Remove 'u' from a python list
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I have a python list of list as follows. I want to flatten it to a single list.
l = [u'']
I am trying.
l = [item for value in l for item in value]
It turns the list to
[u'[', u'1', u'9', u'0', u'2', u'1', u'5', u']']
How to remove the
u from the list.
In your current code, you are iterating on a string, which represents a list, hence you get the individual characters.
>>> from ast import literal_eval >>> l = [u''] >>> l = [item for value in l for item in value] >>> l [u'[', u'1', u'9', u'0', u'2', u'1', u'5', u']']
Seems to me, you want to convert the inner string representation of list, to a flattened list, so here you go:
>>> l = [u''] >>> l = [item for value in l for item in literal_eval(value)] >>> l 
The above will work only when all the inner lists are strings:
>>> l = [u'', u'[190216, 190217]'] >>> l = [item for value in l for item in literal_eval(value)] >>> l [190215, 190216, 190217] >>> l = [u'', u'[190216, 190217]', [12, 12]] >>> l = [item for value in l for item in literal_eval(value)] Traceback (most recent call last): File "<stdin>", line 1, in <module> File "/usr/lib/python2.7/ast.py", line 80, in literal_eval return _convert(node_or_string) File "/usr/lib/python2.7/ast.py", line 79, in _convert raise ValueError('malformed string') ValueError: malformed string
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u means a
unicode string which should be perfectly fine to use.
But if you want to convert
str (which just represents plain bytes in Python 2) then you may
encode it using a character encoding such as
>>> items = [u''] >>> [item.encode('utf-8') for item in items] ['']
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[str(item) for item in list]
>>> li = [u'a', u'b', u'c', u'd'] >>> print li [u'a', u'b', u'c', u'd'] >>> li_u_removed = [str(i) for i in li] >>> print li_u_removed ['a', 'b', 'c', 'd']
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You can convert your unicode to normal string with
>>> list(str(l)) ['[', '1', '9', '0', '2', '1', '5', ']']
Remove Synonyms, Remove Antonyms, remove Definitions and Synonyms . verb transitive. UK /rɪˈmuːv/� Synonyms for remove at Thesaurus.com with free online thesaurus, antonyms, and definitions. Find descriptive alternatives for remove.
I think this issue occurred in
python 2.7 but in latest python version u did not displayed when it run
l = [u''] l = [item for value in l for item in value] print(l)
['[', '1', '9', '0', '2', '1', '5', ']']
If you want to concatenate string items in a list into a single string, you can try this code
l = [u''] l = [item for value in l for item in value] l = ''.join(l) print(l)
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REMOVE, Removing backgrounds from images has never been easier: Select a photo, wait 5 seconds, and get a transparent cutout - 100% automatically and for free. Remove(Int32) Returns a new string in which all the characters in the current instance, beginning at a specified position and continuing through the last position, have been deleted.
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- output like l = [''] ??
lis a single list, consisting of one element, and that element is of type
unicode. It's a string that looks like
, it's not a list whose element is the number
190215. Can you say exactly what you expect the output to be?
result1.append([str(i) for i in line])UnicodeEncodeError: 'ascii' codec can't encode characters in position 56-59: ordinal not in range(128)
- The original data which I want to be converted to normal string file csv >> result
[u'"0000211504512150"', u'"NEW"', u'"27.95"', u'"sdjfgjdshf"', u'"0"', u'"FALSE"', u'""', u'""', u'"adfgugfius708vs"', u'"FBR"', u'"FALSE"', u'"NOT_PUBLISHED"', u'""']..... like file csv >> result
["0000211504512150", "NEW", "27.95", "sdjfgjdshf", "0", "FALSE", "", "", "adfgugfius708vs", "FBR", "FALSE", "NOT_PUBLISHED", ""]