Regex to catch strings with only 2 digits

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I have searched for similar questions, and even though I found several answers, none seams to work. I have a list of strings

Z189
I142
M395
L210
V467
M203
Q277
Q461
Y440
S250
M162
Q96
22Q
W148
Q72
T22T
22TWE22
12E34

and I need a regex to find only strings holding only 2 digits (not more or less). So in this case:

Q96, 22Q, Q72, T22T

my failed attempts include:

\D\d{2}\D
(?<!\d)\d{2}(?!\d)

You could use ^\D*(\d)\D*(\d)\D*$

\D* makes sure anything before your first digit isn't another digit.

(\d) captures your first digit.

\D* makes sure there is no other digits between your two digits.

(\d) captures your second digit.

\D* makes sure anything after your second digit isn't another digit.

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This works well. Note the global and multiline flags.

/^[a-zA-z]\d{2}[a-zA-Z]*$/gm

Explanation: Start of line -> letter -> exactly two digits -> zero or more letters -> end of line

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Comments
  • Try ^(?:\D*\d){2}\D*$? Or ^\D*(?:\d\D*){2}$.
  • Do the two nubers have to be together (T22) or can the be split (2T2)?
  • @Kokogino I frankly don't know, I haven't thought about it. Can u think a solution for each case?
  • If 2 digits are continuous then use: ^\D*\d{2}\D*$
  • you can validate the regexpr above here: regex101.com/r/dX3hD4/113
  • You can replace [^\d] by \D.
  • @Kokogino Edited it :)
  • the regexpr does not match for "1EER4TT" "TT22"
  • @3p3ch3 Yes it does.