How to count certain word in string using C++

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How to counting the same word in a string

Input

Number of String

String1 = dadymathewdadreadad

String2 = sdgfghhjdjrjjyjjrtfdhe

Search = dad

Output

Number of dad in string1 = 3

Number of dad in string2 = 0

Code:
#include <iostream>
#include <string.h>

using namespace std;
int main() {

    string str[50];
    int n;

    cin>>n;

    for(int i = 0; i < n;i++) {
        cin>>str[i];
    }

    for(int i = 0; i < 50;i++) {
        if(substr(i,4) == "dad"){
            n += 1;
        }

    }
    cout<<n;
    return 0;
}
ERROR

In function 'int main()': [Error] 'substr' was not declared in this scope

One trick you could use here would be to just replace the search term (e.g. dad) with empty string, and then compare the length of the string before and after the replacement.

string input = "dadymathewdadreadady";
string search = "dad";
int size_orig = input.size();
replace(string, search, "");
cout << "number of 'dad' is: " << (size_orig - input.size()) / search.size();

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You can use the find() member function of std::string, adjusting the start position after every successful find until the end of the string:

#include <string>

int count(const std::string& sentence, const std::string& word)
{
    int total = 0;
    size_t start = 0;
    size_t pos = 0;

    while ((pos = sentence.find(word, start)) != std::string::npos)
    {
        ++total;
        start = pos + word.size();
    }

    return total;
}

int main()
{
    std::string input = "dadymathewdadreadady";
    int c = count(input, "dad");
    return 0;
}

Counting words in a string - c programming, You needed int words(const char sentence[]) { }. (note braces). For loops go with ; instead of , . Without any disclaimer, here's what I'd have written: See it live� How to counting the same word in a string Input Number of String String1 = dadymathewdadreadad String2 = sdgfghhjdjrjjyjjrtfdhe Search = dad Output Number of dad in string1 = 3 Number of da

Other Solution:

#include <iostream>
#include <string>
using namespace std;

int main(){
    int n; 
    string s[50];
    int c;
    cin>>n;
    for (int i=0;i<n;i++){
        cin>>s[i];
    }
    for (int i=0;i<n;i++) {
        c=0;
        int found=s[i].find("jack");
        while(found!=string::npos){
            found=s[i].find("jack",found+1);
            if(found) c++;
        }
        cout<<c<<endl;
    }
}

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C program to count number of words in a string, How to find total number of words in a given string using loops in C programming. Logic to count total number of words in a string. Example. Input C program to count the frequency of each character in a string – In this article, we will describe the numerous means to count the frequency of each character in a string in C programming. Suitable examples and sample programs have also been added so that you can understand the whole thing very clearly.

Comments
  • std::string::find is your friend
  • You forgot to call substr on the object: str.substr(i,4). Vote to close as typo. Also you can do cin >> str.
  • @bolov str is an array
  • There are multiple problems with your code, besides the error you get. For example, is n the number of strings you should read, or the number of matches in each string? It can't be both simultaneously. You also have no bounds checking, neither for the input nor for the checking.
  • And please take some time to refresh how to ask good questions, as well as this question checklist. It's unclear if you ask about the error and how to fix it, or if you ask about "[h]ow to counting the same word in a string".