Regex match adjacent digits after second occurrence of character

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Stuck with the following issue:

I have a string 'ABC.123.456XX' and I want to use regex to extract the 3 numeric characters that come after the second period. Really struggling with this and would appreciate any new insights, this is the closest I got but its not really close to what I want:

'.*\.(.*?\.\d{3})'

I appreciate any help in advance - thanks.


This expression might also work just OK:

[^\r\n.]+\.[^\r\n.]+\.([0-9]{3})
Test
import re

regex = r'[^\r\n.]+\.[^\r\n.]+\.([0-9]{3})'
string = '''
ABC.123.456XX
ABCOUOU.123123123.000871XX
ABCanything_else.123123123.111871XX
'''

print(re.findall(regex, string))
Output
['456', '000', '111']

If you wish to simplify/modify/explore the expression, it's been explained on the top right panel of regex101.com. If you'd like, you can also watch in this link, how it would match against some sample inputs.


Unix Power Tools, A calculator program must recognize, for instance, that 2 is a numeric constant and that That is, a pattern matches adjacent characters. Look at the following example of a regular expression: ABE Each literal character is a regular Expressions (Pattern Matching) 635 This is the Title of the Book, eMatter Edition second. Hi all, I am trying to match everything after the second to last dash in a file which contains strings with hyphens or dashes. In each line is a string with a series of letters, numbers, and dashes. I would just like to extract everything after the second to last dash. See examples below: ab237234


Visual Basic .NET Power Coding, pattern string; split strings; and replace patterns found in an input string. This pattern will match contiguous digits. The second regular expression stores the first one or two digits in 'month-, the second one or two expression many times, explicitly create an instance of the Regex class, Emitting IL Code at Runtime 117. So the first step passes: Your value begins with one or more non "_" characters. But second step fails: The characters ally or self or enemy are not found in the value starting from the second character to the end of the string. Ally is in the value, but the A is already matched in the first step where 1 or more must be matched.


Dot, not-Dot twice then the 3 digits follow in capture group 1

[^.]*(?:\.[^.]*){2}(\d{3})

https://regex101.com/r/qWpfHx/1

Expanded

 [^.]* 
 (?: \. [^.]* ){2}
 ( \d{3} )                     # (1)

Everything you need to know about Regular Expressions, The following is a regular expression pattern that represents our set of strings Sometimes you have to match characters that are best expressed by as A1-A8 for the first column, B1-B8 for the second column and so on until Any literal or character group matches the occurrence of exactly one character. Red Hat Enterprise Linux Deployment Guide 5. Ruby Regex: match up to the first character occurrence I have a file with lines that vary in their format, but the basic idea is like this: - A block of text #tag @due(2014-04-20) @done(2014-04-22) For example: - Email John Doe #email @due(2014-04-20) @done(2014-04-22) The issue is the #tag and the @due.


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Back to Basics: Regular Expressions, Our regular expression matches the number 2 in our string. In Ruby this is done by appending characters after the regular expression pattern is defined. We need to specify a pattern that will say find any group of contiguous digits. it's the second instance of the string “Back to Basics” we've matched. The FIND function will return the position of the first occurrence of the hash character in within_text string returned by the SUBSTITUTE function. Then add 1 to get the starting position after the second occurrence of the comma character in text. And it returns 11. It is fed into the MID function as its start_num argument.