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I will check if a word exists in a list. How can I show the position of this word?
list = ["word1", "word2", "word3"] try: print list.index("word1") except ValueError: print "word1 not in list."
This piece of code will print
0, because that's the index of the first occurrence of
Python List index(), The index() method returns an integer that represents the index of first match of specified element in the List. You can also provide start and end positions of the List, where the search has to happen in the list. Following is the syntax of index() function with start and end positions. start parameter is optional. The list-style-position property specifies the position of the list-item markers (bullet points). list-style-position: outside; means that the bullet points will be outside the list item. The start of each line of a list item will be aligned vertically: Coffee - A brewed drink prepared from roasted coffee beans Tea; Coca-cola
To check if an object is in a list, use the
>>> words = ['a', 'list', 'of', 'words'] >>> 'of' in words True >>> 'eggs' in words False
index method of a list to find out where in the list, but be prepared to handle the exception:
>>> words.index('of') 2 >>> words.index('eggs') Traceback (most recent call last): File "<stdin>", line 1, in <module> ValueError: 'eggs' is not in list
Python – Get Index or Position of Element in List, end (Optional) - The position from where the search ends. Returns : Returns lowest index where the element appears. Error : If any element� Position [expr, pattern] tests all the subparts of expr in turn to try and find ones that match pattern. Position returns a list of positions in a form suitable for use in Extract, ReplacePart, and MapAt. The form is different from the one used in Part. Position looks only for matches to values in Association objects that appear in expr.
you can use
Python list, Given a list of N integers, find the maximum and minimum element's position in the list. Examples: Input : 3, 4, 1, 3, 4, 5 Output : The maximum is at position 6 The � Note that there is variance among browsers regarding behavior when a block element is placed first within a list element declared as list-style-position: inside.Chrome and Safari both place this element on the same line as the marker box, whereas Firefox, Internet Explorer, and Opera place it on the next line.
The following code:
sentence=["I","am","a","boy","i","am","a","girl"] word="am" if word in sentence: print( word, " is in the sentence") for i, j in enumerate(sentence): if j == word: print("'"+word+"'","is in position",i+1)
would produce this output:
"am" is in position 1 "am" is in position 5
This is because in python the indexing starts at 0
Hope this helped!
Python, Extend the list by appending all the items in the given list; equivalent to a[len(a):] = L . list. insert (i, x). Insert an item at a given position. position: fixed; An element with position: fixed; is positioned relative to the viewport, which means it always stays in the same place even if the page is scrolled. The top, right, bottom, and left properties are used to position the element. A fixed element does not leave a gap in the page where it would normally have been located.
using enumeration - to find all occurences of given string in list
listEx=['the','tiger','the','rabit','the','the'] print([index for index,ele in enumerate(listEx) if ele=='the'])
[0, 2, 4, 5]
5. Data Structures — Python 2.7.18 documentation, Extend the list by appending all the items from the iterable. Equivalent to a[len(a ):] = iterable. list.insert(i, x). Insert an item at a given position. The� Given a string and a character, your task is to find the first position of the character in the string. These types of problem are very competitive programming where you need to locate the position of the character in a string. Let’s discuss a few methods to solve the problem. Method #1: Using Naive Method
Python : methods of list objects, Find index position of first occurrence of 'Ok' in the list iterate over the list elements by index positions, to find the index of element in list i.e.. Types of Marketing Jobs . See below for a list of marketing job titles for a variety of different positions in marketing, advertising, and public relations, including content marketing, account and brand management, communications, digital marketing, and more.
Python: Find index of element in List (First, last or all occurrences , maxminposition(A, n) /* A is a user input list and n is the size of the list.*/ Step 1: use inbuilt function for finding the position of minimum element. Comparable Positions – Use this section to list any positions in the department that have a similar role or level of responsibility. It is useful to the Compensation Analyst during the classification process and helps to ensure positions are classified consistently. On the following page, you will find an example of the Position Details section.
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- You do it by searching for folks who already asked this question and reading the answers already presented here.
- Either stackoverflow.com/questions/364621/python-get-position-in-list or stackoverflow.com/questions/3989016/… will answer your question.
- Possible duplicate of How to get item's position in a list?
- Personally, I think the exception approach is valid iff you expect the word to be in the array, but maybe that's just me. Otherwise, you could test for the presence of the word in the list before finding its index, as shown by jleedev.
- @Lee-Man he asked for a function which would return the index of a value in a list, and I gave that to him, with all use cases. I agree that jleedev's solution is more comfortable, but I tried to provide all use cases for
- IMHO using
try/exceptis the most efficient approach since it only searches for a match once, and is totally "Pythonic" in the sense that it employs the [EAFP ](docs.python.org/glossary.html#term-eafp) (Easier to Ask Forgiveness than Permission) style of programming.
- @Lee-Man: Ignoring double lookups, if exceptional cases are rare, then code using exceptions will have better average performance than the alternative.