Counting number of different words in a txt file in Bash

shell script to count number of words in a file
linux count specific word in file
count occurrences of all words in file linux
count occurrences of word in file bash
count occurrences of word in file linux
count number of words in first 3 lines in unix
linux count occurrences of string in line
awk: count occurrences of string in file

Well, I do not know much about programming at bash, I'm new at it so I'm struggling to find a code to iterate all the lines in a txt file, and count how many words are different. Example: If a txt file has "Nory was a Catholic because her mother was a Catholic" So the result must be 7

$ grep -o '[^[:space:]]*' file | sort -u | wc -l

How to Count the Number of lines, Words, and, Characters in a Text , The most easiest way to count the number of lines, words, and characters in text file is to use the Linux command “wc” in terminal. The command “wc” basically means “word count” and with different optional parameters one can use it to count the number of lines, words, and characters in a text file. 5) pulled out the unique words: uniq outfile2.txt > I *know* there has to be a cleaner and easier way to do all that but that's all I could do. Now I'd like to use my new "" file to compare it to the original file to count how many occurrences of each of these words are found in the original.

How do I count the number of occurrences of a word in a text file with , In case you need to count WORD but not prefixWORD, WORDsuffix or (same physical layout of the file-system (due to practical reasons) among other things). I' ve currently ported bash(1.08) and gcc(1.40), and things seem to work. Using grep -c alone will count the number of lines that contain the matching word instead of the number of total matches. The -o option is what tells grep to output each match in a unique line and then wc -l tells wc to count the number of lines. This is how the total number of matching words is deduced.

You could also lowercase the text so words compares regardless of casing.

Also filter words with the [:alnum:] character class, rather than [a-zA-Z0-9_] that is only valid for US-ASCII, and will fail dramatically with Greek or Turkish.

#!/usr/bin/env bash
echo "The uniq words are the words that appears at least once, regardless of casing." |
  # Turn text to lowercase
  tr '[:upper:]' '[:lower:]' |
  # Split alphanumeric with newlines
  tr -sc '[:alnum:]' '\n' |
  # Sort uniq words
  sort -u |
  # Count lines of unique words
  wc -l

Count occurrences of a list of words in a text file, (words in File1, number of occurrences in File2) fgrep -of f1.txt f2.txt | sort | uniq -c | awk '{print $2 " " $1}' '{a[$1]++} END{for (x in a) print x, a[x]}' counts the words and prints the count. With GNU grep, you can do grep -Eof - f2.txt. That pipeline works on POSIX and Linux. Cancel and add another image. Using grep command. With egrep we can use different directives to count occurrences of word in file, for example to print the total number of occurrence of word " count " in /tmp/dummy_file.txt. copy. # egrep -c '\<count\>' /tmp/dummy_file.txt 6.

I would do it like so, with comments:

echo "Nory was a Catholic because her mother was a Catholic" |
# tr replace
# -s - squeeze
# -c - complementary
# [a-zA-Z0-9_] - all letters, number and underscore
# but complementary set, so all non letters, not numbers and not underscores.
# replace them by newline
tr -sc '[a-zA-Z0-9_]' '\n' |
# and sort unique and display count
sort -u | wc -l

Tested on repl bash.

Decided to use [a-zA-Z0-9_], because this is how GNU sed \w extension matches a word.

How to Count Word Occurrences in a Text File using Shell Script?, One such feature is to find patterns and count the number of occurrences of One such example is to count the number of occurrences of a specific word in a given file. The tr command translates one string to another. Show the total number of times that the word foo appears in a file named bar.txt. The syntax is: grep -c string filename grep -c foo bar.txt Sample outputs: 3. To count total number of occurrences of word in a file named /etc/passwd root using grep, run: grep -c root /etc/passwd To verify that run: grep --color root /etc/passwd

cat yourfile.txt | xargs -n1 | sort | uniq -c > youroutputfile.txt

xargs -n1 = put one word per line

sort = sorts

uniq -c = counts occurrences of distinct values


How to count occurrences of word in file using shell script in Linux , count occurrences of word in file linux. shell script to count number of use the associative arrays of awk to solve this problem in different ways. WC command, short for Word Count, is a command line tool in Unix/Linux systems used for printing newlines, counting number lines & characters in a file. The command can also be combined with other piping operations for general counting functions. To count the number of files in a directory, use the syntax below # ls -1 | wc -l

Finding the number of unique words in a file, find the number of unique words in a file using sort com- mand. simple shell for counting number of word that user need to find from file but i have get several� -c, --count prefix lines by the number of occurrences sort options:-n, --numeric-sort compare according to string numerical value -r, --reverse reverse the result of comparisons In the particular case were the lines you are sorting are numbers, you need use sort -gr instead of sort -nr, see comment

Wc Command in Linux (Count Number of Lines, Words, and , On Linux and Unix-like operating systems, the wc command allows Here is another example that will print the number of lines and the To to count only the number of words in a text file use wc -w followed by the file name.

How to count total number of word occurrences using grep on Linux , I want to find out how many times a word (say foo or an IP address) occurs in a text file using the grep command on Linux or Unix-like system?

  • Hi @Ed Morton, I like the answer (I upvoted it) but I believe it'd be better with a + to say "one or more non spaces" rather than the * which says "zero or more"... It's possible your answer handles that due to the -o flag (I'm not at a shell to test) but I think itd be more semantically correct if nothing else if edited.
  • If I used + instead of * then I'd need to add -E to support EREs or make other changes, I think * is fine.
  • Ok then, fair enough
  • Congratulations, you win today's "Useless use of cat" award :-) Try sed -r -e "s/[ ]+/ /g" -e "s/ /\n/g" filename | sort ... instead.
  • Ha. Fair enough :p
  • S'ok, it works even with that niggle so deserves an upvote.
  • sed -r -e "s/[ ]+/ /g" -e "s/ /\n/g" is the same as tr -s ' ' '\n'
  • I removed the wc -l to see how it works and I found out that it works but some equal words weren't removed because they are separeted by tabs, it was like this Ex: word word word
  • Why do you need sed there? tr can squeeze runs of non-letters before replacing them
  • To remove empty lines. Ex. Hello, my name is kamil. will result in an empty line from ,<space> beeing substituted by two \n\n.
  • echo Hello, my name is kamil. | tr -cs [:alpha:] '\n' does not generate empty lines..