## Java: Generator a random value then add 1 to the value in another variable

how to generate random numbers in java within range

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java random number between 0 and 1

java random number between 1000 and 9999

I know smilar questions have been asked about this, however non of the ones i have seen so far seems to help me in the way i need it to.

I want to be able to add 1 to the random value i get.

Random rand = new Random(); rand.nextInt( 200); Query query = FirebaseDatabase.getInstance().getReference("Level").orderByKey() .startAt(String.valueOf(rand)).endAt(String.valueOf(rand));

the `endAt`

need to be +1 of the rand value

if i do `rand +1`

I get the error:

Operator '+' cannot be applied to Java.Random

Anyone have any tips for me?

Thanks guys, it helped me figure out what i did wrong:

**My Answer:**

Random rand = new Random(); int x = rand.nextInt(200); startAt(String.valueOf(x)).endAt(String.valueOf(x++));

**How to Generate Random Number between 1 to 10,** Since random() method always return a value between 0 and 1, casting into an int will always produce a zero. Now if you multiply zero by any other number, you � 1) java.util.Random. For using this class to generate random numbers, we have to first create an instance of this class and then invoke methods such as nextInt (), nextDouble (), nextLong () etc using that instance. We can generate random numbers of types integers, float, double, long, booleans using this class.

You can do it as follows:

Query query = FirebaseDatabase.getInstance() .getReference("Level") .orderByKey() .startAt(String.valueOf(rand)) .endAt(String.valueOf(rand.nextInt(200)+1));

**Random Number Generation in Java,** Learn how to create random numbers in Java using the math and random classes Java provides the Math class in the java.util package to generate random numbers. To get the max value included, you need to add 1 to your range In addition to ints(), some other frequently used methods that Java 8� It works as Math.random () generates a random double value in the range [0.0, 1.0). When we multiply it by ((max - min) + 1), the lower limit remains 0 but the upper limit becomes (max - min, max - min + 1). Now on casting it with an int, the range becomes [0, max - min] and on adding min, the range becomes [min, max].

There are multiple possibilities to achieve this:

You could do `startAt(rand++)`

or `endAt(++rand)`

Or `rand+=1`

Or you make a variable for just holding the correct value for endAt

int randStart = random(); int randEnd = randstart+1;

**How to generate random numbers in Java,** random() * (max - min + 1) + min to generate values with the min value inclusive and the max exclusive… Note: this method can only be used if you need an� Now - two issues - you are declaring a new int each time you generate a random number - you should move the declaration out of the loop and only set the value in the loop. So for your question - if you declare a variable ( say: int sum - 0; ) outside the loop, and the right after to generate and set the random number in the loop you add that to

**Java Random Generation - JavaBitsNotebook.com,** These created values are not truly "random" because a mathematical formula is used to generate the values. The "random" To generate random integer numbers between 1 and 30 inclusive: int number = (int) Add 1 to get 1.0 to 30.99997. Yes, you can put the random generator in a utility class, in a static method. That way you can call MyUtilities.randomInt(1, 10) and get the required “random” number. You can read a nice discussion about different ways to get “random” numbers here; if you search you will find lots of people ask that sort of question.

**Generate a random number in java in 3 ways,** Random number means a different number every time the application is executed. In order to generate a number between 1 to 50, we multiply the value and add 1 to the result which will make the range of the generated value as 1 to 50. Random Number Generation with Java Random number can be generated using two ways. java.util.Random class is used to generate random numbers of different data types such as boolean, int, long, float, and double. An object of Random class is initialized and the method nextInt (), nextDouble () or nextLong () is used to generate random number.

**Algorithm to generate N random numbers between A and B which ,** If you have 5 random variables which are each uniformly distributed on [-1,1], their sum has average value 0, so it can't be the constant 1. Some other answers � The counter controlled repetition would be appropriate for the calculating sum of first 100 positive integers because the number of repetitions is known in advance--the program that performs this task could use a while repetitions statement with a counter variable that takes on the values of 1 to 100. The program could then add the current

##### Comments

- Can you show us how you initialize the
`Random`

? What does`String.valueOf(rand)`

create? Isn't that a`toString()`

-like representation of the instance`rand`

? Why don't you do anything like a real random`int`

, e.g.`String.valueOf(rand.nextInt() + 1)`

? `Random`

is not a number, it's a generator. You need to call`nextInt()`

to make it generate a number. So:`String.valueOf(rand.nextInt())`

and`String.valueOf(rand.nextInt() + 1)`

.`Random rand = new Random();`

`rand.nextInt( 200);`

- it is not allowing me to do the addition operator or any normal operation on the random value