Search for a certain element in a List and delete it

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I have a List<String> in kotlin which contains the following elements

"Bank", "of", "Luxemburg", "Orange", "County"

How do I search the List if it contains "of"?

How can I get the position of "of" and then delete it from the list?

First be sure that your list is a mutable list:

val list = mutableListOf("bank", "of" , "Luxemburg", "Orange", "country")

Or if you already have a list:

val newList = list.toMutableList()

then do this:



[of, Luxemburg, Orange, country]

If you have more copy value in same list do it:



[bank, of, Luxemburg, Orange, country, Luxemburg]
[bank, of, Orange, country]

Python, We use cookies to ensure you have the best browsing experience on our website . By using our site, you acknowledge that you have read and� So, if we want to search for an element in list or check if an element exists in std::list, then we not to write some code for it i.e. Logic Used to find a given element in list, Iterate over all the elements of list For each element check if this element is equal to given element; Suppose we have a list of strings i.e.

In case you want to remove the first "of" found in the list, then remove will be sufficient. If you want to remove every occurrence of "of", then use removeIf or maybe even removeAll:

fun main() {
    val l: MutableList<String>
                = mutableListOf("Bank", "of", "Luxemburg", "of", "Orange", "of", "County")
    val m: MutableList<String>
                = mutableListOf("Bank", "of", "Luxemburg", "of", "Orange", "of", "County")
    // remove first "of" found
    // remove every element that equals "of"
    l.removeIf { it == "of" }

    // use removeAll
    m.removeAll { it == "of" }

The output is

[Bank, of, Luxemburg, of, Orange, of, County]
[Bank, Luxemburg, of, Orange, of, County]
[Bank, Luxemburg, Orange, County]
[Bank, of, Luxemburg, of, Orange, of, County]
[Bank, Luxemburg, Orange, County]

Python, We use cookies to ensure you have the best browsing experience on our website . By using our site, you acknowledge that you have read and� Python list is an essential container as it stores elements of all the datatypes as a collection. Knowledge of certain list operations is necessary for day-day programming. There are so many ways that you can find an element in the list, some of which are the following. Find an element in the list by index in Python. Python Linear search on the

If you just want the elements back without "of" you can filter them

val list = listOf("bank", "of" , "Luxemburg", "Orange", "country")
val result = list.filter { it != "of" }

Remove an item from a list in Python (clear, pop, remove, del), You can remove the item at the specified position and get the value of that item with pop() . The index at the beginning is 0 (zero-based indexing). Different ways to Erase / Delete an element from a Set in C++; Python : How to Check if an item exists in list ? | Search by Value or Condition; Delete elements, rows or columns from a Numpy Array by index positions using numpy.delete() in Python; Python: Find duplicates in a list with frequency count & index positions

I think this could work: list.indexOf("of").also { if (it != -1) list.removeAt(index) }

Python List remove(), The remove() method removes the first matching element (which is passed as an argument) from the list. The original list is : 10 15 20 25 30 35 The list after deleting 1 element using erase() : 10 15 25 30 35 The list after deleting multiple elements using erase() : 10 15 35 Using list::pop_front() and list::pop_back(): pop_back(): This function removes the last element from the list. This reduces the size of list by 1.

4 Ways to Delete From a List in Python | by Devin Soni, There are several ways to remove an element from a list in Python. Let's look at the four main ones: the clear , pop , and remove methods, and the del operator. Python list method remove() searches for the given element in the list and removes the first matching element. Syntax. Following is the syntax for remove() method − list.remove(obj) Parameters. obj − This is the object to be removed from the list. Return Value. This Python list method does not return any value but removes the given object

Remove Elements From Lists | Python List remove() Method, Also learn how to remove elements from a list using the various methods ( However, this is a slow technique, as it involves searching the item in the list.) The pop() method removes an element at a given index, and will also� Deleting the head of a particular element in an expression is equivalent to applying FlattenAt to the expression at that point. » Deleting the head of a whole expression makes the head be Sequence. » Deleting a whole expression gives the result Sequence []. Delete works on SparseArray objects.

Haskell : delete, Module: List. Function: delete. Type: Eq a => a -> [a] -> [a]. Description: removes the first occurrence of the specified element from its list argument. Related: (\\)� it's pretty deep, I have not had good reliability trying to answer these but what I was trying to say was to note for the reader that "Concurrent Modification Exception" was not implemented as I would think - rather than detecting two threads of which one does a remove() what had been done was to set the exception flag in the jvm solely on the basis that the thread attempting a remove() was

  • use flatmap, ignore elements "of" in closure
  • If you MUST change the list go with other answers, otherwise @AlexandrKolesnik answer above is the way to go
  • @AlexandrKolesnik Thanks for the comment. I'll definitely look into using flatmaps. Much appreciated!
  • If you need to transform the mutable list to a list because you use List<String> in some function or class, don't be afraid, you can always create a list from a mutable list, just by passing the entire mutable list in the constructor
  • here more information if you are interested in using collections:
  • This will only remove the first occurrence of "of"... If that's enough, then nice answer ;-)
  • it doesn't remove the first element, try it with Luxemburg. Ah ok you mean all elements. I edit, now also copy are removed.
  • There is a removeAll(predicate) that does the same thing as removeIf(filter) but is not JDK-only.