## How do I get the numbers in a String and then calculate the average of them?

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So I am currently experimenting with Streams and I try to calculate the average of the numbers in the String "589 Hello 56" in a stream. My approach is like this:

List <int[]> experiment = a.stream() .map(x -> x.replaceAll("[^0-9]", "").split("\\D+")) .map(x-> Arrays.asList(x).stream().mapToInt(Integer::parseInt).toArray()) .collect(Collectors.toList());

So I first get a Stringarray with "589 56", because I split the String. But after that I try to convert everything to an Integerarray to get the average more easily and it doesn´t work, because the "589 56" converts to "58956". Does anyone have a better approach? Thanks in advance.

To calculate the average using stream, you need :

double average = Arrays.stream(a.split("\\D+")) // split with non degits ["589", "56"] .mapToInt(Integer::valueOf) // convert each string to integer [589, 56] .average() // OptionalDouble .getAsDouble(); // double 322.5

Or if you are not sure that your string can contain any number, then you need to avoid this with :

.orElse(0);

or

.orElseThrow(() -> new IllegalArgumentException("no number in the string"));

instead of `.getAsDouble();`

Or if you want to go deeper and for example avoid cases where the numbers can be in front of any non digits for example `a45 Hello 9a7`

where the numbers can be a part of a word, in this case you can go with Pattern and Matcher with this regex `\b\d+\b`

, which use work boundary, like so :

double average = Pattern.compile("\\b\\d+\\b") .matcher(a) .results() .map(MatchResult::group) .mapToInt(Integer::valueOf) .average() .orElse(0);

This last solution can work only from Java9+.

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Try this one

String s = "589 Hello 56"; OptionalDouble average = Arrays.stream(s.split("\\D+")) .mapToInt(Integer::parseInt)// or maybe .mapToDouble(Double::parseDouble) .average();

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The call to replaceAll strips all non-numeric characters from the string including the spaces. This converts '589 Hello 56' into '58956'. Try using `replaceAll("[^0-9\\s]", "")`

.

You will also need to split on the separator characters (i.e., the spaces) instead of the digits.

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##### Comments

- So you want to fetch all numbers from the string, then calculate the average of them?
- The number gathering is a different operation...not sure why you would like to include it in any-stream-processing. Once you have those, you can stream the list and do whatever you want with them.
- @ marstran Yes I want to fetch all the numbers. So in this case it would be "589" and "56". And than I want to calculate the average of these two which is (589+56)/2 = 322.5
- Try this
`Arrays.stream(s.split("\\D+")) .mapToInt(Integer::parseInt) .average();`

*FYI:*`[^0-9]`

and`\D`

is the same thing, so you first remove all non-digit characters, then try to split on the now non-existent non-digits, which means that split will do thing.- Well my IDEA sadly says: "Illegal escape character in string literal"
- Thanks for the update but sadly my compiler says: Exception in thread "main" java.lang.NumberFormatException: For input string: "123456 789" when i try to convert it into an integerarray