How to push all objects of array2 to array1

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I want to push just the objects of array2 into array1.

array1 = [{name:'first'}, {name:'second'}];
array2 = [{name:'third'}, {name:'fourth'}, {name:'five'}];

// Desired result
array1 = [{name:'first'}, {name:'second'}, {name:'third'}, {name:'fourth'}, {name:'five'}];

copyArray() {
   this.array1.push( this.array2 ); 

When I run the copyArray function, the array2 itself was instead copied and not the objects. I got this:

Unwanted result

array1 = [{name:'first'}, {name:'second'}, [{name:'third'}, {name:'fourth'}, {name:'five'}]];

Can someone help me to fix this.

The spread operator (...) makes this easy.

this.array1 = [...this.array1, ...this.array2];

Array.prototype.concat(), const array3 = array1.concat(array2);. 4. . 5 from the original arrays. Elements of the original arrays are copied into the new array as follows:. The push() method adds new items to the end of an array, and returns the new length. Note: The new item(s) will be added at the end of the array. Note: This method changes the length of the array. Tip: To add items at the beginning of an array, use the unshift() method.

Try like this:

Working Demo

  copyArray() {
    this.array2.forEach(item => {
    this.array2 = [];

2 Ways to Merge Arrays in JavaScript, Merge Array with Push 🤔; Browser Support; Resources function combineArray (array1, array2) { return [].concat(array1, array2); } const isArray = [1, 2, 3]; const� The push method appends values to an array. push is intentionally generic. This method can be used with call () or apply () on objects resembling arrays. The push method relies on a length property to determine where to start inserting the given values.

It's unclear what you attempted to do. If you want to concatenate two arrays, just use .concat:

const arr1 = [1, 2, 3];
const arr2 = [4, 5];
const arr3 = arr1.concat(arr2);

console.log('arr1', arr1); // unchanged
console.log('arr2', arr2); // unchanged
console.log('arr3', arr3);

Appending One Array to Another - Perl Cookbook [Book], You want to join two arrays by appending all the elements of one to the end of the other. Solution. Use push : # push push(@ARRAY1, @ARRAY2);� Step 4 — Reformatting Array can be used to iterate through objects in an array and, in a similar fashion to traditional arrays, modify the content of each individual object and return a new array. This modification is done based on what is returned in the callback function.

Proper Angular approach is to use combination, you can either use ForkJoin or Concat, more details on official site.

Arrays, Methods push and unshift can add multiple elements at once: let fruits let arr = new Array ( 2 ) ; // will it create an array of [2] ? alert ( arr [ 0 ] )� array1 = array1.filter{ $0.arrayInsideOfArray1.contains(array2[0]) } Code above works but I'm trying to check if all the elements of $0.arrayInsideOfArray1 match with all the elements of array2 not

Proper way is to use the concat function:

array2 = array1.concat(array2);

It can be use to merge two or more arrays like

var result = array1.concat(array2, array3, ..., arrayN);

array_merge - Manual, Merges the elements of one or more arrays together so that the values of one are appended to the end of the previous one. Variable list of arrays to merge. array ArrayMergeKeepKeys ( array array1 [, array array2 [, array ]]) array_ product � array_push � array_rand � array_reduce � array_replace_ recursive� I am trying to push an object into an array of objects but only if the particular object is not present in the array. If it is present the object should be updated. I am required to do this with es5 Below is what I have tried var database = requir

CoffeeScript Cookbook � Concatenating Arrays, If you want to merge two arrays without creating a new object, you can use the following technique: array1 = [1, 2, 3] array2 = [4, 5, 6] Array::push.apply array1,� array_push() treats array as a stack, and pushes the passed variables onto the end of array.The length of array increases by the number of variables pushed. Has the same effect as:

Does it mutate?, The every() method tests whether all elements in the array pass the test var array1 = [1, 2, 3, 4]; // fill with 0 from position 2 until position 4 https://developer. 3]; var firstElement = array1.shift(); console.log(array1); // expected output: Array [ 2,� Definition and Usage. The array_push() function inserts one or more elements to the end of an array. Tip: You can add one value, or as many as you like. Note: Even if your array has string keys, your added elements will always have numeric keys (See example below).

The Complete Reference for JavaScript Arrays, var array = [1,2,3,4,5]var doubledArray = Array.from(array, (value, index) => value +value);doubledArray; [2,4,6,8,10]; array1.concat[array2, arr3, arr4, . arrN] The push method returns the new length of the array after the item is pushed. This method creates a string by concatenating all the elements of the array. If the field is absent in the document to update, $push adds the array field with the value as its element. If the field is not an array, the operation will fail. If the value is an array, $push appends the whole array as a single element. To add each element of the value separately, use the $each modifier with $push.

  • I did that, but array2 was deleting content of array1...
  • Does this answer your question? JavaScript: How to join / combine two arrays to concatenate into one array?
  • just try this.array1.concat(this.array2).
  • About spread operator, you can use it also inside push: array1.push(...array2);
  • Another thing to keep in mind is that push and concat don't change the reference and a lot of Angular change detection relies on variable reference changes for performance reasons. So, the value result of array1.push(...array2) and my answer above is the same. But mine also changes the reference, making it more likely to be picked up by Angular change detection.
  • I have actually tried this before but I was getteing red line under the array2. It was just an editor problem. However, this works thatnks, I think I need the change editor.
  • Just one observation: ...this.array1, ...this.array2 is different from ...this.array2, ...this.array1 when using the spread operator with objects, the order determines the result when they have a key with same name with different values
  • Can you explain what this: this.array2 = []; does?
  • I assumed you added this.array2.splice(); to clear array2. this.array2 = []; simply make this array empty
  • Thanks alot! I used to like your answers.
  • You are welcome. The other answer is obviously better :)