Filter Array of Objects based on checkboxes

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Hello I want to filter my data based on checkboxes checked.

I have 3 checkboxes.

<input type="checkbox" name="shoes" value="shoes" class="storesCheckBox" />
<input type="checkbox" name="clothes" value="clothes" class="storesCheckBox" />
<input type="checkbox" name="sports" value="sports" class="storesCheckBox" />

and my stores data is

// my stores
var stores = [
    {
        id: 1,
        store: 'Store 1',
        storeType: "shoes"
    },
    {
        id: 2,
        store: 'Store 2',
        storeType: "clothes"
    },
    {
        id: 3,
        store: 'Store 3',
        storeType: "sports"
    },
    {
        id: 4,
        store: 'Store 3',
        storeSells: "shoes"
    }
]

So, If I check shoes checkbox, I want to filter the data based on storeType shoes. So I wrote

var getStores = stores.filter(function (store) {
    return store.storeType === 'shoes';
});

But Now, if I check clothes and shoes is already checked. I want to filter shoes + clothes data. And If I uncheck, shoes again I want to filter only clothes data. It can be any number of checkboxes depending on the store type. can you please help me out with this?

You can try this:

var storeTypesSelected; //array of the types checked
var getStores = stores.filter(function (store) {
    return storeTypesSelected.indexOf(store.storeType) > -1;
});

Use checkboxes to filter to a new array of objects?, This array itself, with all of its objects it going to generate a d3 lat/lon map. Also Based on that, I just sent this to stackoverflow. I want to use checkboxes to filter by "job" and then have a new separate array of objects that is� I would like to filter the array to produce a separate array based on a 'filters' object. For example if my filters are: const FILTERS = { age: 32, name: 'John', occupation: '' }; The new array should be empty as no people in the array have the combination of 32 and John. However if my filters are:

From the checked checkboxes, construct an array (or Set) of the selected values. Then, when iterating over the array, check whether the current storeType is included in the collection:

var stores = [{
    id: 1,
    store: 'Store 1',
    storeType: "shoes"
  },
  {
    id: 2,
    store: 'Store 2',
    storeType: "clothes"
  },
  {
    id: 3,
    store: 'Store 3',
    storeType: "sports"
  },
  {
    id: 4,
    store: 'Store 3',
    storeType: "shoes"
  }
];

document.addEventListener('change', () => {
  const checkedValues = [...document.querySelectorAll('.storesCheckBox')]
    .filter(input => input.checked)
    .map(input => input.value);
  const filteredStores = stores.filter(({ storeType }) => checkedValues.includes(storeType));
  console.log(filteredStores);
});
Shoes: <input type="checkbox" name="shoes" value="shoes" class="storesCheckBox" />
Clothes: <input type="checkbox" name="clothes" value="clothes" class="storesCheckBox" />
Sports: <input type="checkbox" name="sports" value="sports" class="storesCheckBox" />

Filtering an array according to 7 checkboxes in a form, There are 7 checkboxes, each associated with an object. seatConcession = [ { id: 1� I want to use checkboxes to filter by "job" and then have a new separate array of objects that is filtered (leaving the original array intact). I'd like the new array to update anytime checkboxes change. So if "teacher" is checked, you get a new array of first object only.

All you need is to hold the checkbox values for filtering in an array.

var elems = document.getElementsByClassName("storesCheckBox");
var list = [];
for(var i=0; elems[i]; ++i){
      if(elems[i].checked){
           list.push(elems[i].value);
      }
}
var getStores = stores.filter(function (store) {
    return list.indexOf(store.storeType) >= 0;
});

The return statement will do the filtering with indexOf function.

Angular Checkbox Filtering, You're attempting to handle the data binding yourself by creating arrays to store objects based on the click event. Angular does the two way binding for you. Angular Filter Checkboxes. posted on April 13, 2017 by long2know in angular, plunker. A fellow developer asked me how filter Pipes could be used for filtering based on checkboxes. Using the existing code samples I’ve created, I endeavored to put together a little demo of how this can be achieved.

Filtering Items In A List, Learn how to effectively filter items by combining checkboxes, list items, custom icon next to them depending on what value their data-type attribute stored: loop that uses the array's filter method and avoids using a for loop altogether. sessionStorage � Looping Through an Array � Arrays and Objects. I’ll show you an example implementation of how you can handle multiple checkboxes in React.js. Let’s create some config file for the checkboxes: Parameter destructuring is used in the function…

How to get all selected checkboxes in an array using jQuery , Example 1: This example selects the checked checkboxes by a selector and then calls the .each() method to each element and finally push them into the array. Optional. Specifies an array of filter arguments. A valid array key is a variable name, and a valid value is a filter name or ID, or an array specifying the filter, flags and options. This parameter can also be a single filter name/ID; then all values in the input array are filtered by the specified filter: add_empty: Optional. A Boolean value.

.map(), Categories: Traversing > Filtering If you wish to process a plain array or object, use the jQuery.map() instead. As the return value is a jQuery object, which contains of a collection of elements. Consider a form with a set of checkboxes in it:� It specifies the item(s) to add to the array. Return value: It returns a number, which represents the new length of the array. Example 1: This example selects the checked checkboxes by a selector and then calls the .each() method to each element and finally push them into the array.

Comments
  • @CertainPerformance yes! sorry I will fix it.
  • store your conditions into an array, then in the filter use includes method.
  • Did any of the answers work for you?

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