Creating a loop that has a one second gap between loops [Handling Exceptions in the code]

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I'm trying to create a countdown timer that will update a Jlabel in Java for a quiz app. So far I have this for my code but it gives an error for the sleep() method and doesn't run my program.

while (timer > 0) {
     lblTimer.setText(Integer.toString(timer));
     Thread.sleep(1000);
     timer--;
}

class JlabelUpdater {
   private JLabel label;
   private Integer timerTickCount;
   private Integer tickerIntervalInMillis;
   private ScheduledExecutorService scheduledExecutorService = 
           Executors.newScheduledThreadPool(1);

   public JlabelUpdater(JLabel label, Integer timerTickCount, 
                        Integer tickerIntervalInMillis) {
      this.label = label;
      this.timerTickCount = timerTickCount;
      this.tickerIntervalInMillis = tickerIntervalInMillis;
   }

   public void startTimer() {
     scheduledExecutorService.scheduleAtFixedRate(() -> {
        if (timerTickCount == 0) {
           scheduledExecutorService.shutdown();
        }

        System.out.println("timer running: " + timerTickCount);
          changeText(timerTickCount + "");
          timerTickCount--;
         }, 0, tickerIntervalInMillis, TimeUnit.MILLISECONDS);
   }

   private void changeText(final String text) {
      EventQueue.invokeLater(() -> {
             label.setText(text);
             System.out.println("text = " + text);
         }
      );
   }
}

If you want a timer for 5 seconds and update the JLabel text every 1 second you can create an object of this class and call it like this.

new JlabelUpdater(new JLabel(), 5, 1000).startTimer();

It is always recommended to use ScheduledExecutorService instead of Timer whenever possible.

Loop control statements — Object-Oriented Programming in Python , We will discuss the difference between these statements later in the chapter, but first Whenever you write a while loop, make sure that the variable you use in your You might be wondering why the Python interpreter cannot catch infinite loops. Rewrite the previous program so that it has two loops – one which collects� It is difficult to be acurate with the proposed solutions. Instead of calculate the gap between iterations, calculate the absolute time when the next iteration should be executed.


Add a try catch block to catch the exception

     while (timer > 0) {
            lblTimer.setText(Integer.toString(timer));
            try {
                Thread.sleep(1000);
            } catch (InterruptedException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
            timer--;

           }

C Programming Course Notes - Looping Constructs, While loops check for the stopping condition first, and may not execute the body where the body can be either a single statement or a block of statements within is not executed, and execution continues with the code following the loop. C has a comma operator, that basically combines two statements so that they can� In the body of a loop, we have a print function to print the numbers on a new line in the console. We have the value one stored in number, after the first iteration the value will be incremented, and it will become 2. Now the variable number has the value 2.


You need to do one of the following:

A. Surround Thread.sleep|(1000) with try/catch

while (timer > 0) {
    lblTimer.setText(Integer.toString(timer));
    try {
        Thread.sleep(1000);
    } catch (InterruptedException e) {
        e.printStackTrace();
    }
    timer--;
}

B. Append throws InterruptedException in the signature of the method where you have written Thread.sleep(1000);.

Loops: while and for, For every loop iteration, write down which value it outputs and Rewrite the code changing the for loop to while without There's no need to implement a special handling for a be divided without a remainder by anything except 1 and itself. You have second alert(i), on the last line, dude. Sleep allows us to pause a macro for X milliseconds, which is a better resolution than Wait which has a minimum delay of 1 second. So to pause a macro for 5 seconds using Sleep we write this. Sleep 5000 Loops. The big drawback of using Wait or Sleep, is that Excel locks you out until the wait/sleep period has finished.


1.13. Loops and Sequences — Hands-on Python Tutorial for Python 3, There are two Python statement types to do that: the simpler for loops, which we take 1 2 3 4 5. x = 3 # simple sequential code y = x + 2 # updating two variables y = 2*y x Write a two-line for-each loop in a file types2.py containing a call to the type The second call to numberList has a different actual parameter [' apples',� there is another culprit that will cause a pop at the end of the loop. that is if the loop does not end at amplitude zero. it seems the easiest way to do this is in your wave file (the one which allows the reverb to wash out) you create a fadeout (can be very short) to bring the end of the loop exactly to amplitude zero for a fraction of a second).


Loops and Strings | Think Java, Using a while statement, we can repeat the same code multiple times: The body of the loop should change the value of one or more variables so that, eventually, Specifically, ++ is the increment operator; it has the same effect as i = i + 1 . There is another difference between for loops and while loops: if you declare a� Python sleep syntax. The syntax is as follows import time time.sleep(1) time.sleep(N) The time.sleep() suspend execution of a script for the given number of seconds. The argument may be a floating point number to indicate a more precise sleep time.


Loops and iteration, The statements for loops provided in JavaScript are: This expression usually initializes one or more loop counters, but the syntax allows an expression of any degree In the example below, the function contains a for statement that counts the Make sure the condition in a loop eventually becomes false� Back in the day, home computers used to have a “turbo” button, which (when activated), made the processor slower. The problem was that games were coded around an input loop that was expected to take a specific number of milliseconds. If the loop was executed faster, the whole game would speed up, becoming unplayable.