How to exclude certain elements from a List

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I have a List with the following elements.

List<String> numbers = new ArrayList<String>();
numbers.add("1");
numbers.add("2");
numbers.add("3");

How do I get a subset of the List without say "1"? Is there a simpler function which will work against a List of any type.

You could use Guava to create a filtered Collection view:

Collection<String> filtered = Collections2.filter(numbers,
    Predicates.not(Predicates.equalTo("1")));

That's a live view of the original List, so it's very efficient to create but might not be efficient to use depending on how you need to use it and how small the filtered collection is compared to the original. You can copy it to a new list if that will work better:

List<String> filteredList = Lists.newArrayList(filtered);

The simplest way to create a copy list containing all elements except the one you don't want is to use a simple for loop:

List<String> copy = new ArrayList<String>();
for (String number : numbers) {
  if (!"1".equals(number))
    copy.add(number);
}

If you want to modify the original list instead, numbers.removeAll is what you want (as mentioned by @Robin Green).

java - How to exclude certain elements from a List, I have a List with the following elements. List<String> numbers = new ArrayList<​String>(); numbers.add("1"); numbers.add("2"); numbers.add("3");. How do I get a​  Remove an element from List by Index using list.pop() list.pop(index) In python list’s pop() function will remove the element at given index and also returns the deleted element. If index is not given then it deletes the last element. For examples, We have a list of ints i.e.

The question is ambiguous.

numbers.remove("1"); will remove the first instance of "1" in any list. If you might have duplicate elements, use numbers.removeAll (Collections.singletonList ("1")); to remove all of them.

If on the other hand you want to get a subrange of the list, use the subList method.

Excluding items from a list that are in a certain range using list , You can simplify by iterating b 's elements directly, but your original code works for me, too: a = [10.0, 20.0] b = [1.0, 10.0, 15.0, 20.0, 30.0,  Exclude values in one list from another with formula. You can apply the following formulas to achieve it. Please do as follows. 1. Select a blank cell which is adjacent to the first cell of the list you want to remove, then enter formula =COUNTIF ($D$2:$D$6,A2) into the Formula Bar, and then press the Enter key. See screenshot:

you can take a look at Guava libraries which has a filter method on any collection type. here are some examples for your reference. If you don't want to use third party libraries, you have to manually iterate the list and need to copy the elements which doesn't match your criteria.

Remove All Occurrences of a Specific Value from a List, remove(1), but the element's index we want to remove is 0. Calling List.remove() shifts all elements after the removed one to smaller indices. In  Figure 2: Example List After Removing List Element. As you can see based on Figure 2, we just removed the second list element of our example list. In order to delete this list component, we just needed to write a square bracket, a minus sign, and the positioning of the list element we wanted to delete (i.e. [- 2]) behind the name of our list.

I think this could help you out:

final List<String> numbers = Arrays.asList("1", "2", "3");

final List<String> filtered = numbers.stream()
                                     .filter(num -> !"1".equals(num))
                                     .collect(Collectors.toList());

How to remove or exclude specific elements from a C# , Except that we can execute those methods on various data, like arrays, lists, and, indeed, queues. Two of those methods are especially helpful  Each element of the list is located with a certain index assigned to them. To access each element from the list, you have to use the same index term. If you know the index of the list element, you can delete list element easily using the del(). Check the example given below to delete your own list elements.

List.subList(int fromIndex, int toIndex)

Edit: Possible that I didn't understand the question.

@Op. Do you want to remove items of a certain value, or do you want to have a view between two indices?

Python List remove(), Example 2: remove() method on a list having duplicate elements. If a list contains duplicate elements, the remove() method only removes the first matching element​  In the test above we always call list.remove (1), but the element's index we want to remove is 0. Calling List.remove () shifts all elements after the removed one to smaller indices. In this scenario, it means that we delete all elements, except the first. When only the first remains, the index 1 will be illegal.

Remove an item from a list in Python (clear, pop, remove, del), Remove all items: clear() Remove an item by index and get its value: Remove multiple items that meet the condition: List comprehensions. This can be easily done for any HTML element (list, form, div etc.) to exclude it from being translated. You can achieve the same thing programatically in PHP by using the filter trp_no_translate_selectors. add_filter ( 'trp_no_translate_selectors', 'trpc_no_stranslate_selectors', 10, 2); function trpc_no_stranslate_selectors ($selectors_array, $language) { $selectors_array [] = '.do_not_translate_css_class'; $selectors_array [] = '#do_not_translate_css_id'; return $selectors_array; }

How to exclude specific values from a vector?, What I would like as an output is a new vector which has all the values from A excluding values from B. So C=[1;4;5;7;76;89] I am unable to overcome  In CSS, to exclude a particular class, we can use the pseudo-class :not selector also known as negation pseudo-class or not selector. This selector is used to set the style to every element that is not the specified by given selector. Since it is used to prevent a specific items from list of selected items.

How to remove an item from a python list, You can remove an item from a list in three ways: 1. using list object's remove() method. Here you need to specify an item to be removed. If there are multiple  To exclude a new element from being recorded simply click the "Create Rule" button shown here: Clicking the "Create Rule" button will prompt you with the "Add excluded element" modal where you can define the element to be excluded.

Comments
  • Is there a way to achieve this without modifying the original list. I am assuming you should just clone it every time you want to remove
  • @Joe Check out ColinD's answer. By the way, if you are really interested in functional programming (programming without destructive updates), check out Scalaz for Scala (which runs on the JVM) or Haskell (which doesn't) or F# (which runs on .NET).
  • Yes, that is a more general solution (to one possible interpretation of the question!), but it may be more general than what the questioner needed at this time.
  • yes but your answer will modify the existing list.. which might not be the requirement.
  • I just know the value, don't have any info on the index.
  • Ah, ok. Do you how if the only will be one, or can there be several?
  • That's an inefficient way of doing this since it starts iterating at the beginning of the list again each time it removes. Better would be to use the iterator and go through it once removing each match.