Find the number of employees in each department - SQL Oracle

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I have two tables Emp and Dept and I am trying to display how many people work in each department along with their department name, but I can't get it to work. I have tried this select count(ename) as count from emp group by deptno; but the output I am getting is this :

 COUNT
----------
     6
     5
     3

But I also want to show the names for each of those departments. Here are my tables :

Empt:

CREATE TABLE EMP
       (EMPNO NUMBER(4) NOT NULL,
        ENAME VARCHAR2(10),
        JOB VARCHAR2(9),
        MGR NUMBER(4),
        HIREDATE DATE,
        SAL NUMBER(7, 2),
        COMM NUMBER(7, 2),
        DEPTNO NUMBER(2));

INSERT INTO EMP VALUES
        (7369, 'SMITH',  'CLERK',     7902,
        TO_DATE('17-DEC-1980', 'DD-MON-YYYY'),  800, NULL, 20);
INSERT INTO EMP VALUES
        (7499, 'ALLEN',  'SALESMAN',  7698,
        TO_DATE('20-FEB-1981', 'DD-MON-YYYY'), 1600,  300, 30);
INSERT INTO EMP VALUES
        (7521, 'WARD',   'SALESMAN',  7698,
        TO_DATE('22-FEB-1981', 'DD-MON-YYYY'), 1250,  500, 30);
INSERT INTO EMP VALUES
        (7566, 'JONES',  'MANAGER',   7839,
        TO_DATE('2-APR-1981', 'DD-MON-YYYY'),  2975, NULL, 20);
INSERT INTO EMP VALUES
        (7654, 'MARTIN', 'SALESMAN',  7698,
        TO_DATE('28-SEP-1981', 'DD-MON-YYYY'), 1250, 1400, 30);
INSERT INTO EMP VALUES
        (7698, 'BLAKE',  'MANAGER',   7839,
        TO_DATE('1-MAY-1981', 'DD-MON-YYYY'),  2850, NULL, 30);
INSERT INTO EMP VALUES
        (7782, 'CLARK',  'MANAGER',   7839,
        TO_DATE('9-JUN-1981', 'DD-MON-YYYY'),  2450, NULL, 10);
INSERT INTO EMP VALUES
        (7788, 'SCOTT',  'ANALYST',   7566,
        TO_DATE('09-DEC-1982', 'DD-MON-YYYY'), 3000, NULL, 20);
INSERT INTO EMP VALUES
        (7839, 'KING',   'PRESIDENT', NULL,
        TO_DATE('17-NOV-1981', 'DD-MON-YYYY'), 5000, NULL, 10);
INSERT INTO EMP VALUES
        (7844, 'TURNER', 'SALESMAN',  7698,
        TO_DATE('8-SEP-1981', 'DD-MON-YYYY'),  1500,    0, 30);
INSERT INTO EMP VALUES
        (7876, 'ADAMS',  'CLERK',     7788,
        TO_DATE('12-JAN-1983', 'DD-MON-YYYY'), 1100, NULL, 20);
INSERT INTO EMP VALUES
        (7900, 'JAMES',  'CLERK',     7698,
        TO_DATE('3-DEC-1981', 'DD-MON-YYYY'),   950, NULL, 30);
INSERT INTO EMP VALUES
        (7902, 'FORD',   'ANALYST',   7566,
        TO_DATE('3-DEC-1981', 'DD-MON-YYYY'),  3000, NULL, 20);
INSERT INTO EMP VALUES
        (7934, 'MILLER', 'CLERK',     7782,
        TO_DATE('23-JAN-1982', 'DD-MON-YYYY'), 1300, NULL, 10);

Dept:

CREATE TABLE DEPT
       (DEPTNO NUMBER(2),
        DNAME VARCHAR2(14),
        LOC VARCHAR2(13) );

INSERT INTO DEPT VALUES (10, 'ACCOUNTING', 'NEW YORK');
INSERT INTO DEPT VALUES (20, 'RESEARCH',   'DALLAS');
INSERT INTO DEPT VALUES (30, 'SALES',      'CHICAGO');
INSERT INTO DEPT VALUES (40, 'OPERATIONS', 'BOSTON');

Please try:

select count(*) as count,dept.DNAME 
from emp 
inner join dept on emp.DEPTNO = dept.DEPTNO 
group by dept.DNAME

Find the number of employees in each department, SQL Aggregate Function Exercise, Practice and Solution: Write a query in SQL to find the number of employees in each department along with  A request to list "Number of employees in each department" or "Display how many people work in each department" is the same as "For each department, list the number of employees", this must include departments with no employees. In the sample database, Operations has 0 employees. So a LEFT OUTER JOIN should be used.


