How can I keep adding on results obtained from each function call to the arrays?

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John and his family went on a holiday and went to 3 different restaurants. The bills were $124, $48 and $268.

To tip the waiter a fair amount, John created a simple tip calculator (as a function). He likes to tip 20% of the bill when the bill is less than $50, 15% when the bill is between $50 and $200, and 10% if the bill is more than $200.

In the end, John would like to have 2 arrays: 1) Containing all three tips (one for each bill) 2) Containing all three final paid amounts (bill + tip).

I have done the part where each function call with a different bill value returns the correct tip amount and total bill amount.

function billcalc(bill){

var tiplist=[];
    var finalAmount=[];
    var tip; var total;


if(bill<=50)
    {
        tip=0.2*bill;
        total=bill+tip;
        tiplist.push(tip);
        finalAmount.push(total);
        console.log(tiplist);
        console.log(finalAmount);

    }


else if(bill>=50 && bill<=200){
        tip=0.15*bill;
        total=bill+tip;
        tiplist.push(tip);
        finalAmount.push(total);
        console.log(tiplist);
        console.log(finalAmount);
    }


else{
        tip=0.10*bill;
        total=bill+tip;
        tiplist.push(tip);
        finalAmount.push(total);
        console.log(tiplist);
        console.log(finalAmount);
    }
}

billcalc(124);
billcalc(48);
billcalc(268);

I want to get the two arrays to display all the respective tip and total value from each function call.

You could take a function for getting the factor for getting the tip and another function for calculating the tip.

As result add the values of bills and tips for getting all total values.

function getFactor(v) {
    if (v < 50) return 0.2;
    if (v < 200) return 0.15;
    return 0.1;
}

function getTip(amount) {
    return +(amount * getFactor(amount)).toFixed(2); // apply some rounding
}

var bills = [124, 48, 268],
    tips = bills.map(getTip),
    totals = [bills, tips].reduce((a, b) => a.map((v, i) => v + b[i]));

console.log(tips);
console.log(totals);
.as-console-wrapper { max-height: 100% !important; top: 0; }

Array methods, We already know methods that add and remove items from the beginning or the end: That's often used to obtain a copy for further transformations that should The function is called for elements of the array, one after another: let results = arr . filter ( function ( item , index , array ) { // if true item is pushed  first I must ask you why use cout<<"Enter"<<6<<"test scores:"<<endl; insted of cout<<"Enter 6 test scores:"<<endl;. you declered sum within a function. ic c++ it creates the variable in the function and it is destroyes at end of the function. do you think the sum you declared within the main function is changed through CalcAvg function. to do this you should rerurn a pointer to sum in the

Reduce is a very handy array method specifically for accumulating results when iterating over a collection.

Reduce takes a function as an argument, the function generally uses two arguments: the accumulator and the current element. The second argument given to reduce is the initial accumulator. I've defined the two result arrays which allows me to push to them for every iteration.

var result = [124, 48, 268].reduce(function(acc, bill) {
    var tip = 0;
    if(bill < 50){ tip = bill * 0.2 }
    if(50 <= bill && bill < 200){ tip = bill * 0.15 }
    if(200 < bill){ tip = bill * 0.1 }
    acc.tips.push(tip);
    acc.totals.push(bill + tip);
    return acc;
}, {tips: [], totals: []});

Which gives:

  {
  "tips": [
    18.599999999999998,
    9.600000000000001,
    26.8
  ],
  "totals": [
    142.6,
    57.6,
    294.8
  ]
}

Implementation and Application of Functional Languages: 20th , To the programmer, an array appears as an abstract data type, providing means for obtaining array As as data type invariant, p = Πr i=1si must hold for all arrays. returned once more into the calling context through yet another descriptor. result of add, its elements are copied again into the function result's descriptor. One of the most common tasks involving arrays is to iterate (or, to loop) through each element of an array by using a DO group and then performing an operation on each element. The basic example in the previous section uses the following DO

Turns out I merely had to put the two arrays outside the billCalc function and Voila!

Thanks for all the solutions given above.

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