## Can someone help me understand the output of the following code?

I've tried but every time I get a different weird output. Ideally, it should print 0, 1, 2, 3, 4 and come out of the loop but it doesn't happen.

```function foo(iteration) {
if (iteration === 5) {
return;
}
for (let i = 0; i < 5; i++) {
console.log(i);
foo(iteration + 1);
}
}

foo(0);
```

You don't need to use recursion AND a loop. Just the loop itself will work.

```for (let i = 0; i < 5; i++) {
console.log(i);
}```

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To understand the current output, start by walking through your function step by step. It helps me to write it out and keep track of the values.

1. `iteration` starts at `0`

2. it starts the for loop

3. `i` is `0` at this point.

4. its logged to the console.

5. `foo` is called again with value of `1`

6. `iteration` is still less than `5`

7. a new for loop starts. (step 2)

8. `i` is `0`, this is a brand new loop since it's inside of a new instance of `foo`

In each iteration of the for loop, you call `foo` and while `iteration` is less than `5` you start a new for loop.

Here is an example of a function that does what you like:

```function foo(iteration) {
while(iteration < 5) {
console.log(iteration)
iteration++
}
}

foo(0)```

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Since you are already using recursion, there is no need to have that loop. Something like this should work:

```function foo(iteration) {
if (iteration < 5) {
console.log(iteration);
foo(iteration + 1);
}
}

foo(0)```

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