A request to list "Number of employees in each department" or "Display how many people work in each department" is the same as "For each department, list the number of employees", this must include departments with no employees. In the sample database, Operations has 0 employees. So a LEFT OUTER JOIN should be used.

SELECT dept.name, COUNT(emp.empno) AS count
FROM dept
LEFT OUTER JOIN emp ON emp.deptno = dept.deptno
GROUP BY dept.name;

SQL Aggregate Function: Find the number of employees in each , How do I count the number of entries in SQL? ORACLE SQL. Find the total number of employees and the total number of dependents for each department (the number of dependents for a department is the sum of the number of dependents for each employee working for that department). Return the result as department name, total number of employees, and total number of dependents-- drop tables. SCHEMA BELOW


select count(e.empno), d.deptno, d.dname 
from emp e, dep d
where e.DEPTNO = d.DEPTNO 
group by d.deptno, d.dname;

SQL COUNT function, each row separately. This includes rows that contain null values. Make a relationship between both tables and insert some data into the tables. Write a query to find out the highest number of employees in the department. Example 1 SELECT DEPARTMENTNAME,COUNT (*) AS EMPLOYEECOUNT


Try the query below:

select count(*),d.dname from emp e , dept d where d.deptno = e.deptno
group by d.dname

COUNT (Transact-SQL), How do you calculate total salary for each employee table? select count(employee_ID) as "num of employees", department_name, employee_name from employees e, departments d where e.dept_id = d.dept_id group by department_name, employee_name Without adding the emp name I get the correct solution, but with the employee I get 1 in the num of employees oracle oracle-11g


SELECT d.DEPTNO
    , d.dname
    , COUNT(e.ename) AS count
FROM   emp e
      INNER JOIN dept d ON e.DEPTNO = d.deptno
GROUP BY d.deptno
      , d.dname;

Solved: PS7 1. Create A SQL Query That Will Use The Count , How do I count the number of rows returned by a query in SQL? Write an SQL query to print the name of employees having the highest salary in each department. Could you please help me to get the highest salary for each department. If multiple employees having the highest salary in the same department then I need the get oldest employee details(who joined first in the company).


Employees Per Department Twit, Answer to PS7 1. Create a SQL query that will use the count function to return the number of employees in each department in the e count(*),deptno from emp group by deptno; 2.SELECT DECODE(deptno, 1, 'Oracle', view the full answer. In SQL Server / MS Access: ===== select top 1 department_name from EMPLOYEES join DEPARTMENTS on EMPLOYEES.department_id=DEPARTMENTS.department_id group by department_name order by count(*) desc; In My SQL: ===== select department_name from EMPLOYEES join DEPARTMENTS on EMPLOYEES.department_id=DEPARTMENTS.department_id group by department_name


Display department name,the number of employees and their names, Twitter Interview Online Test SQL A Sort your result in descending order of employees per department; if two or more departments have the same number of select d.name, count(e.id) over (partition by d.dept_id) as total_employees ANS select * from dept; 2 Display the details of all employees. ANS select * from emp; 3 Display the name and job for all employees. ANS select ename, job from emp; 4 Display name and salary for all employees. ANS select ename, sal from emp; 5 Display employee number and total salary for each employee. ANS select empno, sal+comm


cont total employees in department and all sect, You need to fetch the number of employees in a sub-query and then use this: join ( select count(dept_id) as total, dept_id from employees group by But maybe there are ways using newer SQL constructs with better performance. Oracle has a smart optimizer so there is no reason to expect that he