## PHP - count consecutive repeated elements in array in the same sequence as they are

I need to count consecutive repeated elements in the array, but if they are non consecutive I want to count them also, to have them in the same sequence as they are.

For example I have flowing array:

$array = Array ('a','b','a','a','a','c','c','b','b','a','a','a','a');

if I use array_count_values function example:

print_r(array_count_values($array));

Output will be:

Array ( [a] => 8 [b] => 3 [c] => 2 )

But I need to get output like this:

element counted value a 1 b 1 a 3 c 2 b 2 a 4

I would appreciate if anybody could help me with this issue?

Thank you.

You can iterate over the array, counting values while they are the same, and pushing a value to the result array when they are different:

$result = []; $count = 0; $current = $array[0]; for ($i = 0; $i < count($array); $i++) { if ($array[$i] == $current) { $count++; } else { $result[] = array($current, $count); $count = 1; } $current = $array[$i]; } $result[] = array($current, $count); print_r($result);

Output:

Array ( [0] => Array ( [0] => a [1] => 1 ) [1] => Array ( [0] => b [1] => 1 ) [2] => Array ( [0] => a [1] => 3 ) [3] => Array ( [0] => c [1] => 2 ) [4] => Array ( [0] => b [1] => 2 ) [5] => Array ( [0] => a [1] => 4 ) )

**Count consecutive pairs of same elements,** Given an array arr[], the task is to count the number of pairs formed by consecutive elements in which both of the elements in a pair are same. No two consecutive elements in the given array are equal. C++; Java; Python3; C#; PHP values of all adjacent elements � Find the K-th Permutation Sequence� count() - Count all elements in an array, or something in an object array_unique() - Removes duplicate values from an array array_values() - Return all the values of an array

Starting with an array with the first item from the source (and a count of 1), this then starts from the second item and checks if it matches the one in the current output. Adding 1 if it matches or adding a new entry if it doesn't...

$array = Array ('a','b','a','a','a','c','c','b','b','a','a','a','a'); $output = [ ["element" => $array[0], "count" => 1 ] ]; $outputPoint = 0; for ( $i = 1, $count = count($array); $i < $count; $i++ ) { if ( $array[$i] == $output[$outputPoint]["element"] ) { $output[$outputPoint]["count"]++; } else { $output[++$outputPoint] = ["element" => $array[$i], "count" => 1 ]; } } print_r($output);

Which outputs...

Array ( [0] => Array ( [element] => a [count] => 1 ) [1] => Array ( [element] => b [count] => 1 ) [2] => Array ( [element] => a [count] => 3 ) [3] => Array ( [element] => c [count] => 2 ) [4] => Array ( [element] => b [count] => 2 ) [5] => Array ( [element] => a [count] => 4 ) )

**Count of only repeated element in a sorted array of consecutive ,** Count of only repeated element in a sorted array of consecutive elements The task is to find length of the sequence of repeated element. Input : arr[] = {1, 2, 3, 4, 4, 4, 5, 6} Output : 4 3 Repeated element is 4 and it appears 3 times. k-th missing element in sorted array � Last duplicate element in a sorted array � Count � If the array is sorted and if max-difference of two adjacent elements is 1, then the length of the repeated sequence is n – 1 – (array [n-1] – array) Value of the element. To the value, we do Binary Search.

This loops through the array and increments the number of elements in `$count`

.

$array = ['a','b','a','a','a','c','c','b','b','a','a','a','a']; $count = []; $crt = -1; foreach($array ?? [] as $element) { if($crt == -1 || $count[$crt]["element"] != $element) { $count[++$crt] = ["element" => $element, "counted_value" => 1]; } else { $count[$crt]["counted_value"]++; } }

The array looks like:

Array ( [0] => Array ( [element] => a [counted_value] => 1 ) [1] => Array ( [element] => b [counted_value] => 1 ) [2] => Array ( [element] => a [counted_value] => 3 ) [3] => Array ( [element] => c [counted_value] => 2 ) [4] => Array ( [element] => b [counted_value] => 2 ) [5] => Array ( [element] => a [counted_value] => 4 ) )

**array_count_values - Manual,** Returns an associative array of values from array as keys and their count as value. Throws E_WARNING for every element which is not string or integer. Removes duplicate values from an array; array_values() - Return all the values of an In order to apply array_map with callback checking for localised values like city� The count () function returns the number of elements in an array.

$out = array(); $cnt = -1; foreach($array as $val) { if(in_array($val,$out)) { $out[] = $var; $finalArr[$cnt]['cnt'] = count($out); }else{ $out = array(); $out[] = $val; $finalArr[] = array('ele'=>$val,'cnt'=>count($out)); $cnt++; } } print_r($finalArr);

**range - Manual,** range — Create an array containing a range of elements If a step value is given, it will be used as the increment between elements in the sequence. step� Find the two repeating elements in a given array. You are given an array of n+2 elements. All elements of the array are in range 1 to n. And all elements occur once except two numbers which occur twice. Find the two repeating numbers. For example, array = {4, 2, 4, 5, 2, 3, 1} and n = 5.

**substr_count - Manual,** PHP 5, PHP 7). substr_count — Count the number of substring occurrences It outputs a warning if the offset plus the length is greater than the haystack length . Return Values � Simply convert the haystack and the needle to the same case (upper or lower). a simple version for an array needle (multiply sub- strings): count (mixed $array_or_countable [, int $mode = COUNT_NORMAL ]) : int Counts all elements in an array, or something in an object. For objects, if you have SPL installed, you can hook into count () by implementing interface Countable.

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I'd like to know a way I could go through each individual element in the array, and getting a value for how many steps the number stays at the same value. For instance, for this example, the output I would be looking for would be