How do you eliminate items from nested lists

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Given a list of ranked ballots and a list of candidates to eliminate, I need to return a new list of ranked ballots where all the candidates in the list of candidates to eliminate have been removed.

This is the code I've tried so far

import doctest 

def eliminate_candidate(ballots, to_eliminate):
    '''
    (list, list) -> list

    >>> eliminate_candidate([['NDP', 'LIBERAL'], ['GREEN', 'NDP'], \
    ['NDP', 'BLOC']], ['NDP', 'LIBERAL'])
    [[], ['GREEN'], ['BLOC']]
    >>> eliminate_candidate([], [])
    []
    >>> eliminate_candidate([[]], [])
    [[]]
    '''
    new_list = []

    # Copy ballots onto new list
    for item in ballots:
        new_list.append(item)

    for item in new_list:
        for element in item:
            if element in to_eliminate:
                item.remove(element)

    return new_list

My first doctest is failing, giving me this output instead:

[['LIBERAL'], ['GREEN'], ['BLOC']]

This is the function required. It searches through the sublists:

def eliminate_candidate(ballots, to_eliminate):
    return [[party for party in ballot if party not in to_eliminate] for ballot in ballots]

ballots = [['NDP', 'LIBERAL'], ['GREEN', 'NDP'], ['NDP', 'BLOC']]
to_eliminate = ['NDP', 'LIBERAL']

print(eliminate_candidate(ballots, to_eliminate))

Output:

[[], ['GREEN'], ['BLOC']]

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Using sets becomes pretty easy!

ballots = [['NDP', 'LIBERAL'], ['GREEN', 'NDP'], ['NDP', 'BLOC']]
to_eliminate = ['NDP', 'LIBERAL']

result = [list(set(x) - set(to_eliminate)) for x in ballots]
result
[[], ['GREEN'], ['BLOC']]

Or:

result = [list(set(x).difference(to_eliminate)) for x in ballots]
result
[[], ['GREEN'], ['BLOC']]

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ballots = [['NDP', 'LIBERAL'], ['GREEN', 'NDP'], ['NDP', 'BLOC']]
to_eliminate = ['NDP', 'LIBERAL']

res = [[element for element in b if element not in to_eliminate] for b in ballots]
print(res)

prints

[[], ['GREEN'], ['BLOC']]

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11. Lists — How to Think Like a Computer Scientist: Learning with , Although a list can contain another list, the nested list still counts as a single We can also remove elements from a list by assigning an empty list to them:. Create a dictionary, using the List items as keys. This will automatically remove any duplicates because dictionaries cannot have duplicate keys.

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Comments
  • Don't use list as the name of a variable!
  • Your output seems to be different to the requirement stated by the OP.
  • But that his output is not as the stated requirement.