## Division by 10 in hexadecimal

hex to decimal
hex to binary

I need to separate the last 6 decimal positions of hexadecimal number from the rest of the number.

Division with 10 in decimal is the same like right shift 4 times (x >> 4) in hexadecimal. I tried to shift right but I never get the correct value.

```Hex: 0x7A 11F8 5EE0
Dec: 524.297.500.000
```

I want to separate the last 6 decimal position into a new variable:

```524.297.500.000 -> 524.297
a = 524.297
b = 500.000
```
```repeat time
0x7A 11F8 5EE0 >> 4
```

I am working with hexadecimal numbers.

Questions:

1. How many times shall I shift right to cut the last 6 decimal position?
2. Is bit shifting (division by 10) faster in binary or in hexadecimal?

As the various comments say, shifting is not going to achieve what you want. And what you want is itself unclear!

However, you can achieve what it looks like you need with conventional division and modulo operators. Something like:

```int x = 524297500;
int a = x / 1000; // 524297
int b = x % 1000; // 500
```

This is just a quick-and-dirty answer. Also, you'll notice I used a smaller number than you and separated the bottom 3 (not 6) decimal places. That's just because your example was too big to fit in an int (very often 32-bits long) and I wanted to show the idea, not the gritty details of the integer type system.

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[all numbers decimal]

If you (for whatever reason) need to divide an integer by 10 using bit shifting you 1st need to convert the integer to be divided into its BCD representation.

Depending on whether you used BCD or packed BCD you needed to shift to the right by 8 bit or 4 bit to divide by 10.

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Separately, shifting by some number of places is the same as dividing by the place value. I wonder if that's where your confusion comes from.

Consider this case in decimal:

```value: 213423
shifted right by one digit: 21342  (the 3 gets discarded)
```

We can see this is the same as dividing by 10 and rounding down:

```value: 213423
divide by 10: 21342.3
round down: 21342
```

The shift by one digit and the divide by 10 give the same answer because each digit has a place-value of 10.

Now in hexadecimal each digit has a place value of 16 (in decimal), so shifting right by one hex digit is the same as dividing by 16 (in decimal).

Finally, in binary each digit has a place-value of two, so shifting by one digit is the same as dividing by two (in decimal). And because of how binary works, shifting by four is the same as dividing by 16 (in decimal).

So everyone is correct in saying something like "a number isn't decimal or hex, but you can represent a number as decimal or hex". But the shift operation is connected to the representation. A shift by 1 in decimal is the same as divide by 10. The final wrinkle is that in C, your only choice is shifting in binary, which is equaivalent to the decimal division by 2, 4, 8, 16...

I hope this helps rather than muddying the waters further!

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How to divide hexadecimal number, a few examples of how to solve hexadecimal addition and division Then subtract F from 10 to get 1, which you write below and bring down� This calculator is designed to multiply and divide values of any Hexadecimal (Hex) numbers. Enter the primary number (in hex; make sure it is valid) first then enter the secondary number (also in hex) for the calculation and click on Calculate.

Decimal to Hexadecimal Converter, C, D, E, F. DECIMAL, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15 So the integer division result is 70 (throw out anything after the decimal point). Record it � For example, 10 in decimal is A in hex, 100 in decimal is 64 in hex, while 1,000 in decimal is 3E8 in hex. Hex numbers have signs, just like decimal ones, for example -1e is equal to -30 in decimal. Hex numerals are used mostly in computing: computer system designers , software engineers and programmers as a convenient representation of the

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• @FredLarson No problem, you have to shift by `3.3219280948873623478703194294893901759...` places ;)