Calculate time difference between each transaction using python

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I'm trying to find out the time difference between each transactions for each unique machine_id right now but have trouble calculate the time difference for each group respectively. event_date has a type of integer while event_time has a type of object

Make a datetime column as -

convert event_date to datetime format

df['event_date'] = pd.to_datetime(df['event_date'], 
                                  format='%Y%m%d',
                                  errors='ignore')\
                                  .astype(str)

combine date and time column

df['event_datetime'] = pd.to_datetime(\
        df['event_date'] + ' '+ df['event_time'])

then find difference on this column by grouping on matching_id

df.groupby('matching_id')['event_datetime']\
       .apply(lambda x: x.max() - x.min())

How to calculate time difference in between rows using loop in , A little bit messy aproach ( but it works atleast), but running difference wasnt working for me, so here you go: df = pd.read_csv('test.csv', sep = "� time delta() arithmetic is not supported for date time.time() objects; if you need to use offsets from an existing date time.time() object, just use date time.datetime.combine() to form a date time.date time() instance, do your calculations, and 'extract' the time again with the .time() method.

May be it might help you:

In [1]: time.time()
Out[1]: 1347517739.44904

In [2]: time.strftime("%Y-%m-%d %H:%M:%S", time.gmtime(time.time()))
Out[2]: '2012-09-13 06:31:43'

replace "%Y-%m-%d" with your date and "%H:%M:%S" with your time And then you can do the same with next transaction and try to subtract them.

Python Tutorial, Because there are quiet different types of date and time format. Unlike some other languages Duration: 3:18 Posted: Aug 5, 2019 from datetime import datetime def time_difference(time_start, time_end): '''Calculate the difference between two times on the same date. Args: time_start: the time to use as a starting point time_end: the time to use as an end point Returns: the difference between time_start and time_end.

diff_ser = pd.to_datetime(df['event_date'].astype(str) + ' ' + df['event_time'],\
                          format= '%Y-%m-%d %H:%M:%S').diff()

PS: you can do something like this. haven't tested it. it may have error.

How to calculate a time difference in minutes in Python, Subtract one datetime object from another to return a timedelta object. Call timedelta. total_seconds() with timedelta as the object from the previous step, to return the total seconds between the two datetime objects. Divide the result by 60 to return the time difference in minutes. C:\programs\time>pep8 --first example8.py C:\programs\time>python example8.py Difference: 37 days, 0:05:00.518000 Days: 37 Microseconds: 518000 Seconds: 300

A Complete Guide to Python DateTime Functions, This tutorial explains python datetime module in detail and how it is used python datetime module and how it is used to handle date, time and Calculate future or past dates; Difference between Two Dates; How to made multiple transactions in the last 6 months; Extracting dates from timestamp values. Contribute your code and comments through Disqus. Previous: Write a Python program to convert a date to Unix timestamp. Next: Write a Python program to convert two date difference in days, hours, minutes, seconds.

Python program to find number of days between two given dates , This solution requires more than O(1) time. A Better and Finally return the difference between two counts. filter_none. edit To store number of days in all months from last_page Python program to calculate age in year. Python Basic: Exercise-14 with Solution. Write a Python program to calculate number of days between two dates. Python datetime.date(year, month, day) : The function returns date object with same year, month and day. All arguments are required. Arguments may be integers, in the following ranges: MINYEAR <= year <= MAXYEAR; 1 <= month <= 12

Solved: How to calculate time difference among consecutive , Solved: Hello I have a table with transactional data so, each row is a transactions. I need to calculate the time difference between two� Even I searched in Google a lot, I couldn’t find an easy method to calculate hours between two times in Python. Finally, after a long time of research I got some code which helped to find days between two dates, then I sat for sometime and wrote a script which gives hours minutes and seconds between two dates.

Comments
  • "event_time has a type of object." That's the dtype (data type) of the Pandas column. It is used for any type of Python data which is not a number or a string. If you extract just one element from the event_time column, what data type is it?
  • the data type is string
  • hi, can you elaborate on find the difference on this column by grouping on mathicn_id. and also since event_date has a type of int and event_time has a type of str, I think I cannot simply add them together. However, if I add str(), it also does not work
  • hi, I have edited the answer, the event_date will be converted to datetime format first then it will be combined with event_time. please try now.
  • I'm interested in learning how to restrict the time difference calculation for transaction with the same machine id. Do you know how to do it?
  • and how I do the subtraction all at once?