## How to accept the only positive element of an array generated by the random number generator?

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I want to keep the third element of the arrays generated by using random numbers. The first two elements can be positive or negative, but the third element will always be positive otherwise a new list of random numbers generated until they satisfy this condition.

I have tried the following, but it does not work:

coord = np.linspace(0, (N)*0.9, num=N) trial = np.ndarray.copy(coord) for i in range(1, N): delta = (2 * np.random.rand(3) - 1) trial[i] += delta if trial[i,2] < 0.0: break else: continue

Very simple:

coord = np.linspace(0, (N)*0.9, num=N) trial = np.ndarray.copy(coord) for i in range(1, N): while True: delta = (2 * np.random.rand(3) - 1) trial[i] += delta if trial[i, 2] > 0: break trial[i] -= delta #Return to the previous values for the next attempt

**Create Arrays of Random Numbers - MATLAB & Simulink,** Use rand, randi, randn, and randperm to create arrays of random numbers. allows you to control the seed and algorithm that generates random numbers. MATLAB offers several generator algorithm options, which are summarized in the � parameters : array of integers number of integers to store in the array description: generate "number" random numbers from 1 to 100 and store them in positions [0..number-1] So the array is always the same size, but may be filled with a different number of random values on each run void printArray (int array[], int number) parameters : array of

To make numbers absolute, use the `abs()`

method.

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Your question is very confusing so, this is how I understand it. Besides, your code doesnt work, because coord has different dimensions than trial so I made some changes

import numpy as np N = 10 sub_num = 3 coord = np.zeros(shape=[N,sub_num]) trial = np.ndarray.copy(coord) def delta(): while True: delta = (2 * np.random.rand(sub_num) - 1) if delta[-1]>0: return delta for i in range(1,N): trial[i] += delta()

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##### Comments

- what is trial array here?
- Here trial is another list of arrays.
`python coord = np.linspace(0, (N)*0.9, num=N) trial = np.ndarray.copy`

- I edited the question
- Hello Aryerez. Thanks for the answer, but I do not want delta to have positive third element of third column. I want trial will be accepted if it has a third positive element. I edited your answer above.
- @Mahesh I've edited it. See if now that's what you wanted.
- I want only the third element to be absolute. The first two elements can be positive or negative.
- @dommetysk Your answer may be correct, but you could have included some information how to make only the third number positive, as clearly asked in the question.
- overwrite that specific array element with its absolute value:
`trial[i][2]=abs(trial[i][2])`