstotal * 0.6;
    labtotalb = exscore / extotal * 0.4;
    total = labtotala + labtotalb;
    cout << "Your Laboratory Grade is " << total * 100 << "\n";
    system("pause");
    break;
case 2:
    cout << "Compute for lecture grade." << "\n";
    cout << "Enter Student Name: ";
    cin >> mystr;
    cout << "Good day, " << mystr << " . Please provide the following grades: " << "\n";
    cout << "CS Score: ";
    cin >> scorecs;
    cout << "Exam Score: ";

    cin >> exscore;
    labtotala = scorecs / cstotal * 0.7;
    labtotalb = exscore / extotal * 0.3;
    total = labtotala + labtotalb;
    cout << "Your Lecture Grade is " << total * 100 << "\n";
    system("pause");
    break;

cin sets a failbit when it gets input of an invalid type.

int x;
cin >> x;

if (!cin) {
    // input was not an integer
}

You can also use cin.fail() to check if the input was valid:

if (cin.fail()) {
    // input was not valid
}

Program to check if input is an integer or a string, cin sets a failbit when it gets input of an invalid type. int x; cin >> x; if (!cin) { // input was not an integer }. You can also use cin.fail() to check if the� Write a function to check whether a given input is an integer or a string. Definition of an integer : Every element should be a valid digit, i.e '0-9'. Definition of a string : Any one element should be an invalid digit, i.e any symbol other than '0-9'. Examples: Input : 127 Output : Integer Explanation : All digits are in the range '0-9'.

How about something like this:

std::string str;
std::cin >> str;

if (std::find_if(str.begin(), str.end(), std::isdigit) != str.end())
{
    std::cout << "No digits allowed in name\n";
}

The above code loops through the whole string, calling std::isdigit for each character. If the std::isdigit function returns true for any character, meaning it's a digit, then std::find_if returns an iterator to that place in the string where it was found. If no digits were found then the end iterator is returned. This way we can see if there was any digits in the string or not.

The C++11 standard also introduced new algorithm functions that can be used, but which basically does the above. The one that could be used instead is std::any_of:

if (std::any_of(str.begin(), str.end(), std::isdigit))
{
    std::cout << "No digits allowed in name\n";
}

How do I check if input is an integer/string?, If an input is an integer or float number, then it can successfully get converted to int or float, and we can say that entered input is number. Given with an input by the user and the task is to check whether the given input is an integer or a string. Integer can be any combination of digits between 0 -9 and string can be any combination excluding 0 – 9. Example Input-: 123 Output-: 123 is an integer Input-: Tutorials Point Output-: Tutorials Point is a string

    cout << "\n Enter number : ";
    cin >> ch;
    while (!cin) {
        cout << "\n ERROR, enter a number" ;
        cin.clear();
        cin.ignore(256,'\n');
        cin >> ch;
    }

Python Check User input is a Number or String, Let's break it down into what we wish to check for: integer; string; float. The type string in Python already has a lot of built-in functions that give� Here we will see how to check whether a given input is integer string or a normal string. The integer string will hold all characters that are in range 0 – 9. The solution is very simple, we will simply go through each characters one by one, and check whether it is numeric or not.

Use the .fail() method of the stream. Something like below:-

   cin >> aString;

  std::stringstream ss;
  ss << aString;
  int n;
  ss >> n;

  if (!ss.fail()) {
   // int;
  } else {
  // not int;
   }

How You Make Sure input() Is the Type You Want It to Be in Python , Check if object is int or float: isinstance() Check if float is integer: is_integer() Check if numeric string is integer If you want to get velues of the� Python input() function always convert the user input into a string. but how to check user input is a number. We can Convert string input to int or float type to check string input is an integer type. also using isdigit() method of string class we can check input string is number or string.

you could use cin.fail() method! When cin fails it will be true and you could us a while loop to loop until the cin is true:

cin>>d;
while(cin.fail()) {
    cout << "Error: Enter an integer number!"<<endl;
    cin.clear();
    cin.ignore(256,'\n');
    cin >> d;
}

Check if a number is integer or decimal in Python, Explore different ways to determine whether a String is numeric or not. but this method can also be modified to check for Integer, Float, Long and For every input that returns true with this method, we can use NumberUtils. My problem here is I don't know how to insert a rule wherein if a user inputted a number on the string, it will cout a warning saying it's not valid, same with if a user inputted a string/char on the

Check If a String Is Numeric in Java, If you want to check whether a Python string is an integer, you can try casting to an int with int() and catching the ValueError if it's not an integer: The Integer class has a number of static methods for parsing strings. For the case where we want to check if if a string contains a valid integer we can use the method Integer.parseInt() and catch the exception that is thrown when the number cannot be parsed.

Testing whether a Python string contains an integer — tdhopper.com, Example 1: Check if a string is numeric. public class Numeric { public static void main(String[] args) { String string = "12345.15"; boolean numeric = true;� If you are creating your own custom exception class, then use regex to check if the input string is an integer or not. private final String regex = "[0-9]"; Then, check if the input follows the regex pattern.

Java Program to Check if a String is Numeric, How to check if input is an integer or string (python). [deleted]. I want to take an input from the user like this. text = input("Enter Text") and then I want to have an if � Enter a number : 782 Integer. Explanation: In this code, we have taken the value of a number in a string called checkint after initialization we will calculate its length. For each character, we will check if it is a digit or not. If it is not a digit it will execute the if statement and the value of count will be 1.

Comments
  • What part of the rule is giving you trouble? How to implement the detection, control flow, branching? If it's just a matter of detecting if a string is a number, you could loop through each character and call isdigit.
  • you need to be more specific as to what you are looking for. Post less code if possible.
  • So will this check whether or not an int is inside of the input? if so will you please explain your code?
  • @DylanLittle Updates my answer trying to explain what it does, and with links to references. Also added a "better" solution when using C++11 or later.
  • ahhh so much better. I can see what's going on now.