SQL Server : How to find duplicated rows value

SQL Server : How to find duplicated rows value

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I want to find a duplicate number more than 4 in rows value.

If you have to find a number that is repeated more than four times, and it is not if you repeat it more than four times in a combination of other numbers.

This table is test2:

num1   num2  num3  num4  num5  numb6
--------------------------------------
 1      1     1     2     3      4
 1      1     1     1     3      4
 1      2     3     4     5      6
 1      2     2     1     4      5

My SQL query:

-- CTE
;WITH TEMP(num1, num2, num3, num4, num5, num6) AS 
(
    SELECT 
        RIGHT(num1) AS num1,
        RIGHT(num2) AS num2,
        RIGHT(num3) AS num3,
        RIGHT(num4) AS num4,
        RIGHT(num5) AS num5,
        RIGHT(num6) AS num6
    FROM 
        test2   
)
-- select duplicate number
SELECT 
    num1, num2, num3,
    num4, num5, num6,
    COUNT (CASE 
             WHEN num1 IN (num2, num3, num4, num5, num6)
                THEN 1
          END) +
    COUNT (CASE
             WHEN num2 IN (num3, num4, num5, num6)
                THEN 1
           END) + 
    COUNT (CASE
             WHEN num3 IN (num4, num5, num6)
                THEN 1
           END) +
    COUNT (CASE
             WHEN num4 IN (num5, num6)
                THEN 1
           END) +
    COUNT (CASE
             WHEN num5IN (num6)
                THEN 1
           END) AS countNum
FROM 
    TEMP
GROUP BY 
    num1, num2, num3, num4, num5, num6

I get a result like this:

num1   num2  num3  num4  num5  numb6  countNum
----------------------------------------------
 1      1     1     1     3      4       4
 1      2     2     1     4      5       4

but I need to get this instead:

num1   num2  num3  num4  num5  numb6  countNum
----------------------------------------------
 1      1     1     1     3      4        4

or I need get data

num1   num2  num3  num4  num5  numb6
------------------------------------
 1      1     1     1     3      4

Use apply!

select t.*, v.cnt
from t cross apply
     (select top (1) num, count(*) as cnt
      from (values (num1), (num2), (num3), (num4), (num5), (num6)
           ) v(num)
      group by num
      order by count(*) desc
     ) v
where v.cnt >= 4;

Not only is this less prone to error than massive case expressions. It could even have better performance.

How to Find Duplicate Values in a SQL Table, we'll need to select the entire table and join that to our duplicate rows. Our query looks like this:. To accomplish this, we’ll need to select the entire table and join that to our duplicate rows. Our query looks like this: SELECT a.*. FROM users a JOIN (SELECT username, email, COUNT(*) FROM users GROUP BY username, email HAVING count(*) > 1 ) b ON a.username = b.username AND a.email = b.email ORDER BY a.email.


You can try below solution:

;with temp_data as (

select  1  as num1 ,    1 as num2 ,    1 as num3 ,    2  as num4 ,   3  as num5 ,    4  as num6 union all
select  1  as num1 ,    1 as num2 ,    1 as num3 ,    1  as num4 ,   3  as num5 ,    4  as num6 union all
select  2  as num1 ,    2 as num2 ,    2 as num3 ,    3  as num4 ,   2  as num5 ,    6  as num6 
)
SELECT * 
FROM temp_data
where 3=(CASE WHEN num1=num2 THEN 1 ELSE 0 END)+
(CASE WHEN num1=num3 THEN 1 ELSE 0 END)+
(CASE WHEN num1=num4 THEN 1 ELSE 0 END)+
(CASE WHEN num1=num5 THEN 1 ELSE 0 END)+
(CASE WHEN num1=num6 THEN 1 ELSE 0 END)
OR
3=(CASE WHEN num2=num1 THEN 1 ELSE 0 END)+
(CASE WHEN num2=num3 THEN 1 ELSE 0 END)+
(CASE WHEN num2=num4 THEN 1 ELSE 0 END)+
(CASE WHEN num2=num5 THEN 1 ELSE 0 END)+
(CASE WHEN num2=num6 THEN 1 ELSE 0 END)
OR
3=(CASE WHEN num3=num1 THEN 1 ELSE 0 END)+
(CASE WHEN num3=num2 THEN 1 ELSE 0 END)+
(CASE WHEN num3=num4 THEN 1 ELSE 0 END)+
(CASE WHEN num3=num5 THEN 1 ELSE 0 END)+
(CASE WHEN num3=num6 THEN 1 ELSE 0 END)
OR
3=(CASE WHEN num4=num1 THEN 1 ELSE 0 END)+
(CASE WHEN num4=num3 THEN 1 ELSE 0 END)+
(CASE WHEN num4=num2 THEN 1 ELSE 0 END)+
(CASE WHEN num4=num5 THEN 1 ELSE 0 END)+
(CASE WHEN num4=num6 THEN 1 ELSE 0 END)
OR
3=(CASE WHEN num5=num1 THEN 1 ELSE 0 END)+
(CASE WHEN num5=num2 THEN 1 ELSE 0 END)+
(CASE WHEN num5=num4 THEN 1 ELSE 0 END)+
(CASE WHEN num5=num3 THEN 1 ELSE 0 END)+
(CASE WHEN num5=num6 THEN 1 ELSE 0 END)
OR
3=(CASE WHEN num6=num1 THEN 1 ELSE 0 END)+
(CASE WHEN num6=num2 THEN 1 ELSE 0 END)+
(CASE WHEN num6=num4 THEN 1 ELSE 0 END)+
(CASE WHEN num6=num3 THEN 1 ELSE 0 END)+
(CASE WHEN num6=num5 THEN 1 ELSE 0 END)
;

