Can someone help me understand the output of the following code?

I've tried but every time I get a different weird output. Ideally, it should print 0, 1, 2, 3, 4 and come out of the loop but it doesn't happen.

function foo(iteration) {
    if (iteration === 5) {
        return;
    }
    for (let i = 0; i < 5; i++) {
        console.log(i);
        foo(iteration + 1);
    }
}

foo(0);

You don't need to use recursion AND a loop. Just the loop itself will work.

for (let i = 0; i < 5; i++) {
  console.log(i);
}

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To understand the current output, start by walking through your function step by step. It helps me to write it out and keep track of the values.

  1. iteration starts at 0

  2. it starts the for loop

  3. i is 0 at this point.

  4. its logged to the console.

  5. foo is called again with value of 1

  6. iteration is still less than 5

  7. a new for loop starts. (step 2)

  8. i is 0, this is a brand new loop since it's inside of a new instance of foo

In each iteration of the for loop, you call foo and while iteration is less than 5 you start a new for loop.

Here is an example of a function that does what you like:

function foo(iteration) {
      while(iteration < 5) {
            console.log(iteration)
            iteration++
     }
}

foo(0)

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Since you are already using recursion, there is no need to have that loop. Something like this should work:

function foo(iteration) {
  if (iteration < 5) {
    console.log(iteration);
    foo(iteration + 1);
  }
}

foo(0)

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Comments
  • It's because the loop inside recursion call of the function. You can just remove the for loop and leave the rest of the code. It will print the numbers as you wish.