## Python: How to concatenate all possible combinations in two lists?

You can use `itertools.product`

:

from itertools import product list1 = ['A', 'B'] list2 = [1, 2, 3] for e1,e2 in product(list1, list2): print(e1+str(e2))

Output:

A1 A2 A3 B1 B2 B3

**combinations between two lists?,** repeat the first list, permutate the second and zip it all together >>> from itertools import permutations, repeat >>> a = [1, 2, 3] >>> b = [4, 5,� I have an array of [1,2,3] I want to calculate meet and joint for two listis, the firs make all the possible combinations using all elements of the two array:{1,2,3} and {1,2,3,4} list1 1 [[1, 2, 3

You may use:

list3 = [a+b for a in list1 for b in map(str, list2)] print(*list3, sep = "\n") A1 A2 A3 B1 B2 B3

**Python merging two lists with all possible permutations,** Then each combination is converted into a list and append to the combination list . Below is the implementation. Python3. Python3. I'm basically looking for a python version of Combination of List<List<int>>. Given a list of lists, I need a new list that gives all the possible combinations of items between the lists.

You can use:

list1 = ['A', 'B'] list2 = [1, 2, 3] for i in list1: for j in list2: print(i+str(j))

**Python program to get all unique combinations of two Lists ,** Python | Merge key value lists � Python | Average of two lists � Python | Dividing two lists � Python | Intersection of two lists. manjeet_04. I know there is a something to generate combinations of items in list in itertools but I don't think I can use it here since I have different "pools" of values. Is there any existing solution to do this, or how should I proceed to do it myself, I am quite stuck with this nested structure.

**Python,** I'm trying to figure out the best way to merge two lists into all possible combinations. So, if I start with two lists like this: list1 = [1, 2] list2 = [3, 4]. The resulting list� import itertools a = [1,2,3] b = [4,5] c = [-1] # result contains all possible combinations. combinations = list(itertools.product(a,b,c)) Note that the resulting combinations variable itself is a list (could be cast to a set), and the different elements are tuples, not dicts.

**Python merging two lists with all possible permutations ,** If we have two lists and we need to combine each element of the first element with each element of the second list, then we have the below� With list comprehension, you can easily loop through all combinations of 2 or 3 lists. But what about more, like 4,6, 20? This recipe show a way to do this, without use of recursion.

**All possible permutations of N lists in Python,** Get code examples like "how to combine two lists in python" instantly right from your Your browser does not currently recognize any of the video formats available. all permutations python � all possible subsequences of a string in python� I know it's far more practical to use itertools to get the all the combinations, but you can achieve this partly with only list comprehension if you so happen to desire, granted you want to code a lot. For combinations of two pairs: lambda l: [(a, b) for i, a in enumerate(l) for b in l[i+1:]] And, for combinations of three pairs, it's as easy as this: