How to get only the digits from list of string using java

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I have list with combination of letters, digits and special characters. I need to extract the digits from string and store them in the same list.

I tried with below code

       List<String> list = new LinkedList<String>();
       list.add("132144, Test");
       list.add("76876295, Test2");
       //tried with replaceAll();
       list.replaceAll(x->x.replace("[^0-9]",""));
       //tried collection
       Collections.replaceAll(list, "\\W+", "");
       System.out.println(list);

Getting the output as [132144, Test,76876295, Test2], need output as [132144,76876295]

Stream the list, map each entry using a regular expression (\\D matches non-digits) to replace all non-digits with nothing. Collect that back into your original list (assuming you need to keep the new values only). Like,

list = list.stream().map(s -> s.replaceAll("\\D+", ""))
        .collect(Collectors.toList());
System.out.println(list);

Outputs (as requested)

[132144, 768762952]

Your current input doesn't have such a case, but you might also filter out any empty String(s) after applying the regex.

list = list.stream().map(s -> s.replaceAll("\\D+", ""))
        .filter(s -> !s.isEmpty()).collect(Collectors.toList());

How to extract numbers from a string and get an array of ints , \d matches a digit, and we need to write \ as \\ in a Java String though. and ] delimites a set of characters to be single matched, i.e., only one time in any order � Using Traversal: The idea is to traverse each character in the string and check if the character of the string contains only digits from 0 to 9.If all the character of the string contains only digits then return true, otherwise, return false.

You can do like this:

    String line = "This order was32354 placed OK?8377jj";
    String regex = "[^\\d]+";

    String[] str = line.split(regex);

    for(int i=0;i<str.length; i++) {
        System.out.println(str[i]);
    }

Output:

32354
8377

Hope this helps.

Extract Numbers From String Using Java Regular Expressions, Extract Numbers From String Using Java Regular Expressions If you want to extract only certain numbers from a string you can provide an index to the group() function. For example, if Java Remove Duplicates From List. The example also shows how to remove all non-numeric characters from String in Java. How to keep only numbers in String? Many times string contains numbers and letters and you want to keep only numbers by removing the non-numeric characters from the string. This can be done using the regular expression and the replaceAll method of String class.

public static void main(String[] args) {

    List<String> list = new LinkedList<String>();
    List<String> list1 = new LinkedList<String>();
    list.add("132144, Test");
    list.add("76876295, Test2");
    for(String s:list)
        list1.add(retriveDigits(s));
    System.out.println(list1);
}

private static String retriveDigits(String str) {
    return str.replaceAll("[^0-9]*", "");

}

}

Please find above class, I think that will help you.

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you can use NumberUtils.isNumber() in stream like this:

list = list.stream()
           .filter(NumberUtils::isNumber)
           .collect(Collectors.toList());

How to check if string contains only digits in Java, Java Program to check whether it is possible to make a divisible by 3 number using all digits in an array � Check whether product of digits at even places is divisible� This program will extract the digits, numbers from the string using java program, in this program we will read a string that will contain digits in the string and will extract the digits, numbers from the inputted string. Extract Digits/ Numbers from String using Java Program //Java program to extract numbers/digits from a string. import java

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How to convert a long number string into a list of integers in Java , You can do a one liner using the new lambda expressions in Java 8. splits the string on non word boundaries, producing an array of strings each has one digit How do I take the input of two integers separated by white space in Java? Assuming the input string will be the string of digits only (i.e. there won't be invalid � Learn how to get first 4 characters of a String or simply any number of first characters of a string in Java. Get first 4 characters of String – Example. To get substring having first 4 chars first check the length of string. If string length is greater than 4 then substring(int beginIndex, int lastIndex) method. This method takes start and

Comments
  • Do you want to include the 2 of the text Test2 into the result?