output:

num1    num2    num3    num4    num5    num6
1        1       1       1       3      4
2        2       2       3       2      6

demo

Finding duplicate values in a SQL table, SQL Server (as at SQL Server 2017) still requires all non-aggregated columns in simpler way to do it than having to find even/odd rows into a triple sub-select: I want to find a duplicate number more than 4 in rows value. If you have to find a number that is repeated more than four times, and it is not if you repeat it more than four times in a combination of other numbers. This table is test2:


Use the below code: this may help you,

select num1,num2,num3,num5 from dup
group by num1,num2,num3,num5
having count(num1)>1 and count(num2)>1 and count(num3)>1 and count(num5)>1

How to Find Duplicate Rows in SQL?, Problem: You have duplicate rows in your table, with only the IDs being unique. This query returns only duplicate records—ones that have the same product To select duplicate values, you need to create groups of rows with the same� USE TestDB GO --Initializing the table TRUNCATE TABLE TableB INSERT INTO TableB(Value) VALUES(1),(2),(3),(4),(5),(5),(3),(5) --Deleting duplicate values ; WITH TableBWithRowID AS ( SELECT ROW_NUMBER() OVER (PARTITION BY Value ORDER BY Value) AS RowID, Value FROM TableB ) DELETE o FROM TableBWithRowID o WHERE RowID > 1 SELECT * FROM TableB


select (select top 1 num1 from your_table group by num1 having count(*) > 1 order by count(*) desc) as num1,
       (select top 1 num2 from your_table group by num2 having count(*) > 1 order by count(*) desc) as num2,
       (select top 1 num3 from your_table group by num3 having count(*) > 1 order by count(*) desc) as num3,
       (select top 1 num4 from your_table group by num4 having count(*) > 1 order by count(*) desc) as num4,
       (select top 1 num5 from your_table group by num5 having count(*) > 1 order by count(*) desc) as num5,
       (select top 1 num6 from your_table group by num6 having count(*) > 1 order by count(*) desc) as num6

demo

How to Find Duplicate Rows With SQL, The first two rows have the same value in the day column, so if I consider those to be duplicates, here's a query to find them. The query uses a� Add a Sort operator from the SSIS toolbox for SQL delete operation and join it with the source data. For the configuration of the Sort operator, double click on it and select the columns that contain duplicate values. In our case, duplicate value is in [FirstName], [LastName], [Country] columns.


Find and Remove Duplicate Rows from a SQL Server Table, Identify Duplicate Rows in a SQL Server Table. Our task is to enforce uniqueness for the 'Value' column by removing duplicates. Removing� Microsoft SQL Server tables should never contain duplicate rows, nor non-unique primary keys. For brevity, we will sometimes refer to primary keys as "key" or "PK" in this article, but this will always denote "primary key."


Find Duplicate Rows in SQL - Select Statement Tutorial, Find duplicate row values in a field or multiple fields in SQL Server table with this tutorial. Do Duration: 2:06 Posted: Mar 23, 2013 Since SQL is a set based language, there is not an easy way, except for using cursors, to know the previous record’s values. If we knew these, we could just compare values, and when they were the same flag the records as duplicates.


How to Find Duplicate Records in SQL, Here, we will discuss a query to find duplicate rows in a database. Also, we will see how can we delete duplicate records in SQL with and� Select statement To find duplicates rows in a table you need to use a Select statement that contains group by with having keyword. Another option is to use the ranking function Row_Number (). Find duplicates rows - Group By