How to compare the signature of two functions?

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Is there a way to check if two functions have the same signature? For example:

int funA (int a, int b);
int funB (int a, int b);
float funC (int a, int b);
int funD (float a, int b);

In this example, funA and funB is the only combination of functions that should return true.

Essentially you want to check if types of two functions are the same:

std::is_same_v<decltype(funA), decltype(funB)>

I wouldn't call this 'comparing signatures', as, if I remember correctly, return type is not a part of a signature (because it doesn't affect overload resolution).

Compare two functions by analyzing an equation and a graph , Compare two functions by analyzing an equation and a graph. From LearnZillion; Created by Levi Straight; Standards 8.F.A.2. teaches Common Core State� Now to generalize the comparison for an arbitrary number of function signatures, you can do the following. #include <type_traits> // std::is_same, std::conjunction_v template<typename Func, typename Funcs> constexpr bool areSameFunctions = std::conjunction_v<std::is_same<Func, Funcs>>; and compare as many functions as one like

You can check the function type with decltype and std::is_same. e.g.

std::is_same_v<decltype(funA), decltype(funB)>  // true


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Others have mentioned the solution using std::is_same and decltype.

Now to generalize the comparison for an arbitrary number of function signatures, you can do the following

#include <type_traits> // std::is_same, std::conjunction_v

template<typename Func, typename... Funcs>
constexpr bool areSameFunctions = std::conjunction_v<std::is_same<Func, Funcs>...>;

and compare as many functions as one like

areSameFunctions<decltype(funA), decltype(funB), decltype(funC)>

(See Live Demo)

Or for less typing (i.e. without decltype), make it as a function

template<typename Func, typename... Funcs>
constexpr bool areSameFunctions(Func&&, Funcs&&...)
   return std::conjunction_v<std::is_same<Func, Funcs>...>;

and call simply by

areSameFunctions(funA, funB, funC) 

(See Live Demo)

Methods � The Julia Language, However, the signatures of method definitions can be annotated to indicate This output tells us that f is a function object with two methods. It also allows comparing the methods available in two worlds just by comparing their ordinal value. Related Topics: Common Core for Grade 8 Common Core for Mathematics More Math Lessons for Grade 8 Examples, solutions, videos, and lessons to help Grade 8 students learn how to compare properties of two functions each represented in a different way (algebraically, graphically, numerically in tables, or by verbal descriptions).

As another possibility that hasn't been mentioned: you can use typeid from typeinfo and ==:

#include <typeinfo>

if(typeid(funA) != typeid(funB))
    std::cerr << "Types not the same" << std::endl;

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Comparison operators, The two-way comparison operator expressions have the form types, the following function signatures participate in overload resolution:� Compares the value of the string object (or a substring) to the sequence of characters specified by its arguments. The compared string is the value of the string object or -if the signature used has a pos and a len parameters- the substring that begins at its character in position pos and spans len characters.

Type Compatibility � TypeScript, Let's start with a basic example of two functions that differ only in their parameter lists: When comparing the types of function parameters, assignment succeeds if each overload in the source type must be matched by a compatible signature � The roots are, x equals negative one and x is equal to two. So these two functions, at most, are going to have two roots in common, because this g of x only has two roots. There's a couple of ways we could tackle it. We could just try to find f's roots, or we could plug in either one of these values and see if it makes the function equal to a zero.

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