How to find the even numbers between a range using recursion?

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I am having trouble using recursion. I want to print and add the even numbers between a given range of two numbers. E.g: Range is between 3 and 9. So the output should be: 4+6+8=18.

printSeries(3,9);
Console.WriteLine("=" + sum);
int sum = 0;

            int printSeries(int number, int number2)
            {
                if (number < 1)
                {
                    number = 1;
                }
                if (number2 < number)
                {
                    if (number % 2 == 0)
                    {
                        return number;
                    }
                    return number + number % 2;
                }
                else
                {
                    int num = printSeries(number, number2 - 2);
                    Console.Write("+" + num);
                    sum += num;
                    return num += 2;
                }
            }

UPDATE: The output I'm getting is correct, but when both numbers are odd, there is an extra iteration. E.g: Range is 3,9: 4+6+8+10=28.

I don't your target exactly but I test your code and then change your code in second section

 private static void Main(string[] args)
    {
        // PrintSeries(7, 13);
        PrintSeries(2, 8);
        Console.WriteLine("=" + sum);
        System.Console.ReadKey();
    }

    private static int sum = 0;
    private static int PrintSeries(int number, int number2)
    {
        if (number < 1)
        {
            number = 1;
        }
        if (number2 <= number)
        {
          if (number % 2 == 0)
            {
                return number;
            }
            return number + number % 2;
        }
        else
        {

            int num = PrintSeries(number, number2 - 2);
            Console.Write("+" + num);
            sum += num;
            return num += 2;
        }
    }

How to find the even numbers between a range using recursion , I don't your target exactly but I test your code and then change your code in second section private static void Main(string[] args)  Declare recursive function to find sum of even number. First give a meaningful name to our function, say sumOfEvenOdd (). Next the function accepts two integer values from user i.e. start and end range. Hence, update function declaration to sumOfEvenOdd (int start, int end);.

 string str="";
 int sum=0;
 Void printSeries(int number, int number2)
        {

          for(int i=number;i<=number2;i++){
          if(i%2==0){
            sum += i;
            if(i!=number){
                str += "+"+i; 
            }else{
                str += i;
            }                
          }
          }
          Console.WriteLine(str + "=" + sum);
          printSeries(7,13);

       }

C exercises: Print even or odd numbers in a given range, Next: Write a program in C to multiply two matrix using recursion. What is the difficulty level of this exercise? Easy Medium Hard.   Here, We can use a C++ program operators to find odd or even number in a given range C++ program to check odd or even using recursion Program 1 This program allows the user to enter two input (number) for the lower limit and upper limit. and it finds whether odd and even numbers in the given range (between upper limit to lower limit)

You can use the following:

public int SumOfEvenNumbersInRange(int start, int end, IList<int> elements)
{
    int CreateSum(int current, int sum)
    {
        if (current > end)
        {
            return sum;
        }
        else
        {
            elements.Add(current);
            return sum + current + CreateSum(current + 2, sum);
        }
    }

    if (Math.Abs(start) % 2 == 0)
        return CreateSum(start, 0);

    return CreateSum(start + 1, 0);
}

This uses a local function to do the actual recursive work. You can then use it like this:

var elements = new List<int>();
var sum = SumOfEvenNumbersInRange(7, 13, elements);

if (elements.Count == 0)
{
    elements.Add(0);
}

Console.WriteLine($"{string.Join(" + ", elements)} = {sum}");

Using it like above would print the following:

8 + 10 + 12 = 30   // SumOfEvenNumbersInRange(7, 13, elements)
2 + 4 + 6 + 8 = 20 // SumOfEvenNumbersInRange(2, 8, elements)

C program to print even or odd numbers in given range using , How to print even numbers in given range using recursion in C. function in C programming to print all even or odd numbers between 1 to n. Starting from a seed value increment the current number by 2 to get next value. When any integer ends in 0,2,4,6,8 and it can be divided by two with the remainder of zero, it is called as an even number. Example of even numbers – 34,-64,78,788. When any integer ends in 0,1,3,5,7,9 and it cannot be divided without a remainder, it is called as an odd number. Example for odd numbers – 33,-69,75,785.

Program to print even or odd numbers in given range using recursion, Program to print even or odd numbers in given range using recursion Here, We can use C programming operators to find odd or even number in the given range. C program to find odd or even number using recursion. Recursion : Print even or odd numbers in a given range : ----- Input the range to print starting from 1 : 10 All even numbers from 1 to 10 are : 2 4 6 8 10 All odd numbers from 1 to 10 are : 1 3 5 7 9

C++ program to print even or odd in given range using recursion , to print odd or even number between given range using recursion. We can use a C++ program operators to find odd or even number in a  How to find sum of even numbers in a list using recursion? Ask Question Asked 4 years, 8 months ago. even_sum(range(10000)) – Peter Wood Oct 4 '15 at 19:12.

C# Program To Print even or odd numbers in a given range using , In this C# program, we will learn how to write a program to print Even or Odd numbers in a given range using Recursion. Calling SumOfEven Function where we are passing array a ,total number of elements as num-1 because we have to calculate from 0 to n-1 as array starts with 0 so if we give 7 elements in array then recursion will execute 7 times i.e from 0-6, and sum which is initialized to zero

Comments
  • This code is working on odd numbers perfectly but, now the problem is that when a number is already even, it is adding one number less like: 2,8 = 4+6+8=18. I want it to be 2+4+6+8=20.
  • Please check again
  • There is one extra iteration if both numbers are odd, now.
  • I'm sorry, I'm not behind the system.
  • Please can you check again later?
  • I asked "using recursion"
  • @GracefulFantasy: To what end? This is not a problem that requires recursion to solve. Are you asking about homework?