How to store in different lists?
I have two list as follows
l1 = [2,4,3] l2 = [4,5,6,7,8,9,10,11,12]
I want to make a three lists like
l2. I can do it different way but I need to do by using loop.
I already tried something as follows:
a =  b =  c =  a.append(l2[0:2]) b.append(l2[2:4+2]) c.append(l2[4+2:])
I want it using loop where element of
l1 will be the size of each new list.
List comprehension with islice
from itertools import islice l1 = [2,4,3] l2 = [4,5,6,7,8,9,10,11,12] il2 = iter(l2) l = [list(islice(il2, x)) for x in l1] print(l) # [[4, 5], [6, 7, 8, 9], [10, 11, 12]]
Testing five methods posted here using timeit on the dataset l1, l2 in Jupyter notebook, with libraries preloaded. Pok Fung Chan post had fastest method.
Method 1. pok fung chan -- 100000 loops, best of 3: 2.17 µs per loop Method 2: ncica -- 100000 loops, best of 3: 2.93 µs per loop Method 3: darrylg -- 100000 loops, best of 3: 4.02 µs per loop Method 4: RoadRunner -- 100000 loops, best of 3: 6.38 µs per loop Method 5: Rakeesh -- 100000 loops, best of 3: 8.76 µs per loop
input from cin is white space delineated which includes spaces. std::cin >> current stores only the first word which was typed. In order to get two words you'd have to call cin twice, or switch to a different way of getting user input.
For the following code, the resulting lists are stored in the "result" list.
The variable "counter" is used to indicate the starting index and "x" is each element in l1, so l2[counter:counter+x] can get the list that you want. This may not be the shortest code but I guess it is clear and concise. Hope that helps!
l1 = [2,4,3] l2 = [4,5,6,7,8,9,10,11,12] result =  counter = 0 for x in l1: result += [l2[counter:counter+x]] counter += x print(result) [[4, 5], [6, 7, 8, 9], [10, 11, 12]]
Step 1: First of all we will create a console application named InterviewQuestionPart6. Step 2: Now we will create a list that is a list of objects and then we will store a different type of data, like
you can do it on this way:
l1 = [2,4,3] l2 = [4,5,6,7,8,9,10,11,12] l2_ = l2.copy() result =  for item in l1: result.append(l2_[:item]) del l2_[:item] a,b,c = result print (a) print (b) print (c)
[4, 5] [6, 7, 8, 9] [10, 11, 12]
C# Nested Lists: Create 2D List or Jagged List Use a nested List to store data in two dimensions. Nested lists are like jagged or 2D lists.
Using a list comprehinsion and
l1 = [2,4,3] l2 = [4,5,6,7,8,9,10,11,12] print([[l2.pop(0) for _ in range(i)] for i in l1])
[[4, 5], [6, 7, 8, 9], [10, 11, 12]]
Create drop down list but show different value in drop down list cell. To finish this task, please do with the following step by step: 1.Create a range name for the cell values you want to use in the drop down list, in this example, I will enter the name dropdown in the Name Box, and then press Enter key, see screenshot:
You can convert
l2 to a
collections.deque to allow O(1) pops from the left using
from collections import deque l1 = [2,4,3] l2 = deque([4,5,6,7,8,9,10,11,12]) result = [[l2.popleft() for _ in range(x)] for x in l1] print(result) # [[4, 5], [6, 7, 8, 9], [10, 11, 12]]
Try to keep each different type of vegetable in a different drawer. Fruits and vegetables need to be able to breathe and let off gases. If the gases get trapped, the food will rot faster.
Store the shoes you wear all the time near the entrance to your home on a small shoe rack or in the closet. Seasonal shoes should be put away in storage when not in use; shoes you wear occasionally should be put in your closet, either on a shoe rack or in a hanging shoe organizer.
List Vs Array . Arrays are memory-efficient.Lists are built on top of arrays. Because of this, Lists use more memory to store the same data. Array is useful when you know the data is fixed length, or unlikely to grow much.
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