How to execute a function x% of the times it is to be executed?

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Use case: Live images are provided in real time and are to be viewed on the screen. To lower the CPU load, the user should be able to discard images and only show, say 10%, or 50%, of the images.

If the user choose 50%, then every other image should be shown (not 50 images in a row, and then discard 50, as that would be 50% too..)

Current code:

showImage();

shows the image 100% of the times.

If the user supply an integer, like 1,2,3 .., meaning every one, every second, every third and so on, something familiar like this can be used:

if(counter % everyWhatImage)
{
     showImage();
}
counter++;

, however, that code don't allow to show less than 50% (the '2') of the images, and so the question is, how to do that?

As this is a live streaming application, it needs to be fast.

In addition, the above code is executed in a callback function, so there is no knowledge of when it is to be executed.


The Commodore 64 in Action: Sound, Graphics & Filing, fre fr Function Format: fre(x) where x is a number. Often, a section of a program is evaluated several times during a single execution RUN. On such occasions  The code inside a function is executed when the function is invoked. It is common to use the term "call a function" instead of "invoke a function". It is also common to say "call upon a function", "start a function", or "execute a function". In this tutorial, we will use invoke, because a JavaScript function can be invoked without being called.


Save up the given proportion in a "running balance". Every time it reaches at least 1.00, "cash in" the savings for an image.

Choosing 27% for an example ...

show_count = 0.00
ratio = 0.27
while (we have more images to show) {
    show_count += ratio
    if (show_count >= 1.00) {
        show_image()
        show_count -= 1.00
}

Run function X times, Hi! I know this is a stupid question, but how to you run a function X times. instead of: test(); test(); test(); test(); test(); delay(1000); test2(); test2(); While in the middle of one function, the program might have to execute the statements in another function. But while executing that new function, the program might have to execute yet another function!


The other answers to this question all appear to implement a counter, so I thought I would suggest a probabilistic approach. You could generate a random number between zero and one each time your function is called:

    random = ((double) rand() / (RAND_MAX))

Then, if the random number is below the prescribed percentage of images to be shown, show the image. Otherwise, discard it.

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