Flask app getting error of "could not locate flask application. .....FLASK_APP environment variable" for Flask Migrate

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I have a file db_table.py that looks like:

from flask import Flask
from flask_sqlalchemy import SQLAlchemy
from flask_migrate import Migrate

app = Flask(__name__)
app.config['SQLALCHEMY_DATABASE_URI'] = 'mysql://root:password@localhost/mydb'

db = SQLAlchemy(app)
migrate = Migrate(app, db)
.....db tables....

When I try to run:

flask db init

I get:

Error: Could not locate Flask application. You did not provide the FLASK_APP environment variable.

I tried first manually setting FLASK_APP var, by doing set FLASK_APP=app.py then running flask db init again, but that didn't resolve the issue.

The flask command line argument needs to know what module to locate the current Flask app instance in.

Set FLASK_APP as an environment variable:

export FLASK_APP=db_table.py

before running your flask command-line app.

See the Command Line Interface documentation:

For the flask script to work, an application needs to be discovered. This is achieved by exporting the FLASK_APP environment variable. It can be either set to an import path or to a filename of a Python module that contains a Flask application.

You can also set the variable per command by setting it on the same command line:

FLASK_APP=db_table.py flask db init

Application Errors — Flask Documentation (0.12.x), from raven.contrib.flask import Sentry sentry = Sentry(app, value needs to be replaced with the DSN value you get from your Sentry installation. Afterwards� As of Flask 1.1.0, this error handler will always be passed an instance of InternalServerError, not the original unhandled error. The original error is available as e.original_exception . Until Werkzeug 1.0.0, this attribute will only exist during unhandled errors, use getattr to get access it for compatibility.

Some problem will can happen if you use DispatcherMiddleware (werkzeug.wsgi). Change return object from app_dispatch to app without app_dispatch for migrate time.

This is a rare case, I hope someone helps...

Handling Application Errors — Flask Documentation (2.0.x), 0, this attribute will only exist during unhandled errors, use getattr to get access it for compatibility. @app.errorhandler(InternalServerError) def handle_500� I had this same problem, however in my case, PROPAGATE_EXCEPTIONS was on, and the exceptions were being swallowed anyway. I was just getting 500 errors with no relevant logs. The problem ended up being caused by werkzeug.debug.DebuggedApplication. I was using it in the usual way in init.py: app = DebuggedApplication(app, evalex=True).

You can refer to this documentation to learn how to set environment variables in Flask.

Unix Bash (Linux, Mac, etc.):

$ export FLASK_APP=hello
$ flask run

Windows CMD:

> set FLASK_APP=hello
> flask run

Windows PowerShell:

> $env:FLASK_APP = "hello"
> flask run

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Why and how to handle exceptions in Python Flask, Learn more in this lesson in Python exception handling and how to do it in a secure manner. Catching exceptions in app.models.threatstack. I'll walk through a If you didn't get a successful response, you raise an error. from flask import Flask app= Flask(__name__) @app.route('/') def home(): return "This is the homepage" if __name__=="__main__": app.run(debug=True) I am using Python 3.6 and IDLE on Windows 10. The problem is I keep getting the following error:

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  • if your application lives in db_table.py file then you should expert this file: export FLASK_APP=db_table.py
  • and test your env: printenv FLASK_APP
  • set FLASK_APP=db_table.py for Windows and $env:FLASK_APP = "db_table.py" for powershell