How to create a DateTime equal to 15 minutes ago?

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I need to create a DateTime object that represents the current time minus 15 minutes.

import datetime and then the magic timedelta stuff:

In [63]: datetime.datetime.now()
Out[63]: datetime.datetime(2010, 12, 27, 14, 39, 19, 700401)

In [64]: datetime.datetime.now() - datetime.timedelta(minutes=15)
Out[64]: datetime.datetime(2010, 12, 27, 14, 24, 21, 684435)

In Python, how do I make a datetime that is 15 minutes from now? 1 , How to create a DateTime equal to 15 minutes ago? what's the best way to do this? share. possible duplicate of How to create a DateTime equal to 15 minutes ago? – Marc B Mar 1 '11 at 17:40. 3. Presumably if it's March 1 today, you want to get March 1 no

 datetime.datetime.now() - datetime.timedelta(minutes=15)

How to subtract minutes from a datetime in Python, datetime object to to return a datetime object minutes earlier than the original datetime object. initial_datetime = datetime.datetime(2020, 1,� Python has a module named datetime to work with dates and times. Let's create a few simple programs related to date and time before we dig deeper.

This is simply what to do:

datetime.datetime.now() - datetime.timedelta(minutes = 15)

timedeltas are specifically designed to allow you to subtract or add deltas (differences) to datetimes.

7.1. datetime — Basic date and time types — Python v3.2.6 , Attributes: year, month, day, hour, minute, second, microsecond, and tzinfo. The smallest possible difference between non-equal timedelta objects, Note that tzinfo=None can be specified to create a naive datetime from an aware 29, 43, 79043) # GMT +1 >>> datetime.utcnow() datetime.datetime(2007, 12, 6, 15, 29,� Examples. The following example uses the AddMinutes method to add a number of whole and fractional values to a date and time.. using namespace System; void main() { DateTime dateValue(2013, 9, 15, 12, 0, 0); array<Double>^ minutes = { .01667, .08333, .16667, .25, .33333, .5, .66667, 1, 2, 15, 30, 17, 45, 60, 180, 60 * 24 }; for each (Double minute in minutes) Console::WriteLine("{0} + {1

from datetime import timedelta    
datetime.datetime.now() - datetime.timedelta(0, 900)

Actually 900 is in seconds. Which is equal to 15 minutes. `15*60 = 900`

Mastering Python Datetime (With Examples) � Pylenin, A simple guide to working with python datetime objects and timezones in Python. Lets say we want to create a date object for January 1 2017 . What is the date and time 2 days 3 hours and 15 minutes ahead from now? **String formatting code that is equivalent to the string** Let's convert a datetime� Example: SQLStatment in SQLSEVER. Field Date 2012-10-12 15:45:53.000 2012-10-12 15:35:53.000 2012-10-12 15:35:53.000. Now is 2012-10-12 15:45:53.000. I would like to compare field date and now date if date field smaller then 10 minutes then Now date, So i want to select those record to display.

I have provide two methods for doing so for minutes as well as for years and hours if you want to see more examples:

import datetime
print(datetime.datetime.now())
print(datetime.datetime.now() - datetime.timedelta(minutes = 15))
print(datetime.datetime.now() + datetime.timedelta(minutes = -15))
print(datetime.timedelta(hours = 5))
print(datetime.datetime.now() + datetime.timedelta(days = 3))
print(datetime.datetime.now() + datetime.timedelta(days = -9))
print(datetime.datetime.now() - datetime.timedelta(days = 9))

I get the following results:

2016-06-03 16:04:03.706615
2016-06-03 15:49:03.706622
2016-06-03 15:49:03.706642
5:00:00
2016-06-06 16:04:03.706665
2016-05-25 16:04:03.706676
2016-05-25 16:04:03.706687
2016-06-03
16:04:03.706716

AddYears Method datetime AddYears(int value) If I want to create a DateTime object that represents a date in the past, I still use the appropriate Add method, but I supply a negative number. So in the following example, I create a DateTime object that is 12 days in the past:

Active 11 days ago. i need to find the records 10 min before system current datetime. This works if I surround '10 minutes' in quotes like so.

Asked 11 years, 5 months ago. equal or greater. What you want is something like this: minutes and seconds. DateTime.Today would be more correct for the OPs

Equals(DateTime, DateTime) Returns a value indicating whether two DateTime instances have the same date and time value.. Equals(DateTime) Returns a value indicating whether the value of this instance is equal to the value of the specified DateTime instance.

Comments
  • Related question: stackoverflow.com/questions/100210/…
  • NB, in Python 3 you'll need to pass the timezone to now() to avoid an error about subtracting offset-naive and offset-aware datetimes: datetime.datetime.now(datetime.timezone.utc)
  • @nornagon that’s not at all applicable here; it doesn’t matter if the datetime object is aware or naive, subtracting a timedelta works regardless.
  • Your import doesn’t match the code; you import timedelta but then use datetime attributes. Either import the module, or add the type.
  • This is no different from much older answers here.