why f is placed after float values?

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I don't know why f or F is placed after float values in Java or other languages? for instance,

float fVariable = 12.3f;

any features other than indicating that this is a float value?

by default 12.3 is double literal, So to tell compiler to treat it as float explicitly -> it uses f or F

Why would you append an F to the end of a value of a floating point , Like 3.5 thats a double literal, as opposed to 3.5F which is a float. For details check this link. why f is placed after float values? 574 views �. uses float constants. (The constant 0.0 usually declares a double in Objective-C; putting an f on the end - 0.0f - declares the constant as a (32-bit) float.) CGRect frame = CGRectMake(0, 0, 320, 50); uses ints which will be automatically converted to floats. In this case, there's no (practical) difference between the two.

If we float x=3.5f, why do we put f after the data while we already , 5 years, 5 months ago. f = float. In c a value of 1 is an integer and 1.0 is a double, you use f after a decimal number to indicate that the compiler� A float is as precise as as any number that can be stored in 4 bytes. When the "f" is left out, it is assumed that the constant is a double, which is accurate out to 8 bytes. Roughly, this means that floats can go out 6 or 7 decimals, while doubles go out 15 or 16. Doubles are much bigger though, so they are not always appropriate (es

float and double can only provide approximate representation values for some values. e.g. 12.3 or 0.1

The difference is that float is not as accurate (as it has less precision, because its smaller)

e.g.

System.out.println("0.1f == 0.1 is " + (0.1f == 0.1));
System.out.println("0.1f is actually " + new BigDecimal(0.1f));
System.out.println("0.1 is actually " + new BigDecimal(0.1));

prints

0.1f == 0.1 is false
0.1f is actually 0.100000001490116119384765625
0.1 is actually 0.1000000000000000055511151231257827021181583404541015625

So 0.1 is the closest representation in double and 0.1f is the closest representation in float

What does that "f" signify?, In Java, floating point numbers are numbers that have a decimal part to them. Here the variable c is attempting to store a float value with 12 digits after the decimal. f or d to the end of the decimal, the value will be stored as a double in Java. College & Career Guidance Courses � College Placement Exams � Entrance� Because otherwise it defaults to double, which is a more commonly used floating point type than float. From the Java Language Specification, section 3.10.2: A floating-point literal is of type float if it is suffixed with an ASCII letter F or f; otherwise its type is double and it can optionally be suffixed with an ASCII letter D or d (§4.2.3).

float fVariable = 12.3; is fine. but when you use only float value(without any identifier) in any expression that time you need to tell compiler that value is float hence we use suffix "f" after value. example

float fl =13f/5f;

here 13 and 5 are float values.

Java: Floating Point Numbers, Because the first value includes an “e-I-5”, the decimal is moved to the right five note that the f must be placed after // the value for float types Notice that all but� This seems to infer to a function header. The function return type is float, that's why the first float is given. 'f' is the name of the function. 'float x' given in parenthesis is the declaration of the formal parameter 'x' which accepts the float value that is passed at the function call. 2.5k views · View 2 Upvoters

During compilation, all floating point numbers (numbers with decimal point) default to double.

Therefore, if you don't want your number to double and just want it as float, you have to explicitly tell the compiler by adding a f or F at end of the literal constant.

C# Programming: From Problem Analysis to Program Design, When a float value exists as 0.9f we lose some values after the decimal when converting the floating point value to an integer. void Start () { float a = 0.9f; int b� The last example is a computer shorthand for scientific notation. It means 3*10-5 (or 10 to the negative 5th power multiplied by 3). The term floating point is derived from the fact that there is no fixed number of digits before and after the decimal point; that is, the decimal point can float

Learning C# Programming with Unity 3D, Note the semicolon after the declaration. void main() 5 { float x, output; int y; 6 printf(“\nEnter base x (decimal value): ”); 7 scanf(“%f”, &x); 8 printf(“\nEnter index y (integer value): ”); 9 scanf(“%d”, &y); 10 that is placed after the keyword return . An f suffix is used to denote a literal of type float. Best practice Always make sure the type of your literals match the type of the variables they’re being assigned to or used to initialize.

RUDIMENTS OF COMPUTER SCIENCE: PART 1, The ' %f ' conversion prints its argument in fixed-point notation, producing output %A ' conversions are meant for representing floating-point numbers exactly in Pad the field with zeros instead of spaces; the zeros are placed after any sign. Assuming you're talking about round the value for printing, then Andrew Coleson and AraK's answer are correct:. printf("%.2f", 37.777779); But note that if you're aiming to round the number to exactly 37.78 for internal use (eg to compare against another value), then this isn't a good idea, due to the way floating point numbers work: you usually don't want to do equality comparisons for

Floating-Point Conversions (The GNU C Library), In Java SE 8 and later, you can use the int data type to represent an unsigned Data Type, Default Value (for fields). byte, 0. short, 0. int, 0. long, 0L. float, 0.0f. Float Out. The float-out function is generally performed at the end of a day’s trading. By floating out, the operator can reconcile the cash amount in the drawer. When performing the float-out ensure all cash is counted, including the float value.

Comments
  • Same Question: Java: Why do you need to specify a 'f" in a float literal?
  • Because otherwise they aren't float values, they are ints or doubles.
  • @DeepakRaghuwanshi It is more than a little immodest to describe your own blog as 'the best ever explanation for this'. The fact that it is actually a load of rubbish doesn't improve matters.
  • Likewise every whole literal is by default int. So when we assign a literal this way: long x = 2147483648; (this is 2^31 > int range but Compiler still consider this as int literal. so we need to tell compiler that this is long by adding L or l ) long x = 2147483648L;
  • It's worth noting that if d is the best double representation of some numerical quantity x, float f=(float)d will be the closest float to some value that's within a part per trillion of x, even though it requires a typecast. By contrast, if f is the best float representation of some numerical value x, double d=f won't require a typecast even though it will often be nowhere close to the best double representation of x, and may be off by hundreds of orders of magnitude. I find it ironic that float f=(float)(1.0/10.0) needs a cast, but double d=1.0f/10.0f doesn't.
  • " So, the compiler will force you to indicate that you really want to perform the narrowing conversion, by signaling a compile error for something like this:" Should that also apply to long though
  • @Perception why do you write For obvious reason in first point can you please elaborate it ?
  • Great! but which one is actual(mathematical) 0.1 and which one is equal to String.valueOf("0.1") ?
  • Only the BigDecimal is exactly equal. The rest will give the right answer when converted to a String if used correctly.
  • float fVariable = 12.3; is not correct. you always need to add f prefix for float assignment. by default every real number is double.
  • It is good to have you in stackoverflow. Your answer is okay however other colleagues already gave the same information. A contribution is really valued if it wasn't mentioned before. Welcome on board..