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So basically I have an array with the following sample input:

10.2    
20.8    
30.1    
28.7    
43.7    
-10.4    
0.0    
8.0    
30.4    
30.0

and I want to copy only elements that are >=30 into another array.

This is the code I currently have, but i'm kind of stuck on how to continue. Any help would be highly appreciated! the double array "reallyWarm" is the array where the copy is being made on

Scanner scanner = new Scanner(System.in);
double[] temperatures = new double[10];
for (int i = 0; i < 10; i++){
    temperatures[i] = scanner.nextDouble();
}
double[] reallyWarm;

You should use if (temperatures[i] >= 30.0) to check for the elements that are greater or equal to 30.0.

Try this:

double[] reallyWarm;
int t = 0;    

for (int i = 0; i < temperatures.length; i++) {
    if (temperatures[i] >= 30.0) {
        t++;    // count elements >= 30.0
    }
}
reallyWarm = new double[t];
int j = 0;
for (int i = 0; i < temperatures.length; i++) {
    if (temperatures[i] >= 30.0) { 
        reallyWarm[j] = temperatures[i];    
        j++;
    }
}

System.out.println(Arrays.toString(reallyWarm));

If you're using java 8 you can achive this task with just one line of code:

double[] reallyWarm;
reallyWarm = Arrays.stream(temperatures).filter(e -> e >= 30.0).toArray();
System.out.println(Arrays.toString(reallyWarm));

Output:

[30.1, 43.7, 30.4, 30.0]

Update for '... a new line after each element...':

for(int i=0; i<reallyWarm.length; i++) {
    System.out.println(reallyWarm[i]);
}

You can use a for loop to traverse through the array and print each element on a new line.

Replacing Numpy elements if condition is met, >>> import numpy as np >>> a = np.random.randint(0, 5, size=(5, 4)) >>> a array ([[4, 2, 1, 1], [3, 0, 1, 2], [2, 0, 1, 1], [4, 0, 2, 3], [0, 0, 0, 2]]) >>> b = a < 3 >>> b� If M2>0 then copy M2 and paste it into D2. Continue doing this until every cell in "M" has been evaluated based on row count. Next, if I end up copying and pasting based on meeting condition then I want to also change Item Status in column F to say "FALSE". Hope someone can help I'm at the tail end of a large project being completed.

Using JAVA 8 and higher version:

double temperatures[] = { 10.2, 20.8, 30.1, -10.4, 30.4, 0.0, 30.0, 43.7 };
double reallyWarm[] = Arrays.stream(temperatures).filter(d -> d >= 30).toArray();

How to replace elements in a NumPy array if a condition is met in , Replacing elements in a NumPy array if a condition is met replaces each element in the array that satisfies the given condition with another value. The result is a list of the elements in A that satisfy both conditions. Be sure to specify each condition with a separate statement connected by a logical operator. For example, you cannot specify the conditions above by A(2<A<9), since it evaluates to A(2<A | A<9). Next, find the elements in A that are less than 9 and even numbered.

Using Java8 Stream :

public void main(String[] args) {
    Double arr[] = { 10.2, 20.8, 30.1, -10.4, 30.4, 0.0, 30.0, 43.7 };
    List<Double> result = Arrays.asList(arr).stream().filter(k -> k >= 30).collect(Collectors.toList());
    System.out.println(result);
}

Find Array Elements That Meet a Condition, Some problems require information about the locations of the array elements that meet a condition rather than their actual values. In this example, you can use� Select the column you will copy cells if column contains specific value or text, and then click the Data > Filter. 2 . Now click the arrow in the left side of first cell of the selected column, and then click the Text Filters > Contains from the drop down list.

How to replace the elements of a matrix using the conditions if,else , Copy to Clipboard for non-scalar conditional, the IF statement will pass if and only if all of the elements in conditional are true or non-zero. What should be done if each individual element must be sorted through but there are thousands of elements if any of these conditions is not satisfied, T equals the elements of M+1. The original list is : [3, 5, 1, 6, 7, 9] The number of odd elements: 5 Method #3 : Using reduce() + lamda reduce function does the task of accumulation as the sum function in the above used methods. lambda is used to perform the condition against which result needs to be checked.

VBA to Copy and Paste Rows if Condition is Met, VBA Code to Copy and Paste specific rows from one sheet to another sheet when condition Duration: 10:44 Posted: 13 May 2017 VBA to Copy and Paste Rows if Condition is Met - Excel VBA Example by ExcelDestination - Duration: Transfer Specific Worksheet Range Data from one worksheet to another based on condition

Conditional visibility, Select an element, static or dynamic, inside a Collection list or on a Collection page that you want to only show when a specific condition is met; Press D to open� Here’s the issue: Excel formulas cannot send data to other cells, sheets, etc. They can only receive data. So, cell “whatever” on Sheet 2 would have to hold a formula like this: =IF(Sheet1!A1=&quot;cat&quot;,Sheet1!B1,&quot;&quot;) and cell “whatever” on Sheet 3 woul

Comments
  • If you are just learning loops and arrays, use a first loop to count the numbers of elements > 30. Then create an array with the right length (you just found it). Then use a second loop to copy all elements > 30 to the new array.
  • I suggest you use java's collection framework arraylist, as it can grow dynamically.
  • I'll make sure to try it, thanks @JBNizet!
  • @Programmingboi123 If my solution solved your problem consider it accepting by clicking a left right button , where it will help to other developers in the community
  • it's good, but i really want a new line after each element instead.
  • you can use a for loop to traverse through the array and print each element on a new line. updating the answer...