Getting those rows from a table where status is still the same some days later?

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I got a MySql table with 3 columns status, mail and created_at. Now I would like to get those rows where status = 'somestatus' where the status is still 'some_status' for example 3 days later. It should be selected by column mail.

So if there is the same status 'somestatus' for the same mail 3 days later (in created_at), I want to select that data. Column created_at contains data in the form of 2016-08-01 14:13:27

If thats easier to fetch: I need all rows for the same mail where the status was and is still 'somestatus'. As soon as the status was 'somestatus' and later changed to any other than 'somestatus', I do not want that data. Easier?

Checks records for DATEDIFF between @startDate (set this to whatever), and that + 3 days

SET @startDate = '2019-11-23';
SELECT status, mail, created_at FROM table
WHERE status = 'somestatus' AND
MAIL = 'some value' AND
DATEDIFF(@startDate, (@startDate + INTERVAL 3 DAY)) = -3

After updated question this should do the trick.

Check a sub query in your where. And go through all Mails that have a different value then notpayed.

SELECT status, mail, created_at
FROM test
FROM `test`
where status != 'notpayed'
) to support above query

select rows in sql with latest date for each ID repeated multiple times , ID= t.ID and table.Date = t.max_dt. Note that if you have multiple equally higher dates for same ID, then you will get all those rows in result. I have a table that has an ID, a value, and a date. There are many IDs, Values, and dates in this table. Records are inserted into this table periodically. The ID will always stay the same but occasionally the value will change. How can I write a query that will give me the ID plus the most recent time the value has changed?

  Id as Id,
  Client_Id as Client_Id,
  Name as Name,
  Value as Value,
  date as date,
  row_number() over (Partition by client_id,name,value order by id) as row_num
FROM <your_table>) a
WHERE a.row_num = 1;

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You have to use DATEDIFF function which returns difference between two dates in days, like this:

SELECT status, mail, created_at
FROM tbl
WHERE status = 'somestatus' AND DATEDIFF(NOW(), created_at) = 3

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  • Do you want to retrieve all rows which did not change their status in 3 days? I suggest using a second column status_changed_at containing info on when was the last time status was modified (you would need to update it along with status).
  • I cant add any columns. I just need those rows (by column mail) for which the status is still the same 3 days later (according to created_at).
  • are all of these records available already (for example 2016-08-01, 2016-08-02, 2016-08-03, 2016-08-04). Or is this going into the future (so today +3 days)
  • The dates are all in the table already, I just need to select them somehow.
  • @Arnie You can't really do that without recording last status change date / history of updates.
  • Thanks, but here I have to set the startdate manually which I cant, because its dynamic. Is there a way to set it dynamically in order to get the desired results?
  • What do you mean with i have to get the startDate dynamically? Earlier you said all dates were in the past so there is no corrolation between now and then
  • Yes, the dates are all in the database already, each in a separate row. But I need this to work without setting the start date. Like this: Return all rows where the mail is the same, status is somestatus and created_at is at least 3 days away from the previous created_at for the same mail.
  • is mail always 3 records of the same unique "id or along those lines". With a max of 3 records per unique mail?
  • @Arnie if you could show what your table looks like with some data in it, it could greatly improve our capability to help you
  • Try to explain what you have done in your solution, this will be a lot more helpful to other users rather than a code only answer
  • Looks good, but does not work I think, thats becasue of the NOW(). It should always compare created_at with created_at. Something like DATEDIFF(created_at, created_at) = 3