why am i only getting the first row value in array "row" in the below code. i need all the values corresponding to the query

why am i only getting the first row value in array "row" in the below code. i need all the values corresponding to the query

Related searches
  $s = $conn->prepare($q);
  $s->execute([$tagIdValue]);
  $d = $s->fetchAll();
  return $d;

function x($d) {
    foreach ($d as $row) {
      $val = $row["id"];
      $cont = trimContent($row);
      return $row;
    }
  }

i have a query , which returns all the values in the table and a function to convert it into an assosiate array. But only getting the first row in the array


Because ur using return inside loop, it only take first value and return it.

  $s = $conn->prepare($q);
  $s->execute([$tagIdValue]);
  $d = $s->fetchAll();
  return $d;

function x($d) {
    $arr =[]
    foreach ($d as $row) {
      $val = $row["id"];
      $cont = trimContent($row);
      array_push($arr, $val)
    }
   return $arr;
  }

PHP MSQL While Loop only returns first row - PHP, PHP MSQL While Loop only returns first row $metrics = array(); $result= mysql_query($metricsql)or die(" Error: Could not connect to I'm still returning only one row however. I was just testing the return to see if I would get different values. I am trying to write an array to a range and I have tried several ways but no matter what, I always get only the FIRST value of the array over and over again. Here is the code: Option Explicit Sub


Put your return outside the loop so only it returns only the first loop

function x($d) {
   foreach ($d as $row) {
     $val = $row["id"];
     $cont = trimContent($row);
     return $row;
}
}

Excel formula: First row number in range, You can get the first row (i.e. the starting row number) in a range with a formula necessary to make sure you are dealing with only one item, and not an array. In first row that is in Z3 there is a negative value in this form -0.97-5 The result of SEARCH function Gives Result as 1, because the first character is "-". This causes problem because your expected result is 5 . This problem can be avoided using 2 as the start number. I feel it is better to change all formulas.


Because, you are returning the result set in the loop.

So, only the first row is returned from the loop.

As, in the first iteration, return statement is encountered, so, that function will return and control will get out of the function.

And next iterations will not loop over the result set.

We need to create an array before loop,

append results to that array

and return the array.

Corrected Code:

$s = $conn->prepare($q);
  $s->execute([$tagIdValue]);
  $d = $s->fetchAll();
  return $d;

function x($d) {
 $array = array();
    foreach ($d as $row) {
      $val = $row["id"];
      $cont = trimContent($row);
       $array[] = $row;
    }
 return $array;
}

Excel formula: Get first text value with HLOOKUP, To lookup and retrieve the first text value across a range of columns, you can use the The table array C5:E5, entered as a relative references so that it changes as the The row index number is 1, since the range contains only one row. Problem: The array arguments don’t have the same dimension All of the array arguments should be the same dimension. If they’re not, then you get the #VALUE! error. For example, if Array 1 refers to a range of 3 rows and 2 columns, then Array 2 must also correspond to the similar range.


Instead writing a return inside a loop, replace that line with an array push or array shift function.

Once the loop has ended return the final result obtained from array_push/array_shift.

Access Data in Tables - MATLAB & Simulink, Table variables have names, just as the fields of a structure have names. The rows of a table First five rows of array extracted from table variable named ' Date'. To get the second field value in the first row, use code like the following: field2 = avarRecords(1,0) The avarRecords variable automatically becomes a two-dimensional array when GetRows returns data. If you request more rows than are available, then GetRows returns only the number of available rows.


You need to return outside the loop :

$s = $conn->prepare($q);
$s->execute([$tagIdValue]);
$d = $s->fetchAll();
return $d;

function x($d) {
  $arr =array();
  foreach ($d as $k=> $row) {
    $val = $row["id"];
    $cont = trimContent($row);
    $arr[$k] = $row;
  }
  return $arr;
}

Array Indexing - MATLAB & Simulink, Access elements of an array. For example, access the first and third elements of the second row of A . r = A(2,[1 3]). r = 1�2 5 7 Indexing with Logical Values. Note: this is an array formula and must be entered with Control-Shift-Enter.. How this formula works. So, the gist of the problem is this: We want to get the first non-blank cell, but we don't have a direct way to do that in Excel.


This is due to the fact that R first selects the values, and then adds the dimensions necessary to represent the data correctly. In this case R needs two dimensions with four indices (the number of columns) and two indices (the number of tables), respectively. As R fills a matrix column-wise, the original rows now turned into columns.


If you array-enter that formula in a 5 row by 4 column range, the intersection of that range’s third row and first column contains the regression’s R-squared value. So if you select just a single cell and enter the following formula, you’ll get the R-squared value only: =INDEX(LINEST(A2:A51,B2:D51,,TRUE),3,1)


This selects matrix index 2 (the final matrix), row 0, column 1, giving a value 31. Picking a row or column in a 3D array. You can access any row or column in a 3D array. There are 3 cases. Case 1 - specifying the first two indices. In this case, you are choosing the i value (the matrix), and the j value (the row). This will select a specific row.