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i want to get the 'printed value' of html pages.

i tried below query, but showGetResult() just return 'null value'

but my apache server logs printed i accessed index.php when i try this code.

(index.php just print helloworld)

<script type="text/javascript" src="http://code.jquery.com/jquery-latest.js"><\script>
<script type="text/javascript">
function showGetResult( name )
{
     var result = null;
     jQuery.ajax({
        url: 'http://localhost/index.php',
        type: 'get',
        dataType: 'text/html',
        success:function(data)
        {
            alert(data);
            result = data;
        } 
     });
     return result;
}

document.write(showGetResult('test'));
</script>

I think what you want to do is this.

<script type="text/javascript" src="http://code.jquery.com/jquery-latest.js"><\script>
<script type="text/javascript">
function showGetResult( name )
{
     jQuery.ajax({
        url: 'http://localhost/index.php',
        type: 'get',
        dataType: 'text/html',
        success:function(data)
        {
            alert(data);
            document.write(data);
        } 
     });
}

showGetResult('test');
</script>

jquery - return value using ajax result on success, There are many ways to get jQuery AJAX response. I am sharing with you two common approaches: First: use async=false and within function return ajax- object� Hello all, Is it possible to get a return value from a page call within an ajax call? For example, $("#new_request").click(function(e){ $.ajax({ Return value from .ajax call - jQuery Forum


This is the way AJAX works (asynchronously, like the name suggests). The showGetResult function returns before the AJAX call completes. showGetResult will therefore simply return null since that's what you've assigned to result.

Move any code that depends on the result of the AJAX call inside the success callback. Alternatively, you could make the call synchronous, but that's not usually what you want.

Ajax function to return value - JavaScript, I have a function that i want to call another function to get a result from the server jQuery.ajax({ url: 'http://mysite.com/lookupcity.asp?cityid=' + cityid, type: 'get',� I am making an ajax call to controller and returning a string value from controller. in controller: public JsonResult () { // some service call to get data string output = some value from service call; return Json(output); }


AJAX requests are aynchronous by default; you can't return their result in a function, you need to use callbacks. The easiest way to achieve what you want is to put your code that handles your data in your success handler:

    success:function(data)
    {
        alert(data);
        result = data;
        document.write(showGetResult('test'));
    } 

Also, don't use document.write.

jQuery.get(), jQuery.get( url [, data ] [, success ] [, dataType ] )Returns: jqXHR. Description: Load Type: PlainObject. A set of key/value pairs that configure the Ajax request . You can, however, bind a variable in the outer scope and set it in the callback. To get the functionality that you want, you'll need to use $.ajax and set the async option to false. Then you can define a variable in the outer scope and assign it in the ajax callback, returning this variable from the function.


You have the wrong dataType per the documentation for jQuery.ajax:

"html": Returns HTML as plain text; included script tags are evaluated when inserted in the DOM.

So you want to use html:

...
dataType: 'html',
...


In addition, as others have said, the ajax request is asynchronous. So you need to restructure your code. For example:

function showGetResult( name )
{
 var result = null;
 jQuery.ajax({
    url: 'http://localhost/index.php',
    type: 'get',
    dataType: 'html',
    success:function(data)
    {
        alert(data);
        result = data;
        document.write(result);
    } 
 });
}

showGetResult('test');

jQuery.ajax(), Note: Setting cache to false will only work correctly with HEAD and GET requests. Each converter's value is a function that returns the transformed value of the� I have a function that i want to call another function to get a result from the server web page (text format) and return it to the original function this is not working - what am I doing wrong


You're missing a fundamental point here. The success method is not run when you call showGetResult. It is run asynchronously.

At the point that you put return result; it is still null (because success has not yet been invoked).

What you need to do is have document.write execute after success is invoked. Either like this:

<script type="text/javascript" src="http://code.jquery.com/jquery-latest.js"><\script>
<script type="text/javascript">
function showGetResult( name )
{
     var result = null;
     jQuery.ajax({
        url: 'http://localhost/index.php',
        type: 'get',
        dataType: 'text/html',
        success:function(data)
        {
            alert(data);
            document.write(data);
        } 
     });
     return result;
}

//document.write(showGetResult('test'));
showGetResult('test');
</script>

Or with a callback:

<script type="text/javascript" src="http://code.jquery.com/jquery-latest.js"><\script>
<script type="text/javascript">
function showGetResult( name )
{
     var result = null;
     jQuery.ajax({
        url: 'http://localhost/index.php',
        type: 'get',
        dataType: 'text/html',
        success:function(data)
        {
            alert(data);
            writeToDocument(data);
        } 
     });
}

function writeToDocument(data) {
   document.write(data);
}

showGetResult('test');
</script>

How to get AJAX post return value?, Your ajax call is asynchronous so your code doesn't halt at the $.ajax line, it continues on to the jQuery.ajax() | jQuery API Documentation[^]. The "A" in AJAX is asynchronous meaning that it happens while the rest of code carries on. In your case it means that by the time the done method returns a value the rest of your code has moved on so it can't do anything with the value. The proper way to do this would be to do your appending within the done handler of the ajax call.


How to Return AJAX Response from Asynchronous JavaScript Call, Asynchronous methods cannot easily return its value, unlike If you are using jQuery, you can easily do this by setting the async option to false. getJSON, $. get, and others, you will need to revise it to $.ajax and then use� function testAjax() { return $.ajax({ url: "getvalue.php" }); } returns a jqXHR object, which is a jQuery Deferred Object. To make it return a real promise, you can change it to - using the method from the Q wiki: function testAjax() { return Q($.ajax({ url: "getvalue.php" })); } or, using the method from the HTML5 Rocks article:


AJAX & Deferreds, AJAX — "asynchronous JavaScript and XML" — is a means of loading data mix sync and async operations; you get their return values back as arguments to� If a request with jQuery.get () returns an error code, it will fail silently unless the script has also called the global.ajaxError () method. Alternatively, as of jQuery 1.5, the.error () method of the jqXHR object returned by jQuery.get () is also available for error handling.


Jquery AJAX Result data retrieve back to client si, I have just created an AJAX request in velocity template and able to get Now I need to return the result data to the client side back at jquery "Result" parameter. posted data get inserted, Now, i want to send result value fail/success to client � Definition and Usage The val () method returns or sets the value attribute of the selected elements. When used to return value: This method returns the value of the value attribute of the FIRST matched element.