Method to reverse array causes StackOverflowError

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I try to write a method to reverse an array, but I always get an StackOverFlowError. Can someone help?

Here is my code:

public class Exercise4_2 {

    public static void main(String[] args) {
        int [] arr = {1, 3, 5, 7, 9};
        int result = reverse(arr);
        System.out.print(result);
    }

    static Integer reverse(int[] arr) {
        int n = arr.length;
        for (int i = 0; i < n/2; i++) {
            int temp = arr[i];
            arr[i] = arr[n-1-i];
            arr[n-1-i] = temp;
        }
        return reverse(arr);
    }
}

Your function is basically like:

reverse() {
    ...
    reverse();
}

How do you think this recursion will end? A correct recursion always need a base case, a case that can terminates the recursion...

Anyway, the way you solved it doesn't need any recursion. Then remove the call to reverse() inside reverse...

Reversing an Array in Java, Collections.reverse() can do that job for you if you put your numbers in a List of Integers . List<Integer> list = Arrays.asList(1, 4, 9, 16, 9, 7, 4, 9, 11);� The Reverse() method in array class reverses the sequence of the elements in the entire one-dimensional Array. To reverse an array, just use the Array.Reverse() method − Array.Reverse(temp); Within the reverse method, set the elements like the following code snippet. int[] list = { 29, 15, 30, 98}; int[] temp = list; You can try to run the

The reverse method should return a int[], and this array should be your arr parameter. No need of recursion.

StackOverflowError in Java with examples, The main cause of the StackOverflowError is that we haven't provided the proper terminating condition to our recursive function or template, which means it will� However, we don’t create a new array like the above method. Instead, we reverse the original array itself. In this method we swap the elements of the array. The first element is swapped with the last element. The second element id swapped with the last but one element and so on. For instance, consider array [1, 2, 3, …., n-2, n-1, n].

Simple solution: return the int[] that you have reversed, rather than calling the same method.

The method call is causing your program to go into infinite recursion.

Here is the fixed code :

public static void main(String[] args) {
    int [] arr = {1, 3, 5, 7, 9};
    int result = reverse(arr);
    System.out.print(result);
}

static Integer reverse(int[] arr) {
    int n = arr.length;
    for (int i = 0; i < n/2; i++) {
        int temp = arr[i];
        arr[i] = arr[n-1-i];
        arr[n-1-i] = temp;
    }
    return arr;
}

What a very bad day at work taught me about building Stack , The way the system is currently built, when you ask a question that Finding answers to questions on StackOverflow via Google is great, (Gold-badge votes are immediate; I think this is a cause for some and the vast array of skillsets that a typical developer with 20 years of experience uses every day. 1) How to apply recursive call for this method. for the original, the method is : reverse(int[] a). so, after first step, you should create array b from a[2] --> a[n-1]. and using reverse(int[] b)`. 2) after reverse b, what should we do to reverse a ? Assign values of b again back to a.

Thank you all! This is how i solved the problem:

public class Exercise4_2 {
public static void main(String[] args) {
    int [] arr = {1, 3, 5, 7, 9};
    reverse(arr);
    for (int i = 0; i < arr.length; i++) {
      System.out.print(arr[i]);
      if (i < arr.length - 1) {
        System.out.print(", ");
      }
    }
}
public static void reverse(int[] arr) {
    int n = arr.length;
    for (int i = 0; i < n/2; i++) {
        int temp = arr[i];
        arr[i] = arr[n-1-i];
        arr[n-1-i] = temp;
    }
}

}

What are the Most Disliked Programing Languages?, There are many ways to measure the popularity of a language; for where tags being disliked by a component of programmers leads to them� The reverse() method reverses the order of the elements in an array. Note: this method will change the original array.

Lang – Apache Commons Lang Release Notes, 3.0, 2011-07-18, Backwards incompatible update of Commons Lang to Java 5 MultilineRecursiveToStringStyle StackOverflowError when object is an array. Bug in method appendFixedWidthPadRight of class StrBuilder causes an� The reverse method transposes the elements of the calling array object in place, mutating the array, and returning a reference to the array. reverse is intentionally generic; this method can be called or applied to objects resembling arrays. Objects which do not contain a length property reflecting the last in a series of consecutive, zero

StackOverflowError on compilation, gotten to the point where we encounter this StackOverflowError on constructs ( large array, large expression. e = e.next+ }+ buf.reverse foreach { e => val i = e. sym.name.start & HASHMASK e.tail = hashtable(i) hashtable(i) = e Any ideas what SBT does differently here that might be causing the issue? Collections.reverse(Arrays.asList(yourArray)); java.util.Collections.reverse() can reverse java.util.Lists and java.util.Arrays.asList() returns a list that wraps the the specific array you pass to it, therefore yourArray is reversed after the invocation of Collections.reverse().

Jackson, How to use Jackson to break the infinite recursion problem on bidirectional Infinite recursion (StackOverflowError). (through ArrayList[0]. Object[] invertUsingStreams(Object[] array) { return IntStream.rangeClosed(1, array.length) .mapToObj(i -> array[array.length - i]) .toArray(); } Here we use the method IntStream.range to generate a sequential stream of numbers. Then we map this sequence into array indexes in descending order. 5. Using Collections.reverse()

Comments
  • Whats the recursive call for?
  • Well typically in recursion, you need a check to see if you should return something that isn't recursive. Otherwise - how would your recursion ever end? There is nothing to stop reverse() from calling itself over and over.